Problem 24
Question
A processor of carrots cuts the green top off each carrot, washes the carrots, and inserts six to a package. Twenty packages are inserted in a box for shipment. Each box of carrots should weigh 20.4 pounds. The processor knows that the standard deviation of box weight is 0.5 pound. The processor wants to know if the current packing process meets the 20.4 weight standard. How many boxes must the processor sample to be \(95 \%\) confident that the estimate of the population mean is within 0.2 pound?
Step-by-Step Solution
Verified Answer
The processor needs to sample 25 boxes to be 95% confident.
1Step 1: Identify the Known Values
We know that the standard deviation of the weight of the boxes is 0.5 pounds, the desired confidence level is 95%, and the margin of error is 0.2 pounds.
2Step 2: Find the Z-value for the Desired Confidence Level
For a 95% confidence level, the Z-value is typically 1.96. This is derived from the standard normal distribution table.
3Step 3: Apply the Sample Size Formula
Use the formula for sample size: \[ n = \left( \frac{Z \cdot \sigma}{E} \right)^2 \]where \( \sigma \) is the standard deviation, \( E \) is the margin of error, and \( Z \) is the Z-value for the desired confidence level.
4Step 4: Insert Known Values into the Formula
Substitute the known values into the formula: \[ n = \left( \frac{1.96 \cdot 0.5}{0.2} \right)^2 \]
5Step 5: Calculate the Sample Size
Simplify the expression inside the parentheses first, \[ \frac{1.96 \cdot 0.5}{0.2} = 4.9 \] Then calculate the square of 4.9:\[ n = (4.9)^2 = 24.01 \]
6Step 6: Round Up to the Nearest Whole Number
Since sample size must be a whole number, round up 24.01 to 25.
Key Concepts
Confidence IntervalStandard DeviationMargin of ErrorZ-value
Confidence Interval
A confidence interval gives a range of values within which we can be certain the true population parameter lies, to a point of confidence. For example, if we have a 95% confidence interval, that means that, statistically, if we repeated an experiment or sampled randomly multiple times, 95% of the intervals calculated from those experiments should contain the population parameter.
- The concept allows researchers to quantify the uncertainty in measurements or results.
- In practical terms, the confidence level tells you how sure you can be that the interval includes the parameter being estimated.
Standard Deviation
Standard deviation measures how spread out the numbers in a data set are. In the context of this exercise, the standard deviation of box weight is given as \(0.5\) pounds. This figure indicates how much variation or "dispersion" exists from the average box weight.
- A smaller standard deviation means the values tend to be close to the mean.
- A larger deviation indicates that the values are more spread out.
Margin of Error
The margin of error represents the extent of random sampling error in a survey’s results. In this case, the margin of error is \(0.2\) pounds, meaning that the processor wants to ensure that the estimate of the population mean won't deviate from the actual mean by more than \(0.2\) pounds.
- It reflects listeners' willingness for an acceptable range of difference?
- Helps gauge the precision of estimates – the smaller the margin, the more precise the estimate.
Z-value
The Z-value, within the realm of statistics, is a measure that describes a value's relationship to the mean of a group of values. It signifies how many standard deviations an element is from the mean. For a 95% confidence level, the Z-value is typically \(1.96\). This number is crucial in deriving confidence intervals due to its tie to the standard normal distribution.
- This value is also known as the 'critical value' and varies with the confidence level.
- The chosen Z-value anchors the confidence interval width, directly affecting the interval's precision.
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