Problem 24
Question
Exercises \(19-28\) tell how many units and in what directions the graphs of the given equations are to be shifted. Give an equation for the shifted graph. Then sketch the original and shifted graphs together, labeling each graph with its equation. $$ y=-\sqrt{x} \quad \text { Right } 3 $$
Step-by-Step Solution
Verified Answer
Shift 3 units right: New equation is \(y = -\sqrt{x-3}\).
1Step 1: Identify the Original Function
The original equation given is \(y = -\sqrt{x}\). This is the equation of a graph where the negative square root of \(x\) is plotted. It is a transformed version of the basic square root function \(y = \sqrt{x}\) reflected across the x-axis.
2Step 2: Determine the Shift
The problem states that the graph of the function should be shifted 'Right 3'. This indicates a horizontal shift of the graph 3 units to the right on the Cartesian plane.
3Step 3: Formulate the Shifted Equation
To shift a function horizontally by \(c\) units, you modify the input \(x\) with an opposite sign. Therefore, shifting \(y = -\sqrt{x}\) 3 units to the right will result in the equation \(y = -\sqrt{x-3}\).
4Step 4: Sketch the Graphs
First, sketch the graph of the original function \(y = -\sqrt{x}\). This graph should start at the origin, moving downwards and to the right. Then, for the shifted function \(y = -\sqrt{x-3}\), move every point on the original graph 3 units to the right. Label each graph accordingly.
Key Concepts
Horizontal ShiftVertical ShiftReflected GraphSquare Root Function
Horizontal Shift
A horizontal shift involves moving the entire graph of a function left or right on the Cartesian plane. The direction and number of units to move are crucial for this transformation.
- A shift to the right is achieved by replacing the variable \(x\) with \(x - c\), where \(c\) is the number of units.
- A shift to the left is achieved by replacing \(x\) with \(x + c\).
Vertical Shift
A vertical shift modifies the position of a graph up or down along the y-axis. The vertical shift depends on whether you are adding or subtracting from the entire function.
- To shift upwards, add a constant \(k\) to the function, creating the new function \(y = f(x) + k\).
- To shift downwards, subtract \(k\) from the function, resulting in \(y = f(x) - k\).
Reflected Graph
Reflection in graphs involves flipping the graph across a particular axis, changing how it is presented visually.
- Reflecting across the x-axis is done by changing the function from \(y = f(x)\) to \(y = -f(x)\).
- Reflecting across the y-axis involves substituting \(x\) with \(-x\), i.e., from \(y = f(x)\) to \(y = f(-x)\).
Square Root Function
The square root function is foundational and appears in many mathematical contexts. The basic form is \(y = \sqrt{x}\), representing a half-parabola opening to the right. It starts at the origin (0,0) and moves upwards to the right as \(x\) increases.Significant characteristics of a square root function include:
- Domain: Non-negative values of \(x\), since square roots of negative numbers are not real.
- Range: Non-negative values of \(y\) for \(y = \sqrt{x}\) but changes with different transformations.
- Graph Shape: Starts at one point and moves in a positive or negative direction based on transformations.
Other exercises in this chapter
Problem 23
In Exercises 17–30, write an equation for each line described. Passes through \((-12,-9)\) and has slope 0
View solution Problem 24
Graph the functions in Exercises \(23-26\) $$ g(x)=\left\\{\begin{array}{ll}{1-x,} & {0 \leq x \leq 1} \\ {2-x,} & {1
View solution Problem 24
In Exercises \(19-30,\) say whether the function is even, odd, or neither. Give reasons for your answer. $$ g(x)=x^{4}+3 x^{2}-1 $$
View solution Problem 24
Solve the inequalities in Exercises \(19-34,\) expressing the solution sets as intervals or unions of intervals. Also, show each solution set on the real line.
View solution