Problem 24
Question
A beam of electrons \(\left(m=9.11 \times 10^{-31} \mathrm{kg} / \text { electron }\right)\) has an average speed of \(1.3 \times 10^{8} \mathrm{m} \cdot \mathrm{s}^{-1} .\) What is the wavelength of electrons having this average speed?
Step-by-Step Solution
Verified Answer
The wavelength of electrons is approximately \( 5.60 \times 10^{-12} \text{ m} \).
1Step 1: Identify Known Values
We start by noting down the values we have. The mass of an electron is \( m = 9.11 \times 10^{-31} \text{ kg} \) and the average speed \( v = 1.3 \times 10^8 \text{ m/s} \).
2Step 2: Determine Formula to Use
Given these values, we need to find the wavelength of the electrons. This can be achieved using the de Broglie wavelength formula, defined as \( \lambda = \frac{h}{mv} \), where \( h \) is the Planck's constant \( h = 6.63 \times 10^{-34} \text{ J·s} \).
3Step 3: Substitute Values into the Formula
Substitute the known values into the de Broglie wavelength formula: \[ \lambda = \frac{6.63 \times 10^{-34} \text{ J·s}}{9.11 \times 10^{-31} \text{ kg} \times 1.3 \times 10^8 \text{ m/s}}. \]
4Step 4: Calculate the Wavelength
Now, perform the calculation: \[ \lambda = \frac{6.63 \times 10^{-34}}{(9.11 \times 10^{-31}) \times (1.3 \times 10^8)} = \frac{6.63 \times 10^{-34}}{1.1843 \times 10^{-22}}. \] \[ \lambda \approx 5.60 \times 10^{-12} \text{ m}. \]
5Step 5: Result Interpretation
The calculated wavelength \( \lambda \approx 5.60 \times 10^{-12} \text{ m} \) represents the wavelength of electrons moving at an average speed of \( 1.3 \times 10^8 \text{ m/s} \). This wavelength is in the picometer range, typical for particles like electrons.
Key Concepts
Electron SpeedPlanck ConstantWavelength CalculationParticle Physics
Electron Speed
In this scenario, we are dealing with electrons moving at a significant speed. Understanding electron speed is crucial in particle physics, as the behavior of particles at different velocities can vary greatly.
- Electrons have mass: \(9.11 \times 10^{-31} \text{ kg}\).
- In the given problem, the electrons' speed is \(1.3 \times 10^8 \text{ m/s}\).
Planck Constant
The Planck constant is a fundamental figure in quantum mechanics. It is essential for calculations involving particle wavelengths, notably in the realm of wave-particle duality.The value of the Planck constant is \(6.63 \times 10^{-34} \text{ J·s}\).
- This constant relates the energy of a photon to its frequency: \(E = h u\).
- It is critical when calculating the de Broglie wavelength.
Wavelength Calculation
To compute the wavelength of the electrons, we apply the de Broglie wavelength formula:\[ \lambda = \frac{h}{mv} \]Here, \(\lambda\) represents the wavelength, \(h\) is the Planck constant, \(m\) refers to the mass of the electron, and \(v\) is the speed of the electron.
- The aim is to find the wavelength at a given speed.
- Plugging in the values: \( \lambda = \frac{6.63 \times 10^{-34}}{9.11 \times 10^{-31} \times 1.3 \times 10^8} \).
Particle Physics
Particle physics explores the nature of subatomic particles, like electrons. It explains how these particles behave and interact at high velocities, as well as incorporating both particle and wave-like traits.
The de Broglie wavelength is central in understanding wave-particle duality. In essence, subatomic particles can exhibit characteristics of both waves and particles.
- Particles have measurable wavelengths depending on their momentum.
- This duality supports quantum theories, enriching our understanding of atomic scales.
Other exercises in this chapter
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