Problem 24
Question
For the following problems, solve the equations, if possible. $$ y(3 y-4)=0 $$
Step-by-Step Solution
Verified Answer
Answer: The values of y that satisfy the given equation are y = 0 and y = \frac{4}{3}.
1Step 1: Identify the factors in the equation
The given equation has two factors: y and (3y - 4).
2Step 2: Apply Zero-product Property
According to the zero-product property, either y = 0, or (3y - 4) = 0, or both. We will now solve for y in each case.
3Step 3: Solve y = 0
In this case, the solution is already provided: y = 0.
4Step 4: Solve (3y - 4) = 0 for y
To solve for y, we will first isolate y by adding 4 to both sides of the equation:
3y - 4 + 4 = 0 + 4
This simplifies to:
3y = 4
Now, divide both sides by 3:
y = \frac{4}{3}
5Step 5: State the solution set
The solution set of the given equation contains the values of y that satisfy the zero-product property, which are y = 0 and y = \frac{4}{3}.
Key Concepts
Zero-product PropertyEquation SolvingFactorizationSolution Set
Zero-product Property
The zero-product property is a fundamental principle in algebra that helps us solve equations involving products of terms. This property states that if the product of two or more factors equals zero, then at least one of these factors must be zero.
This concept can be visualized easily:
This concept can be visualized easily:
- If \(a \times b = 0\), then either \(a = 0\), \(b = 0\), or both.
Equation Solving
Equation solving involves finding the values of variables that make an algebraic equation true. When solving equations like \(y(3y-4) = 0\), we utilize properties like zero-product property to simplify the process.
The basic steps for solving equations include:
The basic steps for solving equations include:
- Identifying the factors involved in the equation.
- Applying the appropriate mathematical property, such as the zero-product property.
- Solving each factor by isolating the variable.
Factorization
Factorization is the process of breaking down an expression into a product of its simpler factors. This method is especially useful when dealing with polynomial equations, where rewriting the equation as a product of factors can significantly simplify solving it.
In our exercise, the equation \(y(3y-4) = 0\) is already presented in its factored form.
To factor an equation means to express it as a product of terms, such as:
In our exercise, the equation \(y(3y-4) = 0\) is already presented in its factored form.
To factor an equation means to express it as a product of terms, such as:
- From something like \(x^2 - 4x\) to \(x(x-4)\).
- To confirm factorization, you can expand the factors back out to ensure they reconstruct the original equation.
Solution Set
The solution set of an equation is the collection of all possible values of the variable that satisfy the equation. In algebraic terms, these solutions are the numbers that make the mathematical statement true when substituted back into the original equation.
For the given equation \(y(3y-4) = 0\), we determine the solution set by solving the factors:
For the given equation \(y(3y-4) = 0\), we determine the solution set by solving the factors:
- Setting \(y = 0\) directly results in one part of the solution.
- Solving \(3y-4=0\) yields \(y=\frac{4}{3}\) as another solution.
Other exercises in this chapter
Problem 24
For the following problems, solve the equations by completing the square. $$ -x^{2}-14 x=13 $$
View solution Problem 24
For the following problems, solve each of the quadratic equations using the method of extraction of roots. $$ b^{2}=6 $$
View solution Problem 24
For the following problems, write the values of \(a, b,\) and \(c\) in quadratic equations. $$ 5 x-7=-3 x^{2} $$
View solution Problem 25
For the following problems, solve the equations. $$ m^{2}-81=0 $$
View solution