Problem 24
Question
Find the domain of each logarithmic function analytically. You may wish to support your answer graphically. $$f(x)=\log |6 x+6|$$
Step-by-Step Solution
Verified Answer
The domain is \((-\infty, -1) \cup (-1, \infty)\).
1Step 1: Understanding the Logarithmic Function
The function given is \(f(x) = \log|6x + 6|\). A logarithmic function is defined only for positive arguments. This means that inside the logarithm, the expression \(|6x + 6|\) must be greater than 0.
2Step 2: Solving the Inequality
To ensure the argument of the logarithm is positive, set the inequality: \(|6x + 6| > 0\). This inequality implies that \(6x + 6 eq 0\). To solve this, isolate \(x\): \[6x + 6 = 0 \] \ Solve for \(x\) by subtracting 6 from both sides: \[6x = -6 \] \ Divide both sides by 6: \[x = -1 \] Thus, \(6x + 6\) is non-zero when \(x eq -1\). The domain is therefore all \(x\) except \(x = -1\).
3Step 3: Writing the Domain
Since \(x\) can be any real number except \(-1\), the domain of \(f(x) = \log|6x + 6|\) is: \((-\infty, -1) \cup (-1, \infty)\).
Key Concepts
Domain of a FunctionInequalitiesGraphical Methods
Domain of a Function
When we talk about the domain of a function, we are trying to find all the possible input values for which the function is defined. For logarithmic functions, the argument inside the logarithm (what you're taking the log of) must be greater than zero. This is because logarithms of non-positive numbers are not defined in the real number system.
In our specific function, \(f(x) = \log|6x + 6|\), the absolute value \(|6x + 6|\) needs to be greater than zero. This means we solve the inequality \(|6x + 6| > 0\).
In our specific function, \(f(x) = \log|6x + 6|\), the absolute value \(|6x + 6|\) needs to be greater than zero. This means we solve the inequality \(|6x + 6| > 0\).
- This simplifies to \(6x + 6 eq 0\), which helps us identify values that \(x\) cannot take.
- When we solve \(6x + 6 = 0\), we find \(x = -1\).
Inequalities
Inequalities are expressions that define the range of values that satisfy a given condition. In the case of our logarithmic function, the condition is that the argument of the log function must be greater than zero.
To explore this further, we solved the inequality \(|6x + 6| > 0\). Absolute values can make things a bit tricky, as they reflect both positive and negative scenarios. However, in this instance, maintaining the expression simply different from zero suffices:
To explore this further, we solved the inequality \(|6x + 6| > 0\). Absolute values can make things a bit tricky, as they reflect both positive and negative scenarios. However, in this instance, maintaining the expression simply different from zero suffices:
- Finding \(6x + 6 eq 0\) leads us to \(x eq -1\).
- This means the inequality holds for all \(x\) except where \(x\) is precisely \(-1\).
Graphical Methods
Graphical methods offer a visual representation of mathematical functions, helping us understand where a function is defined and continuous. When dealing with logarithmic functions and their domains, a graph can illustrate where the function is valid—highlighting restrictions on \(x\).
For the function \(f(x) = \log|6x + 6|\), a graph helps visually assert the domain we calculated analytically. Here's how:
For the function \(f(x) = \log|6x + 6|\), a graph helps visually assert the domain we calculated analytically. Here's how:
- Plotting the expression \(|6x + 6| > 0\) on a graph, you’ll see the function dips at \(x = -1\), confirming it’s undefined there.
- The graph visually shows where the function rises and where restrictions apply, solidifying our understanding of the domain \((-\infty, -1) \cup (-1, \infty)\).
Other exercises in this chapter
Problem 23
Solve each equation. Give the exact answer. $$\log _{6} x=-3$$
View solution Problem 23
Graph each function by hand and support your sketch with a calculator graph. Give the domain, range. and equation of the asymptote. Determine if \(f\) is increa
View solution Problem 24
Decide whether each function is one-to-one. $$f(x)=-7$$
View solution Problem 24
Solve each equation. Give the exact answer. $$\log _{4} x=-\frac{1}{6}$$
View solution