Problem 24
Question
If the mean of a set of observations \(x_{1}, x_{2}, x_{3}, \ldots, x_{n}\) is \(\bar{x}\), then mean of observations \(x_{i}+3 i \forall i=1,2,3, \ldots n\) equals (A) \(\bar{x}+3(n+1)\) (B) \(\bar{x}+\frac{3(n+1)}{2}\) (C) \(\bar{x}+\frac{n+1}{2 n}\) (D) None of these
Step-by-Step Solution
Verified Answer
(B) \(\bar{x} + \frac{3(n+1)}{2}\)
1Step 1: Understanding the Problem
We start with a set of observations \(x_1, x_2, x_3, \ldots, x_n\) with a given mean \(\bar{x}\). We need to find the mean of a new set of observations formed by adding \(3i\) to each \(x_i\) (i.e., \(x_i + 3i\) for each observation).
2Step 2: Recall the Formula for Mean
The mean of a set of observations \(x_1, x_2, x_3, \ldots, x_n\) is given by \(\bar{x} = \frac{x_1 + x_2 + x_3 + \ldots + x_n}{n}\). This states that the mean is the total sum of the observations divided by the number of observations \(n\).
3Step 3: Form the Sum of New Observations
For the new observations \(x_1 + 3 \cdot 1, x_2 + 3 \cdot 2, x_3 + 3 \cdot 3, \ldots, x_n + 3n\), their sum is: \((x_1 + x_2 + x_3 + \ldots + x_n) + (3 \cdot 1 + 3 \cdot 2 + 3 \cdot 3 + \ldots + 3n)\).
4Step 4: Calculate the Additional Sum
The additional sum \(3 \cdot 1 + 3 \cdot 2 + 3 \cdot 3 + \ldots + 3n\) can be factored as \(3(1 + 2 + 3 + \ldots + n)\). The sum \(1 + 2 + 3 + \ldots + n\) is a known arithmetic series given by \(\frac{n(n+1)}{2}\).
5Step 5: Calculate the New Mean
Substituting for the sum, the new total sum is \((x_1 + x_2 + x_3 + \ldots + x_n + 3 \cdot \frac{n(n+1)}{2})\). The mean of the new observations then is \(\frac{\text{Sum of New Observations}}{n} = \frac{(x_1 + x_2 + x_3 + \ldots + x_n) + \frac{3n(n+1)}{2}}{n}\).
6Step 6: Simplify the Expression
Simplifying the expression, the new mean becomes \(\frac{x_1 + x_2 + \ldots + x_n}{n} + \frac{3n(n+1)}{2n}\). Recognizing that the first term is \(\bar{x}\), the new mean becomes \(\bar{x} + \frac{3(n+1)}{2}\).
7Step 7: Choose the Correct Option
Comparing our result \(\bar{x} + \frac{3(n+1)}{2}\) with the given options, the correct answer is option (B).
Key Concepts
Arithmetic SeriesArithmetic MeanMathematical Problem Solving
Arithmetic Series
An arithmetic series is a sequence of numbers in which each term after the first is obtained by adding a constant difference to the previous term. This constant difference is known as the 'common difference.' A series can be represented as:
- The first term: \(a\)
- The common difference: \(d\)
Arithmetic Mean
The arithmetic mean is one of the most common ways to represent a set of observations through a single value that summarizes the entire dataset. Technically, it is the sum of the values in a dataset divided by the number of values: \[\bar{x} = \frac{x_1 + x_2 + \ldots + x_n}{n}\] This formula calculates what is often referred to as the average. It provides a balance point for the data, offering a simple snapshot of the overall dataset.
To understand this in practice, consider a set of values like 2, 4, 6. The arithmetic mean would be \[\frac{2+4+6}{3} = 4\] In problems like the one in our exercise, the aim is to analyze how adding consistent changes, like \(3i\) to each observation, affects this mean.
To understand this in practice, consider a set of values like 2, 4, 6. The arithmetic mean would be \[\frac{2+4+6}{3} = 4\] In problems like the one in our exercise, the aim is to analyze how adding consistent changes, like \(3i\) to each observation, affects this mean.
Mathematical Problem Solving
Mathematical problem-solving is a fundamental skill that helps in understanding and interacting with complex problems systematically. Here is a typical approach to solving mathematical problems:
- Understand the Problem: Identify what's given and what's needed. In the exercise, we start with a set of observations and aim to find a modified mean.
- Formulate a Plan: Recall relevant formulas and principles—including the concepts of arithmetic series and mean.
- Carry Out the Plan: Execute your strategy—calculate the additional sum with added modifications.
- Review and Check: Ensure your solution is logical and matches expectations—in this case, selecting the correct mean transformation option.
Other exercises in this chapter
Problem 22
The A.M. of a set of 50 numbers is 38 . If two numbers of the set, namely 55 and 45 are discarded, the A.M. of the remaining set of numbers is (A) \(38.5\) (B)
View solution Problem 23
The mean weight per student in a group of seven students is \(55 \mathrm{~kg}\) If the individual weights of 6 students are \(52,58,55,53,56\) and 54 ; then wei
View solution Problem 25
The weighted mean of the square of 1st \(n\) natural numbers whose weights are corresponding numbers, equals (A) \(\frac{(n+1)(2 n+1)}{2}\) (B) \(\frac{n(n+1)}{
View solution Problem 26
If the variate of a distribution takes the values 1,2 , \(3, \ldots n\) with frequencies \(n, n-1, n-2, \ldots .3,2,1\), then mean value of the distribution is
View solution