Problem 24
Question
For each plane curve, (a) graph the curve, and (b) find a rectangular equation for the curve. $$x=t^{2}+2, y=t^{2}-4 ; \text { for } t \text { in }(-\infty, \infty)$$
Step-by-Step Solution
Verified Answer
The rectangular equation is \(x - y = 6\).
1Step 1: Graph the Parametric Equations
To graph the curve given in parametric form \(x = t^2 + 2\) and \(y = t^2 - 4\), consider several values for \(t\). For example, if \(t = 0\), \(x = 2\) and \(y = -4\). If \(t = 1\), \(x = 3\) and \(y = -3\), and so on. By plotting these points and others within a reasonable range for \(t\), you'll notice the path traced by the curve on the \(xy\)-plane.
2Step 2: Eliminate the Parameter
To find a rectangular (Cartesian) equation for the curve, eliminate the parameter \(t\). Start by solving for \(t^2\) from one of the parametric equations. From \(x = t^2 + 2\), we get \(t^2 = x - 2\). Similarly, from \(y = t^2 - 4\), we get \(t^2 = y + 4\).
3Step 3: Establish the Relationship Between x and y
Since both equations from Step 2 equal \(t^2\), we can set them equal to each other:\(x - 2 = y + 4\) . Simplify this equation to get \(x - y = 6\). This is the rectangular equation of the curve.
Key Concepts
Graphing Plane CurvesRectangular EquationsParametric to Cartesian Conversion
Graphing Plane Curves
Graphing plane curves involves plotting a set of equations that describe both x and y coordinates in terms of a third variable, known as a parameter, often represented as \(t\). This is different from the typical Cartesian coordinates, where you might have y expressed directly in terms of x.
To graph these parametric equations, like \(x = t^2 + 2\) and \(y = t^2 - 4\), you need to substitute various values of \(t\) to find corresponding x and y points. For instance, if \(t = 0\), \(x = 2\) and \(y = -4\) gives you a point (2, -4) on the plane.
To graph these parametric equations, like \(x = t^2 + 2\) and \(y = t^2 - 4\), you need to substitute various values of \(t\) to find corresponding x and y points. For instance, if \(t = 0\), \(x = 2\) and \(y = -4\) gives you a point (2, -4) on the plane.
- Substitute different values of \(t\), like \(t = 1\) gives \(x = 3\) and \(y = -3\).
- Continue with more values to see the trend, forming a set of points (x, y) to plot.
- Recognize the shape and direction of the curve as you plot more points.
Rectangular Equations
Rectangular equations, also known as Cartesian equations, describe a curve in the plane using only x and y coordinates. This format removes the parameter \(t\) that was originally involved in parametric equations.
Converting to a rectangular equation often makes it simpler to analyze the relation between x and y directly. Once converted, the equation lets us understand the curve's characteristics, like its slope, intercepts, and any symmetries or patterns.
For the given parametric equations \(x = t^2 + 2\) and \(y = t^2 - 4\), our goal is to express the relationship between x and y without including \(t\).
Converting to a rectangular equation often makes it simpler to analyze the relation between x and y directly. Once converted, the equation lets us understand the curve's characteristics, like its slope, intercepts, and any symmetries or patterns.
For the given parametric equations \(x = t^2 + 2\) and \(y = t^2 - 4\), our goal is to express the relationship between x and y without including \(t\).
- Solve for \(t^2\) in terms of x: \(t^2 = x - 2\).
- Solve similarly for y: \(t^2 = y + 4\).
- Set these equal due to their common value in terms of \(t^2\), which gives \(x - 2 = y + 4\).
Parametric to Cartesian Conversion
Converting parametric equations to Cartesian equations is a crucial skill in analyzing curves without involving the parameter \(t\). This process simplifies the study of curves by providing a single equation relating x and y variables directly.
To carry out this conversion effectively, start by isolating \(t\) or its expressions involving powers, like \(t^2\), from one of the parametric equations. For instance, from \(x = t^2 + 2\), derive \(t^2 = x - 2\).
Do the same for the other equation, \(y = t^2 - 4\), obtaining \(t^2 = y + 4\). These equalities imply the parameter is eliminated when the two expressions for \(t^2\) are set equal:
To carry out this conversion effectively, start by isolating \(t\) or its expressions involving powers, like \(t^2\), from one of the parametric equations. For instance, from \(x = t^2 + 2\), derive \(t^2 = x - 2\).
Do the same for the other equation, \(y = t^2 - 4\), obtaining \(t^2 = y + 4\). These equalities imply the parameter is eliminated when the two expressions for \(t^2\) are set equal:
- Equate \(x - 2 = y + 4\), which results in \(x - y = 6\).
- This direct relationship between x and y allows for straightforward graphing and analysis without the extra step of parameter substitution.
Other exercises in this chapter
Problem 23
Given vectors u and v, find (a) \(2 u\) (b) \(2 u+3 v\) (c) \(v-3 u\) Do not use a calculator. $$\mathbf{u}=2 \mathbf{i}, \mathbf{v}=\mathbf{i}+\mathbf{j}$$
View solution Problem 23
Solve each triangle. \(a=9.3\) inches, \(b=5.7\) inches, \(c=8.2\) inches
View solution Problem 24
Find the sum of each pair of complex numbers. Express your answer in rectangular form. Do not use a calculator. $$7+6 i, 3 i$$
View solution Problem 24
Plot the point whose rectangular coondinates are given. Then determine nwo pairs of polar coondinates for the point with \(0^{\circ} \leq \theta
View solution