Problem 24
Question
For Problems \(21-34\), use the factor theorem to help answer some questions about factors. $$ \text { Is } x-5 \text { a factor of } 8 x^{2}-47 x+32 ? $$
Step-by-Step Solution
Verified Answer
No, \( x-5 \) is not a factor because \( f(5) \neq 0 \).
1Step 1: Understanding the Factor Theorem
The factor theorem states that a polynomial \( f(x) \) has a factor \( x-c \) if and only if \( f(c) = 0 \). This means to determine if \( x-5 \) is a factor, we need to check if substituting 5 into the polynomial results in zero.
2Step 2: Substituting to Find \( f(5) \)
We have the polynomial \( f(x) = 8x^2 - 47x + 32 \). Substitute \( x = 5 \) into this polynomial: \[f(5) = 8(5)^2 - 47(5) + 32.\]
3Step 3: Calculating \( f(5) \)
Calculate \( f(5) = 8(25) - 47(5) + 32 \). First, find \( 8(25) = 200 \) and \( 47(5) = 235 \). Now substitute these values back into the equation: \[ f(5) = 200 - 235 + 32 \].
4Step 4: Simplifying to See If It Equals Zero
Simplify the expression: \[ f(5) = 200 - 235 + 32 = -35 + 32 = -3 \]. Since \( f(5) = -3 \) and not zero, \( x-5 \) is not a factor of the polynomial.
Key Concepts
Polynomial FactorizationAlgebraic ExpressionsRoots of Polynomials
Polynomial Factorization
Polynomial factorization is a key process in algebra that involves expressing a polynomial as the product of its factors. Think of it like breaking down a large number into its smaller prime components or parts that multiply to make the original number. This process allows us to simplify polynomials, solve polynomial equations more easily, and see insights into their structure.
To factor polynomials, we often use methods such as:
To factor polynomials, we often use methods such as:
- Finding common factors, where you look for terms that can be factored out of the polynomial.
- Using special formulas, like differences of squares or perfect square trinomials.
- Applying the factor theorem, which tells us that if a polynomial evaluated at a certain value equals zero, then that value is a root, and the related factor is part of the polynomial's factorization.
Algebraic Expressions
Algebraic expressions are combinations of variables, numbers, and operations (like addition and multiplication) that form an equation or relationship. When dealing with algebraic expressions, it’s important to simplify them, just like cleaning up and arranging your room for better usability.
In the context of the Factor Theorem, an algebraic expression like a polynomial can be tested for factors by substituting specific values to see if they yield zero, which helps determine if the expression can be factored further.
Algebraic expressions can be manipulated in various ways:
In the context of the Factor Theorem, an algebraic expression like a polynomial can be tested for factors by substituting specific values to see if they yield zero, which helps determine if the expression can be factored further.
Algebraic expressions can be manipulated in various ways:
- Combining like terms by adding or subtracting coefficients of the same variable power.
- Distributive property, where you distribute a multiplied value across terms inside parentheses.
- Substitution, which is entering specific numbers for variables to evaluate the expression.
Roots of Polynomials
Roots of polynomials are the values of the variable that make the polynomial equal zero. In simpler terms, they are the solutions to the polynomial equation. Finding these roots is a fundamental task in algebra as it gives insights into the behavior and solutions of polynomial functions.
For any given polynomial, its roots can be found using the factor theorem. If substituting a value into the polynomial makes it zero, then that value is a root, and the corresponding factor is \(x - \ ext{value}\). This process not only confirms roots but also helps in factorizing the polynomial completely.
For any given polynomial, its roots can be found using the factor theorem. If substituting a value into the polynomial makes it zero, then that value is a root, and the corresponding factor is \(x - \ ext{value}\). This process not only confirms roots but also helps in factorizing the polynomial completely.
- For example, in our exercise, checking if \(x-5\) is a factor involves calculating whether substituting 5 results in zero.
- Roots can be real or complex numbers depending on the polynomial’s coefficients.
- Each root corresponds to at least one factor of the polynomial.
Other exercises in this chapter
Problem 24
For Problems \(23-34\), graph each polynomial function by first factoring the given polynomial. You may need to use some factoring techniques from Chapter 3 as
View solution Problem 24
For Problems \(21-26\), verify that the equations do not have any rational number solutions. $$ 2 x^{4}-3 x^{3}+6 x^{2}-24 x+5=0 $$
View solution Problem 24
Use synthetic division to determine the quotient and remainder for each problem. $$ \left(x^{4}-3 x^{3}-6 x^{2}+11 x-12\right) \div(x-4) $$
View solution Problem 25
First check for symmetry and identify the asymptotes for the graphs of the following rational functions. Then use your graphing utility to graph each function.
View solution