Problem 24
Question
A compound alloy of gold and copper crystallizes in a cubic lattice in which the gold atoms occupy the lattice points at the corners of a cube and a copper atom occupies the center of each cube face. The formula of this compound is (a) \(\mathrm{Au}_{3} \mathrm{Cu}\) (b) \(\mathrm{AuCu}_{3}\) (c) \(\mathrm{Au}_{4} \mathrm{Cu}\) (d) \(\mathrm{AuCu}_{2}\)
Step-by-Step Solution
Verified Answer
The formula of the compound is \( \text{AuCu}_3 \).
1Step 1: Understand the Lattice Structure
The cubic lattice has gold atoms at the corners of the cube and copper atoms at the center of each face. In a unit cell of a cubic lattice, there are 8 corners and 6 faces.
2Step 2: Calculate Contribution of Gold Atoms
Each corner atom is shared by 8 adjacent unit cells in a cubic lattice. Therefore, the contribution of gold atoms per unit cell is \( \frac{8}{8} = 1 \) gold atom.
3Step 3: Calculate Contribution of Copper Atoms
Each face-centered atom is shared by 2 unit cells. Therefore, the contribution of copper atoms per unit cell is \( \frac{6}{2} = 3 \) copper atoms.
4Step 4: Determine the Empirical Formula
Combine the number of gold and copper atoms calculated to determine the empirical formula of the compound: \( \text{1 Au atom} + \text{3 Cu atoms} = \text{AuCu}_3 \).
Key Concepts
Cubic LatticeEmpirical Formula CalculationFace-Centered Cubic Structure
Cubic Lattice
A cubic lattice is one of the simplest and most common ways that atoms are arranged in a crystal structure. Imagine a cube where atoms are positioned at the corners. These corner atoms are shared among multiple cubes. Specifically, each atom at a corner connects with eight neighboring cubes. This sharing is efficient in packing the atoms into a repeating pattern.
Cubic lattices are characterized by their symmetrical geometry, which means the sides and angles are all the same. They can be found in different variations such as simple cubic, body-centered cubic (BCC), and face-centered cubic (FCC). Understanding the cubic lattice gives a good foundation for further insights, including those involving more complex structures.
Empirical Formula Calculation
Finding the empirical formula of a compound involves determining the simplest whole-number ratio of atoms present. In the context of a crystal lattice, this means counting the contribution of each type of atom in a unit cell. When calculating the empirical formula for compounds in a crystal structure:
- Identify the different sites that each type of atom occupies.
- Calculate the number of each type of atom in a unit cell by considering shared and unshared positions.
- For corner atoms, because each corner atom is shared by eight cubes, its contribution is \( \frac{1}{8} \) per cube.
- For face-centered atoms, shared by two cubes, the contribution is \( \frac{1}{2} \) per cube face.
Face-Centered Cubic Structure
The face-centered cubic (FCC) structure is a specific type of cubic lattice. In this configuration, atoms are located at each corner and the center of each face of the cube.
The FCC structure is one of the most closely packed arrangements possible, second only to the hexagonal close-packed structure. Because of this dense packing:
- FCC structures are highly efficient in how they use space.
- They typically have high coordination numbers, meaning each atom in the lattice is in close contact with many others.
Other exercises in this chapter
Problem 22
Which of the following is arranged in order of increasing molecular speed? (a) \(\mathrm{HBr}
View solution Problem 23
A solid is made of two elements \(\mathrm{A}\) and \(\mathrm{B}\). The atoms of \(\mathrm{A}\) are arranged in a cep structure and those of B occupy all the tet
View solution Problem 24
In which of the following pairs of the molecules (gaseous) have the same root mean square speed ? (a) He and \(\mathrm{Ar}\) (b) \(\mathrm{NO}_{2}\) and \(\math
View solution Problem 25
Which of the following solids is amorphous ? (a) Fe metal (b) Fused quartz (e)' Wurtzite (d) NiAs
View solution