Problem 24
Question
Exer \(19-36:\) Find an equation for the ellipse that has its center at the origin and satisfies the given conditions. Foci \(F(0, \pm 4), \quad\) minor axis of length 4
Step-by-Step Solution
Verified Answer
The ellipse is: \( \frac{x^2}{4} + \frac{y^2}{20} = 1 \).
1Step 1: Understand the Definition of an Ellipse
An ellipse is defined as the set of points such that the sum of the distances from any point on the ellipse to two fixed points, called foci, is constant. The standard equation of an ellipse centered at the origin with a vertical major axis is \( \frac{x^2}{b^2} + \frac{y^2}{a^2} = 1 \), where \( a > b \).
2Step 2: Identify the Given Elements
The foci of the ellipse are given as \( F(0, \pm 4) \). This means the distance \( c \) from the center to each focus is 4. Additionally, the minor axis, which is \( 2b \), is given as 4.
3Step 3: Calculate Half the Minor Axis
Since the length of the minor axis is 4, we find \( b \) by dividing it by 2: \( b = \frac{4}{2} = 2 \).
4Step 4: Use the Relationship Between \(a\), \(b\), and \(c\)
In an ellipse, \( c^2 = a^2 - b^2 \). We know \( c = 4 \) and \( b = 2 \), so we substitute these into the formula: \( 4^2 = a^2 - 2^2 \).
5Step 5: Solve for \(a^2\)
Calculate \( a^2 \) by solving the equation: \( 16 = a^2 - 4 \). Therefore, \( a^2 = 20 \).
6Step 6: Write the Equation of the Ellipse
Since \( a^2 = 20 \) and \( b^2 = 4 \), substitute these into the standard ellipse equation to get \( \frac{x^2}{4} + \frac{y^2}{20} = 1 \).
Key Concepts
Ellipse DefinitionEllipse FociMinor AxisStandard Equation of an Ellipse
Ellipse Definition
In simple terms, an ellipse is a squashed circle. It resembles an oval shape that can vary from being almost circular (when the two axes are close in length) to more elongated. The key geometric definition of an ellipse states that it comprises a set of points where the sum of the distances from two fixed points, known as the foci, is constant.
If you imagine stretching a loop of string tied at both ends to the foci, the path traced by the pencil will outline an ellipse. This fundamental property differentiates ellipses from other geometrical shapes, such as circles, which have equidistant points from a single central point.
Ellipse Foci
The foci are two crucial points on an ellipse. In our task, the foci are located at the coordinates
- \( F(0, +4 ) \)
- \( F(0, -4) \)
Minor Axis
The minor axis of an ellipse is the shortest diameter and is perpendicular to the major axis. For our given ellipse, the minor axis length is 4 units. This information helps us find the value of \( b \), half the length of the minor axis. In mathematical terms:
- The total length of the minor axis = 4 units.
- Therefore, \( b = \frac{4}{2} = 2 \).
Standard Equation of an Ellipse
The standard equation of an ellipse with its center at the origin differs based on which axis is the major one. Since the major axis is vertical in our example, the equation takes the form: \[ \frac{x^2}{b^2} + \frac{y^2}{a^2} = 1 \] where:
- \( a \) is the semi-major axis length, or \( a^2 = 20 \) as calculated,
- \( b \) is the semi-minor axis length, or \( b^2 = 4 \),
- The formula \( c^2 = a^2 - b^2 \) is used to find the relationship between \( a \), \( b \), and the distance \( c \) to the foci.
Other exercises in this chapter
Problem 24
Find an equation for the hyperbola that has its center at the origin and satisfies the given conditions. Foci \(F(0, \pm 3)\) vertices \(V(0, \pm 2)\)
View solution Problem 24
Find a polar equation that has the same graph as the equation in \(x\) and \(y\). $$2 y=-x+4$$
View solution Problem 24
Find an equation of the parabola that satisfies the given conditions. Focus \(F(-3,-2),\) directrix \(y=1\)
View solution Problem 25
Find a polar equation of the conic with focus at the pole that has the given eccentricity and equation of directrix. $$e=\frac{1}{3}, \quad r=2 \sec \theta$$
View solution