Problem 24
Question
(a) sketch the curve represented by the parametric equations (indicate the orientation of the curve). Use a graphing utility to confirm your result. (b) Eliminate the parameter and write the corresponding rectangular equation whose graph represents the curve. Adjust the domain of the resulting rectangular equation, if necessary. $$x=\cos \theta, y=4 \sin \theta$$
Step-by-Step Solution
Verified Answer
The graph of the parametric equations is an ellipse with a horizontal radius of 1 and a vertical radius of 4. The corresponding rectangular equation is \(x^2 + \frac{y^2}{16} = 1\).
1Step 1: Sketching the Curve
To start, recognize the nature of these parametric equations. The equations given are \(x = \cos \theta\) and \(y = 4 \sin \theta\). They signify an ellipse in the x-y plane, whose horizontal radius is 1 (from \(\cos \theta\)) and vertical radius is 4 (from \(4 \sin \theta\)). Now, sketch this ellipse on a paper or use a graphing utility to plot it. Remember to indicate the orientation, which is counterclockwise (since as \(\theta\) increases, we move in a counterclockwise direction).
2Step 2: Converting to Rectangular Form
To convert the parametric equations to a rectangular equation, one way is to solve one of the equations for \(\theta\) and then substitute into the other. However, for these particular equations, a more convenient way is to use the Pythagorean trigonometric identity \(\sin^2\theta + \cos^2\theta = 1\). Square both equations to get \(x^2 = \cos^2\theta\) and \(y^2 = 16\sin^2\theta\). Adding these two equations yields \(x^2 + \frac{y^2}{16} = 1\), which is the rectangular form of the given parametric equations. This equation represents an ellipse with a horizontal radius of 1 and a vertical radius of 4, consistent with our sketch. We don't need to adjust the domain in this case as the full ellipse is represented for \( \theta \) in the range from 0 to \(2\pi\).
Key Concepts
Elliptical CurvesPythagorean IdentityConverting Parametric to Rectangular EquationsGraphing Orientation
Elliptical Curves
Elliptical curves are fascinating geometrical shapes characterized by their oval-like appearance. Unlike circles, ellipses have two different radii: one for the horizontal axis and one for the vertical. In the given parametric equations
- \(x = \cos \theta\)
- \(y = 4 \sin \theta\)
Pythagorean Identity
In trigonometry, the Pythagorean identity is fundamental and can be a powerful tool when dealing with parametric equations. The identity \(\sin^2\theta + \cos^2\theta = 1\) originates from the Pythagorean theorem, which applies to right-angled triangles. This identity allows one to relate sine and cosine, which helps eliminate the parameter in equations and make them easier to work with.
By leveraging this identity, you can transition from parametric to rectangular forms smoothly. For example, by squaring the parametric equations \(x = \cos \theta\) and \(y = 4 \sin \theta\), you get \(x^2 = \cos^2 \theta\) and \(y^2 = 16 \sin^2 \theta\). Adding these gives us the relationship \(x^2 + \frac{y^2}{16} = 1\), revealing the rectangular form of the ellipse. Such transitions enhance understanding and provide a clear path to graphing complex entities.
By leveraging this identity, you can transition from parametric to rectangular forms smoothly. For example, by squaring the parametric equations \(x = \cos \theta\) and \(y = 4 \sin \theta\), you get \(x^2 = \cos^2 \theta\) and \(y^2 = 16 \sin^2 \theta\). Adding these gives us the relationship \(x^2 + \frac{y^2}{16} = 1\), revealing the rectangular form of the ellipse. Such transitions enhance understanding and provide a clear path to graphing complex entities.
Converting Parametric to Rectangular Equations
Converting parametric equations into rectangular form is a significant step in simplifying complex relations. The idea is to eliminate the parameter \(\theta\) and derive an equation in terms of \(x\) and \(y\) only. For the given parametric equations:
This method often uncovers hidden features of the curve and is more applicable in various mathematical analyses.
- \(x = \cos \theta\)
- \(y = 4 \sin \theta\)
This method often uncovers hidden features of the curve and is more applicable in various mathematical analyses.
Graphing Orientation
Understanding the orientation of a graph helps in correctly interpreting the parametric equations. The orientation indicates the direction in which a curve is traced as the parameter increases. For the parametric equations
To visualize this, imagine tracing the shape on the paper; as \(\theta\) increases, follow the path your pen takes. This can also be confirmed using graphing utilities that animate the tracing of curves, showing the path followed as you move along the curve. Being aware of graph orientation is crucial for accurate representation and understanding of parametric curves.
- \(x = \cos \theta\)
- \(y = 4 \sin \theta\)
To visualize this, imagine tracing the shape on the paper; as \(\theta\) increases, follow the path your pen takes. This can also be confirmed using graphing utilities that animate the tracing of curves, showing the path followed as you move along the curve. Being aware of graph orientation is crucial for accurate representation and understanding of parametric curves.
Other exercises in this chapter
Problem 24
Use symmetry to sketch the graph of the polar equation. Use a graphing utility to verify your graph. $$\theta=-5 \pi / 3$$
View solution Problem 24
Plot the point given in polar coordinates and find the corresponding rectangular coordinates for the point. $$\left(0, \frac{5 \pi}{4}\right)$$
View solution Problem 24
Write the equation of the circle in standard form. Then identify its center and radius. $$x^{2}+y^{2}-10 x-6 y+25=0$$
View solution Problem 24
Find the center, vertices, foci, and asymptotes of the hyperbola, and sketch its graph using the asymptotes as an aid. Use graphing utility to verify your graph
View solution