Problem 24
Question
A neodymium-glass laser emits short pulses of high-intensity electromagnetic waves. The electric field of such a wave has an rms value of \(E_{\mathrm{rms}}=2.0 \times 10^{9} \mathrm{~N} / \mathrm{C} .\) Find the average power of each pulse that passes through a \(1.6 \times 10^{-5}-\mathrm{m}^{2}\) surface that is perpendicular to the laser beam.
Step-by-Step Solution
Verified Answer
The average power is approximately \( 8.5 \times 10^{10} \ \text{W} \).
1Step 1: Understanding the Concept
The average power of an electromagnetic wave passing through a surface is related to the intensity of the wave and the area it passes through. The intensity is given by the formula \( I = \frac{1}{2} c \varepsilon_0 E_{\text{rms}}^2 \), where \( c \) is the speed of light and \( \varepsilon_0 \) is the permittivity of free space.
2Step 2: Calculate the Intensity
Substitute \( E_{\text{rms}} = 2.0 \times 10^9 \ \text{N/C} \), \( c = 3.0 \times 10^8 \ \text{m/s} \), and \( \varepsilon_0 = 8.85 \times 10^{-12} \ \text{F/m} \) into the formula:\[I = \frac{1}{2} \times 3.0 \times 10^8 \ \text{m/s} \times 8.85 \times 10^{-12} \ \text{F/m} \times (2.0 \times 10^9 \ \text{N/C})^2\].Calculate \( I \).
3Step 3: Compute the Intensity Result
Perform the calculations: \[I = \frac{1}{2} \times 3.0 \times 10^8 \times 8.85 \times 10^{-12} \times 4.0 \times 10^{18}\].Calculate \( I = 5.31 \times 10^{15} \ \text{W/m}^2 \).
4Step 4: Compute the Average Power
Use the formula \( P = I \times A \) to calculate the average power, where \( A = 1.6 \times 10^{-5} \ \text{m}^2 \) is the area. Substitute \( I \) from Step 3:\[P = 5.31 \times 10^{15} \ \text{W/m}^2 \times 1.6 \times 10^{-5} \ \text{m}^2 \].
5Step 5: Solve for Average Power
Calculate the result:\[P = 5.31 \times 1.6 \times 10^{10}\].Thus, the average power \( P = 8.5 \times 10^{10} \ \text{W} \).
Key Concepts
Electromagnetic WavesIntensity of LightElectric Field
Electromagnetic Waves
Electromagnetic waves are waves that carry energy through space. They are produced by the movement of charged particles and do not require a medium to travel through. Electromagnetic waves encompass a broad spectrum: from radio waves to gamma rays. This spectrum is categorized based on the frequency and wavelength of the waves.
An important characteristic of electromagnetic waves is that they travel at the speed of light, which is approximately \(3.0 \times 10^8 \ \text{m/s}\). They consist of perpendicular electric and magnetic fields that oscillate and propagate through space. These fields are perpendicular to each other and to the direction of wave travel, meaning they are transverse waves.
An important characteristic of electromagnetic waves is that they travel at the speed of light, which is approximately \(3.0 \times 10^8 \ \text{m/s}\). They consist of perpendicular electric and magnetic fields that oscillate and propagate through space. These fields are perpendicular to each other and to the direction of wave travel, meaning they are transverse waves.
- Electromagnetic waves can transfer energy across vast distances, like from the sun to the earth.
- They are utilized in numerous technologies, such as radio transmission, medical imaging, and laser applications.
Intensity of Light
The intensity of light is a measure of the energy carried by light waves as they travel through a given area. It is often expressed in watts per square meter \(W/m^2\). In practical terms, intensity tells us how bright or strong the light is at a particular point.
For electromagnetic waves like those emitted by a laser, intensity \(I\) can be calculated using the formula:
\[I = \frac{1}{2} c \varepsilon_0 E_{\text{rms}}^2\]
where
For electromagnetic waves like those emitted by a laser, intensity \(I\) can be calculated using the formula:
\[I = \frac{1}{2} c \varepsilon_0 E_{\text{rms}}^2\]
where
- \(c\) is the speed of light (\(3.0 \times 10^8 \ \text{m/s}\)),
- \(\varepsilon_0\) is the permittivity of free space (\(8.85 \times 10^{-12} \ \text{F/m}\)),
- and \(E_{\text{rms}}\) is the root mean square of the electric field strength.
Electric Field
The electric field is a vector field that represents the electric force per unit charge exerted at each point in space. It is produced by electric charges or by changing magnetic fields. In the context of electromagnetic waves, the electric field is a fundamental component, and its strength can significantly impact the intensity of the wave.
For lasers, the electric field is often described by its root mean square (RMS) value, which provides a measure of its average magnitude across the waveform:
\(E_{\mathrm{rms}} = \frac{E_{0}}{\sqrt{2}}\)
where \(E_{0}\) is the peak electric field.
For lasers, the electric field is often described by its root mean square (RMS) value, which provides a measure of its average magnitude across the waveform:
\(E_{\mathrm{rms}} = \frac{E_{0}}{\sqrt{2}}\)
where \(E_{0}\) is the peak electric field.
- The RMS value gives us a practical measure to calculate the intensity of the light wave.
- In laser applications, the more intense the electric field, the higher the potential energy carried by the laser beam, useful in applications like cutting or medical treatments.
Other exercises in this chapter
Problem 22
An industrial laser is used to burn a hole through a piece of metal. The average intensity of the light is \(\bar{S}=1.23 \times 10^{9} \mathrm{~W} / \mathrm{m}
View solution Problem 23
The microwave radiation left over from the Big Bang explosion of the universe has an average energy density of \(4 \times 10^{-14} \mathrm{~J} / \mathrm{m}^{3}\
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The average intensity of sunlight at the top of the earth's atmosphere is \(1390 \mathrm{~W} / \mathrm{m}^{2}\). What is the maximum energy that a \(25-\mathrm{
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The mean distance between earth and the sun is \(1.50 \times 10^{11} \mathrm{~m} .\) The average intensity of solar radiation incident on the upper atmosphere o
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