Problem 24
Question
For the following exercises, simplify each expression. \(12 \sqrt{3}-4 \sqrt{75}\)
Step-by-Step Solution
Verified Answer
The simplified expression is \(-8\sqrt{3}\).
1Step 1: Identify and Simplify Square Roots
First, we need to simplify each square root in the expression. The term \(\sqrt{75}\) can be simplified as: \(\sqrt{75} = \sqrt{25 \times 3} = \sqrt{25} \times \sqrt{3} = 5\sqrt{3}\). Therefore, the expression now becomes: \(12\sqrt{3} - 4(5\sqrt{3})\).
2Step 2: Apply the Distributive Property
Next, apply the distributive property to the term \(-4(5\sqrt{3})\) to get \(-20\sqrt{3}\). Now, the expression is \(12\sqrt{3} - 20\sqrt{3}\).
3Step 3: Combine Like Terms
Since both terms in the expression have the common part \(\sqrt{3}\), we can combine them. By subtracting the coefficients, we have: \(12 - 20 = -8\). Thus, the expression simplifies to: \(-8\sqrt{3}\).
Key Concepts
Square RootsDistributive PropertyCombining Like Terms
Square Roots
Square roots are used to find a number which, when multiplied by itself, gives the original number. For example, the square root of 9 is 3, because 3 multiplied by 3 equals 9. In simplifying expressions, it's common to encounter square roots like \( \sqrt{75} \). To simplify, we can break down \( \sqrt{75} \) into its prime factors:
- First, note that 75 can be factored into 25 and 3.
- Since 25 is a perfect square, \( \sqrt{25} = 5 \), hence \( \sqrt{75} = \sqrt{25 \times 3} = 5\sqrt{3} \).
Distributive Property
The distributive property is a fundamental principle that allows us to multiply a single term by each term in a parenthesis, effectively "distributing" the multiplication across terms. In the expression \(-4(5\sqrt{3})\), the distributive property helps us break it down into easier parts. Here's how it works:
- We distribute the \(-4\) across \(5\sqrt{3}\).
- This gives us \(-4 \times 5 \times \sqrt{3} = -20\sqrt{3}\).
Combining Like Terms
Combining like terms is a method used to simplify expressions, bringing together terms that have identical variable parts. To do this, you can simply add or subtract their coefficients. In the expression we have, \(12\sqrt{3} - 20\sqrt{3}\), both terms contain the \(\sqrt{3}\) component. Here's how we proceed:
- Identify the like terms which, in this case, are terms both including \(\sqrt{3}\).
- Since the terms are similar, subtract their coefficients: \(12 - 20 = -8\).
Other exercises in this chapter
Problem 24
For the following exercises, factor the polynomial. \(25 y^{2}-196\)
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For the following exercises, expand the binomial \((4 x+5)^{2}\)
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For the following exercises, convert each number in scientific notation to standard notation. \(9.8 \times 10^{-9}\)
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For the following exercises, simplify the given expression. \((15-7) \times(3-7)\)
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