Problem 24
Question
Find the sum of the first ten terms of the sequence where \(a_{n}=2^{5-n} .31 \frac{31}{32}\)
Step-by-Step Solution
Verified Answer
The sum of the first ten terms is 31.
1Step 1: Identify the sequence type
The given sequence is defined by the formula \(a_{n}=2^{5-n}\). It represents a geometric sequence because each term is obtained by multiplying the previous term by a constant factor.
2Step 2: Recognize geometric sequence properties
For a geometric sequence, a common ratio \(r\) can be found by dividing any term by the previous term. Here, the common ratio \(r=\frac{a_{n+1}}{a_n}=\frac{2^{5-(n+1)}}{2^{5-n}}=\frac{1}{2}\).
3Step 3: Identify the first term
To find the sum of the first ten terms, begin by identifying the first term of the sequence when \(n=1\). Substitute \(n=1\) into the formula: \(a_1=2^{5-1}\cdot\frac{31}{32}=16\cdot\frac{31}{32}=15.5\).
4Step 4: Use the formula for the sum of a geometric series
The sum \(S_n\) of the first \(n\) terms of a geometric sequence is given by: \[S_n = a_1 \cdot \frac{1-r^n}{1-r}\] where \(a_1\) is the first term, \(r\) is the common ratio, and \(n\) is the number of terms.
5Step 5: Substitute values to find the sum
Now, substitute \(a_1=15.5\), \(r=\frac{1}{2}\), and \(n=10\) into the formula: \[S_{10} = 15.5 \cdot \frac{1-(\frac{1}{2})^{10}}{1-\frac{1}{2}}\] Calculate accordingly: \[S_{10} = 15.5 \cdot \frac{1-\frac{1}{1024}}{1-\frac{1}{2}} = 15.5 \cdot \frac{1023/1024}{1/2} = 15.5 \cdot \frac{1023}{512}\].
6Step 6: Calculate the sum
Perform the calculation from the previous step: \[S_{10} = 15.5 \times \frac{1023}{512} = 31\]. Thus, the sum of the first ten terms of the sequence is 31.
Key Concepts
Sum of Geometric SeriesCommon Ratio in SequencesFirst Term of a Sequence
Sum of Geometric Series
Knowing how to find the sum of a geometric series is a crucial skill in mathematics, especially when dealing with sequences. For a geometric sequence, each term has a consistent ratio, known as the common ratio, multiplied to the previous term. To calculate the sum of the first few terms in a geometric series, we use the formula: \[ S_n = a_1 \cdot \frac{1-r^n}{1-r} \] where \(a_1\) represents the first term, \(r\) is the common ratio, and \(n\) is the total number of terms. This formula helps us quickly find the sum without having to add each term individually. Let's break it down further:
- First Term (\(a_1\)): The initial term of the sequence.
- Common Ratio (\(r\)): The consistent factor by which each term is multiplied to get to the next.
- Terms (\(n\)): The number of terms you want to include in the sum.
Common Ratio in Sequences
The common ratio in a geometric sequence is the factor by which each term is multiplied to obtain the next term. It's the essence of geometric progression. Finding this ratio is straightforward: choose any term in the sequence and divide it by the preceding term. This gives us the ratio that forms the backbone of the sequence. In the given exercise, for example, the common ratio \(r\) was determined as \(\frac{1}{2}\). Here’s how you can verify:
- Take the term formula: \(a_n = 2^{5-n} \cdot \frac{31}{32}\), where \(n = 2\) gives us the second term.
- Divide the second term by the first to obtain: \(-)\) \(\frac{1}{2}\).
First Term of a Sequence
In any sequence, the first term plays a significant role as it sets the starting value and influences subsequent terms. In arithmetic and geometric sequences, this term often determines the overall trend and direction of the sequence. To find the first term \(a_1\) of a sequence, you substitute the starting value of the index, typically \(n = 1\), into the sequence formula. From our exercise:
- We substituted \(n = 1\) into \(a_n = 2^{5-n} \cdot \frac{31}{32}\).
- This gave us \(a_1 = 15.5\), setting the initial anchor for our sequence.
Other exercises in this chapter
Problem 23
Find the common ratio of the geometric sequence with 3 rd term 12 and 6 th term \(96.2\)
View solution Problem 23
$$ -3,-6,-9,-12,-15, \ldots $$ \(-3 n\)
View solution Problem 24
A well driller charges \(\$ 9.00\) per foot for the first 10 feet, \(\$ 9.10\) per foot for the next 10 feet, \(\$ 9.20\) per foot for the next 10 feet, and so
View solution Problem 24
Find the common ratio of the geometric sequence with 2nd term \(\frac{8}{3}\) and 5 th term \(\frac{64}{81} . \quad \frac{2}{3}\)
View solution