Problem 24
Question
Find the derivative with respect to the independent variable. $$ f(x)=-3 \cos ^{2}\left(3 x^{2}-4\right) $$
Step-by-Step Solution
Verified Answer
The derivative is \( 18x \sin(6x^2 - 8) \).
1Step 1: Identify the function composition
The function given is a composition of a cosine squared function and a quadratic function. Rewriting it using another variable, let \( u = 3x^2 - 4 \), then the function becomes \( f(x) = -3 \cos^2(u) \). Differentiate using the chain rule.
2Step 2: Differentiate the outside function
Using the chain rule, differentiate \( -3 \cos^2(u) \) with respect to \( u \). Since \( -3 \cos^2(u) \) can be rewritten as \( -3 \times (\cos(u))^2 \), use the derivative of the power and the chain rule: \( \frac{d}{du}(-3(\cos(u))^2) = -3 \times 2\cos(u)(-\sin(u)) \). Simplifying this gives \( 6 \cos(u) \sin(u) \).
3Step 3: Differentiate the inside function
Differentiate the inner function \( u = 3x^2 - 4 \) with respect to \( x \). This derivative is \( \frac{du}{dx} = 6x \), using the power rule.
4Step 4: Combine results using the chain rule
Combine the derivatives from Step 2 and Step 3 using the chain rule: \( \frac{df}{dx} = 6 \cos(u) \sin(u) \times 6x \). This results in \( 36x \cos(u) \sin(u) \).
5Step 5: Simplify using trigonometric identity
Use the identity \( \sin(2u) = 2\sin(u)\cos(u) \) to simplify the expression. Thus, \( 36x \cos(u) \sin(u) = 18x \sin(2u) \).
6Step 6: Substitute back the original expression for u
Recall that \( u = 3x^2 - 4 \). Substitute back to get \( \frac{df}{dx} = 18x \sin(2 \times (3x^2 - 4)) \). Therefore, the derivative is \( 18x \sin(6x^2 - 8) \).
Key Concepts
DerivativeChain RuleTrigonometric Identity
Derivative
In calculus, a derivative represents the rate of change of a function with respect to a variable. It tells us how a function behaves as its input changes. For example, if we have a function like \( f(x) = ax^2 + bx + c \), the derivative \( f'(x) \) would help determine how the value of \( f \) changes as \( x \) changes. Derivatives are essential in understanding the behavior of functions:
- They help to find the slope of the tangent line to the curve at any point.
- They are used to find maximum and minimum points on a graph, which are crucial in optimization problems.
- They provide insights into the increasing or decreasing nature of functions.
Chain Rule
The chain rule is a formula used to compute the derivative of a composition of functions. When dealing with complex functions, like a function within another function, the chain rule simplifies the differentiation process.For the function provided, \( f(x) = -3 \cos^2(3x^2 - 4) \), the chain rule allows us to take the derivative by identifying the inner and outer functions.
- The inner function is \( u = 3x^2 - 4 \).
- The outer function is \( v = -3 \cos^2(u) \).
Trigonometric Identity
Trigonometric identities are equations involving trigonometric functions that are true for every value of the occurring variables where both sides are defined. These identities are powerful tools in calculus, particularly when simplifying derivatives of trigonometric functions.In the exercise, the identity \( \sin(2u) = 2 \sin(u) \cos(u) \) is crucial. This identity helps simplify expressions involving products of sine and cosine:
- The original derivative expression \( 36x \cos(u) \sin(u) \) uses this identity to become \( 18x \sin(2u) \).
Other exercises in this chapter
Problem 24
Calculate the linear approximation for \(f(x)\) : $$f(x) \approx f(a)+f^{\prime}(a)(x-a)$$ \(f(x)=e^{-3 x}\) at \(a=0\)
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(a) Use the formal definition to find the derivative of \(y=\frac{1}{x}\) at \(x=2\). (b) Show that the point \(\left(2, \frac{1}{2}\right)\) is on the graph of
View solution Problem 24
Differentiate the functions with respect to the independent variable. (Note that log denotes the logarithm to base 10.) $$ f(x)=\ln (3 x+4) $$
View solution Problem 24
Apply the product rule to find the normal line, in slope-intercept form, of \(y=f(x)\) at the specified point. \(f(x)=\frac{(2-x)(3-x)}{4}\), at \(x=-1\)
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