Problem 24
Question
Determine whether the distinct lines through each pair of points are parallel. $$(2,4)\( and \)(6,1) ;(-3,1)\( and \)(1,-2)$$
Step-by-Step Solution
Verified Answer
Yes, the distinct lines through each pair of points are parallel because they have the same slope of -3/4.
1Step 1: Determine the Slope of the First Line
The equation to calculate the slope of a line between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by \(m_1 = (y_2 - y_1) / (x_2 - x_1)\). For the first pair of points, \((2,4)\) and \((6,1)\), we substitute into the equation and get \(m_1 = (1-4) / (6-2) = -3/4\).
2Step 2: Determine the Slope of the Second Line
Similarly, the slope of the second line passing through the points \((-3,1)\) and \((1,-2)\) is calculated by \(m_2 = (y_2 - y_1) / (x_2 - x_1)\). Substituting the points into this equation, we get \(m_2 = (-2-1) / (1 - (-3)) = -3/4\).
3Step 3: Compare the Slopes
Next, the slopes of the two lines are compared. If the slopes are equal, then the lines are parallel. From step 1 and 2, we found that \(m_1 = m_2 = -3/4\). Therefore, the lines are indeed parallel. Note: When calculating the slopes, ensure that the calculation of slope does not result in division by zero, which would signify a vertical line.
Key Concepts
Slope CalculationEquation of a LineCoordinate Geometry
Slope Calculation
The slope of a line is a measure of its steepness and direction. It is calculated by the formula:
To compute the slope, subtract the y-coordinate of the first point from the y-coordinate of the second point, then do the same with their x-coordinates and divide the results.
In our example, for the points \( (2,4) \) and \( (6,1) \), the slope is:
- \( m = \frac{y_2 - y_1}{x_2 - x_1} \)
To compute the slope, subtract the y-coordinate of the first point from the y-coordinate of the second point, then do the same with their x-coordinates and divide the results.
In our example, for the points \( (2,4) \) and \( (6,1) \), the slope is:
- \( m_1 = \frac{1 - 4}{6 - 2} = \frac{-3}{4} \)
Equation of a Line
The equation of a line is essential for describing linear relationships in coordinate geometry. The simplest form of this equation is known as the slope-intercept form, represented as:
Once you have the slope, as calculated, and a point through which the line passes, you can substitute these values into the equation to solve for \( b \), the y-intercept.
Understanding the equation allows us to visualize the line on a coordinate plane where every solution is a point on the line. In the case of parallel lines, the slope remains unchanged, signifying lines that never meet or diverge as they both extend indefinitely.
- \( y = mx + b \)
Once you have the slope, as calculated, and a point through which the line passes, you can substitute these values into the equation to solve for \( b \), the y-intercept.
Understanding the equation allows us to visualize the line on a coordinate plane where every solution is a point on the line. In the case of parallel lines, the slope remains unchanged, signifying lines that never meet or diverge as they both extend indefinitely.
Coordinate Geometry
Coordinate geometry, also referred to as analytic geometry, bridges algebra and geometry by using a coordinate system. It empowers the analysis of geometric shapes via algebra, using an organized grid of horizontal and vertical lines known as axes.
Points in coordinate geometry are plotted as \( (x, y) \) pairs representing locations in this grid. By calculating distances and gradients (slopes) between these points, coordinate geometry aids in solving complex geometric problems algebraically.
Points in coordinate geometry are plotted as \( (x, y) \) pairs representing locations in this grid. By calculating distances and gradients (slopes) between these points, coordinate geometry aids in solving complex geometric problems algebraically.
- Helps quantify geometric relationships by assigning numerical values to geometric figures.
- Allows for precise plotting and visual representation of lines, curves, and shapes.
Other exercises in this chapter
Problem 24
Write the point-slope form of the equation of the line satisfying each of the conditions in Exercises \(1-28 .\) Then use the point-slope form of the equation t
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In Exercises \(13-26,\) begin by solving the linear equation for \(y .\) This will put the equation in slope-intercept form. Then find the slope and the \(y\) -
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Use intercepts and a checkpoint to graph each equation. $$6 x-2 y=12$$
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Plot the given point in a rectangular coordinate system. $$\left(0, \frac{7}{2}\right)$$
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