Problem 24
Question
If the mean of a set of observations \(x_{1}, x_{2}, x_{3}, \ldots, x_{n}\) is \(\bar{x}\), then mean of observations \(x_{i}+3 i \forall i=1,2,3, \ldots n\) equals (A) \(\bar{x}+3(n+1)\) (B) \(\bar{x}+\frac{3(n+1)}{2}\) (C) \(\bar{x}+\frac{n+1}{2 n}\) (D) None of these
Step-by-Step Solution
Verified Answer
The correct answer is (B) \(\bar{x} + \frac{3(n+1)}{2}\).
1Step 1: Understanding the Problem
We are given that the mean of a set of observations \(x_1, x_2, x_3, \ldots, x_n\) is \(\bar{x}\). We need to find the mean of the modified observations \(x_i + 3i\) for all \(i = 1, 2, 3, \ldots, n\).
2Step 2: Expressing the Mean of Original Observations
The mean \(\bar{x}\) of the original set of observations can be expressed as \(\bar{x} = \frac{x_1 + x_2 + x_3 + \ldots + x_n}{n}\).
3Step 3: Calculate the Sum of Modified Observations
For each observation, we add \(3i\), so the sum of modified observations becomes \((x_1 + 3 \, (1)) + (x_2 + 3 \, (2)) + ... + (x_n + 3 \, (n))\). This simplifies to \((x_1 + x_2 + ... + x_n) + 3(1 + 2 + ... + n)\).
4Step 4: Summing the Series
The sum of the series \(1 + 2 + ... + n\) can be calculated using the formula for the sum of the first \(n\) natural numbers: \(\frac{n(n+1)}{2}\).
5Step 5: Combine and Simplify
The sum of the modified observations is \((x_1 + x_2 + ... + x_n) + 3 \cdot \frac{n(n+1)}{2}\). This simplifies to \(\sum_{i=1}^{n} x_i + \frac{3n(n+1)}{2}\).
6Step 6: Find the New Mean
Divide this new sum by \(n\) to get the new mean: \[\text{New Mean} = \frac{\sum_{i=1}^{n} x_i + \frac{3n(n+1)}{2}}{n} = \bar{x} + \frac{3(n+1)}{2}\].
7Step 7: Identify the Correct Answer
The calculated new mean, \(\bar{x} + \frac{3(n+1)}{2}\), matches option (B).
Key Concepts
Summation of natural numbersArithmetic operations in statisticsCalculation of modified means
Summation of natural numbers
Summation of natural numbers is a fundamental concept in mathematics. To find the sum of the first \( n \) natural numbers, we use a handy formula:
For example, if \( n = 5 \), the sum is: 1 + 2 + 3 + 4 + 5.
Using the formula, you get:
- \( rac{n(n+1)}{2} \)
For example, if \( n = 5 \), the sum is: 1 + 2 + 3 + 4 + 5.
Using the formula, you get:
- \( rac{5(5+1)}{2} = 15 \)
Arithmetic operations in statistics
Arithmetic operations are essential in calculating various statistical measures. The mean, or average, is a primary metric used for summarizing data. To calculate the mean of a set of observations \( x_1, x_2, ..., x_n \), you perform the following steps:
- Sum the observations: \( ext{Sum} = x_1 + x_2 + ... + x_n \)
- Divide by the number of observations: \( ar{x} = \frac{ ext{Sum}}{n} \)
Calculation of modified means
The calculation of modified means involves adjusting the original set of observations by a specified change. Suppose each observation \( x_i \) is modified by adding \( 3i \) — where \( i \) represents the position or index in the data set. To find the new mean, follow these steps:
- Calculate the original mean: \( \bar{x} = \frac{x_1 + x_2 + ... + x_n}{n} \)
- Add \( 3i \) to each observation and find the new sum: \( ext{New Sum} = x_1 + 3(1) + x_2 + 3(2) + ... + x_n + 3(n) \)
- Apply the summation of natural numbers: \( rac{n(n+1)}{2} \)
- Combine the sums: \( ext{New Sum} = \sum_{i=1}^{n} x_i + 3 \cdot \frac{n(n+1)}{2} \)
- Calculate the new mean: \( ext{New Mean} = \frac{ ext{New Sum}}{n} = \bar{x} + \frac{3(n+1)}{2} \)
Other exercises in this chapter
Problem 22
The A.M. of a set of 50 numbers is 38 . If two numbers of the set, namely 55 and 45 are discarded, the A.M. of the remaining set of numbers is (A) \(38.5\) (B)
View solution Problem 23
The mean weight per student in a group of seven students is \(55 \mathrm{~kg}\) If the individual weights of 6 students are \(52,58,55,53,56\) and 54 ; then wei
View solution Problem 25
The weighted mean of the square of lst \(n\) natural numbers whose weights are corresponding numbers, equals (A) \(\frac{(n+1)(2 n+1)}{2}\) (B) \(\frac{n(n+1)}{
View solution Problem 26
If the variate of a distribution takes the values 1,2 , \(3, \ldots n\) with frequencies \(n, n-1, n-2, \ldots 3,2,1\), then mean value of the distribution is (
View solution