Problem 24
Question
A drug has a half-life of 12 hours. If the initial dosage is 5 milligrams, how many milligrams will be in the patient's body in 16 hours?
Step-by-Step Solution
Verified Answer
Approximately 1.984 milligrams remain after 16 hours.
1Step 1: Understand the Concept of Half-life
The half-life of a drug is the time it takes for half of the drug to be eliminated from the body. In this exercise, the half-life is given as 12 hours, meaning every 12 hours, the drug amount reduces to half of its previous amount.
2Step 2: Identify Initial Conditions and Time Passed
The initial dosage given is 5 milligrams. We need to determine how many milligrams remain in the body after 16 hours.
3Step 3: Calculate the Number of Half-lives Passed
Determine how many half-lives pass in 16 hours. Since one half-life is 12 hours: \[ \text{Number of half-lives} = \frac{16}{12} = \frac{4}{3} \approx 1.33 \]
4Step 4: Apply the Half-life Formula
Use the exponential decay formula: \[ A = A_0 \times \left( \frac{1}{2} \right)^n \]where \( A_0 = 5 \) milligrams, \( n = \frac{4}{3} \). Substitute these values into the formula: \[ A = 5 \times \left( \frac{1}{2} \right)^\frac{4}{3} \]
5Step 5: Compute the Remaining Dosage
Calculate the amount \( A \) using a calculator:\[ A = 5 \times 0.39685 \approx 1.984 \text{ milligrams} \]Here, the critical computation is that \( \left( \frac{1}{2} \right)^\frac{4}{3} \approx 0.39685 \).
6Step 6: Conclude with the Result
After 16 hours, approximately 1.984 milligrams of the drug remain in the patient's body.
Key Concepts
Understanding Half-lifeInitial Dosage ExplanationIntroducing the Exponential Decay Formula
Understanding Half-life
Half-life is a fundamental concept in science, particularly in chemistry and pharmacology. It refers to the time required for a substance to reduce to half its initial amount. In our case, it's about how the concentration of a drug decreases over time.
For example, if a drug's half-life is 12 hours, starting with 5 milligrams means after 12 hours, only 2.5 milligrams will remain in the body. This process continues every 12 hours, cutting the current amount by half each time.
For example, if a drug's half-life is 12 hours, starting with 5 milligrams means after 12 hours, only 2.5 milligrams will remain in the body. This process continues every 12 hours, cutting the current amount by half each time.
- Half-life is consistent: no matter how much you start with, it always takes the same amount of time to halve the remaining substance.
- It's crucial for understanding how medications process and are eliminated from the body.
Initial Dosage Explanation
The initial dosage is the starting amount of a drug administered to a patient. It is crucial because it determines the initial concentration of the medicine in the body.
In terms of exponential decay, the initial dosage is denoted as \(A_0\) in the formula. This value is a benchmark that allows us to predict future concentrations after certain time intervals.
In terms of exponential decay, the initial dosage is denoted as \(A_0\) in the formula. This value is a benchmark that allows us to predict future concentrations after certain time intervals.
- Initial dosage: set by medical professionals based on factors like age, weight, and health condition.
- It's important for effective treatment: too little might be ineffective, too much could be harmful.
Introducing the Exponential Decay Formula
The exponential decay formula plays a crucial role in calculating how a substance reduces over time. It's particularly useful in contexts such as radioactive decay and pharmacokinetics.
The formula is given by:\[A = A_0 \times \left( \frac{1}{2} \right)^n\]Here, \(A\) represents the remaining dosage, \(A_0\) is the initial dosage, and \(n\) is the number of half-lives that have elapsed.
The formula is given by:\[A = A_0 \times \left( \frac{1}{2} \right)^n\]Here, \(A\) represents the remaining dosage, \(A_0\) is the initial dosage, and \(n\) is the number of half-lives that have elapsed.
- This formula illustrates how each half-life reduces the amount by 50%.
- It's a reliable tool for predicting decreases in drug concentrations or decay processes.
Other exercises in this chapter
Problem 23
Write each expression as a sum or difference of logarithms. Example: \(\log \left(m^{2} n^{5}\right)=2 \log m+5 \log n\) $$\log _{b}\left(x^{1 / 2} y^{1 / 3}\ri
View solution Problem 23
Write each exponential equation in its equivalent logarithmic form. $$78,125=5^{7}$$
View solution Problem 24
Solve the exponential equations. Make sure to isolate the base to a power first. Round our answers to three decimal places. $$e^{x^{2}}=73$$
View solution Problem 24
Write each expression as a sum or difference of logarithms. Example: \(\log \left(m^{2} n^{5}\right)=2 \log m+5 \log n\) $$\log _{b}(\sqrt{r} \sqrt[3]{t})$$
View solution