Problem 24
Question
\(\cdot\) Find the fundamental frequency and the frequency of the first three overtones of a pipe 45.0 \(\mathrm{cm}\) long (a) if the pipe is open at both ends; (b) if the pipe is closed at one end. (c) For each of the preceding cases, what is the number of the highest harmonic that may be heard by a person who can hear frequencies from 20 \(\mathrm{Hz}\) to \(20,000 \mathrm{Hz}\) ?
Step-by-Step Solution
Verified Answer
Open pipe: Fundamental frequency = 381.1 Hz, highest harmonic = 52.
Closed pipe: Fundamental frequency = 190.6 Hz, highest harmonic = 103.
1Step 1: Determine the Speed of Sound
First, note the speed of sound in air is approximately \( v = 343 \, \text{m/s} \). This value is needed to calculate the frequencies.
2Step 2: Calculate the Wavelength in an Open Pipe
For an open pipe resonator, the fundamental frequency (first harmonic) wavelength, \( \lambda_1 \), is given by the formula \( \lambda_1 = 2L \), where \( L \) is the length of the pipe. For a pipe of length \( 45.0 \, \text{cm} = 0.45 \, \text{m} \), the fundamental wavelength is \[ \lambda_1 = 2 \times 0.45 = 0.9 \, \text{m}. \]
3Step 3: Calculate the Fundamental Frequency of the Open Pipe
The fundamental frequency \( f_1 \) can be found using the relationship \[ f_1 = \frac{v}{\lambda_1} = \frac{343}{0.9} = 381.1 \, \text{Hz}. \]
4Step 4: Determine the Overtones of the Open Pipe
The first three overtones for an open pipe will have frequencies \( f_2 = 2f_1, \) \( f_3 = 3f_1, \) and \( f_4 = 4f_1. \) Using the fundamental frequency from Step 3:- \( f_2 = 2 \times 381.1 = 762.2 \, \text{Hz} \)- \( f_3 = 3 \times 381.1 = 1143.3 \, \text{Hz} \)- \( f_4 = 4 \times 381.1 = 1524.4 \, \text{Hz} \)
5Step 5: Calculate the Wavelength in a Closed Pipe
For a pipe closed at one end, the fundamental wavelength \( \lambda_1 \) is given by \( \lambda_1 = 4L \), so \[ \lambda_1 = 4 \times 0.45 = 1.8 \, \text{m}. \]
6Step 6: Calculate the Fundamental Frequency of the Closed Pipe
Using the relationship between frequency, speed, and wavelength:\[ f_1 = \frac{v}{\lambda_1} = \frac{343}{1.8} = 190.6 \, \text{Hz}. \]
7Step 7: Determine the Overtones in the Closed Pipe
For a closed pipe, overtones occur at odd integer multiples of the fundamental frequency. Calculate the first three overtones:- \( f_3 = 3 \times 190.6 = 571.8 \, \text{Hz} \)- \( f_5 = 5 \times 190.6 = 953.0 \, \text{Hz} \)- \( f_7 = 7 \times 190.6 = 1334.2 \, \text{Hz} \)
8Step 8: Find the Highest Audible Harmonic for the Open Pipe
A person can hear from 20 Hz to 20,000 Hz. For an open pipe, the harmonic frequencies are multiples of the fundamental frequency:- \( f_n = n \times 381.1 \, \text{Hz} \), find \( n \) such that \( n\times 381.1 < 20,000 \). Solve \( n < \frac{20,000}{381.1} \approx 52.5 \). The highest harmonic is \( n = 52 \).
9Step 9: Find the Highest Audible Harmonic for the Closed Pipe
For the closed pipe, the harmonic frequencies are \( f_n = (2k-1) \times 190.6 \), for odd \( n \) such that \( (2k-1) \times 190.6 < 20,000 \). Solve \( (2k-1) < \frac{20,000}{190.6} \approx 104.9 \). The highest harmonic is \( n = 103 \).
Key Concepts
Fundamental FrequencyOpen Pipe ResonatorClosed Pipe ResonatorSpeed of Sound
Fundamental Frequency
The fundamental frequency, often known as the first harmonic, refers to the lowest frequency produced by an oscillating system, such as a pipe resonator. It serves as the base frequency upon which overtones or harmonics build.
An important formula to remember when dealing with pipe resonators is the equation for frequency, given by:
In simpler terms, when you pluck a string of a given length, its vibration creates a sound wave that travels at the speed of sound, producing the fundamental frequency.
Understanding the fundamental frequency is crucial as it sets the stage for determining overtones, and hence, the harmonics of the system.
An important formula to remember when dealing with pipe resonators is the equation for frequency, given by:
- \[ f_1 = \frac{v}{\lambda} \]
In simpler terms, when you pluck a string of a given length, its vibration creates a sound wave that travels at the speed of sound, producing the fundamental frequency.
Understanding the fundamental frequency is crucial as it sets the stage for determining overtones, and hence, the harmonics of the system.
Open Pipe Resonator
An open pipe resonator is a type of tube with both ends open, allowing air to move freely in and out. This design supports both even and odd harmonics, multiplying the sound experience.
For an open pipe, the length \( L \) of the pipe plays a key role in determining its fundamental frequency. Using the equation:
The open pipe's harmonics can be seen in the formula:
In such resonators, the first overtone is twice the fundamental frequency, the second overtone is thrice, and so on. These harmonics create the rich sounds utilized in musical instruments like flutes and organ pipes.
For an open pipe, the length \( L \) of the pipe plays a key role in determining its fundamental frequency. Using the equation:
- \[ \lambda_1 = 2L \]
The open pipe's harmonics can be seen in the formula:
- \( f_n = n \times f_1 \)
In such resonators, the first overtone is twice the fundamental frequency, the second overtone is thrice, and so on. These harmonics create the rich sounds utilized in musical instruments like flutes and organ pipes.
Closed Pipe Resonator
A closed pipe resonator is a tube that is open at one end and closed at the other. This unique setup produces sound waves that only reflect odd harmonics, unlike their open-ended counterparts.
For closed pipes, the fundamental wavelength is given by:
The fundamental frequency is also determined using our standard formula, but the harmonics here follow a distinct pattern:
This means the pipe supports only the first, third, fifth harmonics, and so on, making instruments like clarinets and bassoons sound unique compared to open pipe instruments.
For closed pipes, the fundamental wavelength is given by:
- \[ \lambda_1 = 4L \]
The fundamental frequency is also determined using our standard formula, but the harmonics here follow a distinct pattern:
- \( f_n = (2k-1) \times f_1 \)
This means the pipe supports only the first, third, fifth harmonics, and so on, making instruments like clarinets and bassoons sound unique compared to open pipe instruments.
Speed of Sound
The speed of sound is a critical component in the propagation of sound waves through a medium. On a standard day at sea level, the speed of sound in air is approximately 343 meters per second.
Factors affecting the speed of sound include:
Understanding the speed of sound's dependency on the environment aids in accurately predicting and designing musical instruments and audio arrays.
Factors affecting the speed of sound include:
- Temperature: Sound travels faster in warmer air because molecules move more quickly.
- Medium: Sound waves travel at different speeds through air, water, and solid materials due to their density and elasticity.
- Humidity: More humid air increases the speed of sound because water vapor is less dense than dry air.
Understanding the speed of sound's dependency on the environment aids in accurately predicting and designing musical instruments and audio arrays.
Other exercises in this chapter
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