Problem 24
Question
(a) Graph \(f(x)=x, x \geq 0\), and \(g(x)=x^{2}, x \geq 0\), together, in one coordinate system. (b) For which values of \(x\) is \(f(x) \geq g(x)\), and for which values of \(x\) is \(f(x) \leq g(x)\) ?
Step-by-Step Solution
Verified Answer
\(f(x) \geq g(x)\) for \(0 \leq x \leq 1\); \(f(x) \leq g(x)\) for \(x \geq 1\).
1Step 1: Identify the Functions
We have two functions: \(f(x) = x\) and \(g(x) = x^2\). Both functions are defined for \(x \geq 0\). We'll graph these functions on the same coordinate plane.
2Step 2: Graph the Functions
Firstly, plot the line \(f(x) = x\), which is a straight line through the origin with a slope of 1. Next, plot \(g(x) = x^2\), which is a parabola with its vertex at the origin that opens upwards. The graph of \(f(x) = x\) is linear, while \(g(x) = x^2\) is quadratic.
3Step 3: Find Points of Intersection
To find where these functions intersect, set \(f(x) = g(x)\), which leads to \(x = x^2\). Solve the equation \(x^2 - x = 0\) by factoring: \(x(x-1) = 0\). It gives us solutions \(x = 0\) and \(x = 1\). These are the points where the two graphs intersect.
4Step 4: Determine Sections of Inequality
Test intervals between intersection points to determine where \(f(x) = x\) is greater than or less than \(g(x) = x^2\). Choose test points in the intervals \([0, 1]\) and \([1, \infty)\).
5Step 5: Check Interval \([0, 1]\)
Select a test point, for example, \(x = 0.5\). Calculate \(f(0.5) = 0.5\) and \(g(0.5) = (0.5)^2 = 0.25\). Since \(0.5 > 0.25\), in the interval \([0, 1]\), \(f(x) \geq g(x)\).
6Step 6: Check Interval \([1, \infty)\)
Select a test point, for example, \(x = 2\). Calculate \(f(2) = 2\) and \(g(2) = 2^2 = 4\). Since \(2 < 4\), in the interval \([1, \infty)\), \(f(x) \leq g(x)\).
Key Concepts
Intersection of FunctionsLinear and Quadratic FunctionsInequalities in Functions
Intersection of Functions
The intersection of two functions refers to the points where the graphs of these functions cross each other on a coordinate plane. To find the intersection point, we set the functions equal to each other. For example, given two functions, \( f(x) = x \) and \( g(x) = x^2 \), we solve the equation \( f(x) = g(x) \), which simplifies to \( x = x^2 \).
Factoring this equation, we have \( x(x - 1) = 0 \). This gives us the solutions \( x = 0 \) and \( x = 1 \), indicating the points where the two graphs intersect. These intersections are crucial as they reveal the points where both functions have the same output value. Understanding these intersections can help in analyzing the behavior of the functions and their comparative growth or decay within given domains.
Factoring this equation, we have \( x(x - 1) = 0 \). This gives us the solutions \( x = 0 \) and \( x = 1 \), indicating the points where the two graphs intersect. These intersections are crucial as they reveal the points where both functions have the same output value. Understanding these intersections can help in analyzing the behavior of the functions and their comparative growth or decay within given domains.
Linear and Quadratic Functions
Linear functions, like \( f(x) = x \), represent straight lines on a graph. They have a constant rate of change and are defined by equations of the form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. In our case, the line \( f(x) = x \) crosses the origin, and its slope is \( 1 \).
Quadratic functions, like \( g(x) = x^2 \), form parabolas on a graph. These functions have a variable rate of change, represented by equations of the form \( y = ax^2 + bx + c \). The function \( g(x) = x^2 \) is a simple parabola with its vertex at the origin, opening upwards.
Both function types are fundamental in algebra, illustrating basic graph shapes and providing insights into real-world scenarios such as motion, growth, and optimization. Understanding their shapes and properties helps in predicting and interpreting mathematical and practical situations.
Quadratic functions, like \( g(x) = x^2 \), form parabolas on a graph. These functions have a variable rate of change, represented by equations of the form \( y = ax^2 + bx + c \). The function \( g(x) = x^2 \) is a simple parabola with its vertex at the origin, opening upwards.
Both function types are fundamental in algebra, illustrating basic graph shapes and providing insights into real-world scenarios such as motion, growth, and optimization. Understanding their shapes and properties helps in predicting and interpreting mathematical and practical situations.
Inequalities in Functions
Inequalities in functions highlight the intervals where one function's output is greater than or less than another's. This is particularly useful when comparing rates of change or growth within the same graph. In our scenario, we examine the intervals where \( f(x) = x \) is greater than or equal to \( g(x) = x^2 \) and vice versa.
- For the interval \([0, 1]\), testing with a point like \( x = 0.5 \), we find \( f(0.5) = 0.5 \) and \( g(0.5) = 0.25 \). Here, \( f(x) \) is greater than \( g(x) \), so \( f(x) \geq g(x) \).
- For the interval \([1, \infty)\), using a test point such as \( x = 2 \), we calculate \( f(2) = 2 \) and \( g(2) = 4 \). This shows \( f(x) \leq g(x) \) since 2 is less than 4.
Other exercises in this chapter
Problem 23
Determine the equation of the line that satisfies the stated requirements. Put the equation in standard form. The line with slope \(-2\) and \(x\) -intercept \(
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Explain how the following functions can be obtained from \(y=x^{3}\) by basic transformations: (a) \(y=x^{3}-1\) (b) \(y=-x^{3}-1\) (c) \(y=-3(x-1)^{3}\)
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Determine the equation of the line that satisfies the stated requirements. Put the equation in standard form. The line with slope 1 and \(x\) -intercept ( 2,0 )
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Explain how the following functions can be obtained from \(y=1 / x\) by basic transformations: (a) \(y=1-\frac{1}{x}\) (b) \(y=-\frac{1}{x-1}\) (c) \(y=\frac{x}
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