Problem 239
Question
For the following exercises, sketch the graph of the exponential function. Determine the domain, range, and horizontal asymptote. $$f(x)=e^{x}+2$$
Step-by-Step Solution
Verified Answer
Domain: (-∞, ∞), Range: (2, ∞), Horizontal asymptote: y = 2.
1Step 1: Understanding the Function
The function given is an exponential function: \[ f(x) = e^{x} + 2 \] This function is a transformation of the basic exponential function \( e^x \), which means the graph should be shifted vertically.
2Step 2: Identify Vertical Shift
The function \( f(x) = e^{x} + 2 \) indicates a **vertical shift** upwards by 2 units from the parent function \( e^x \). This transformation affects the range and horizontal asymptote.
3Step 3: Determine Domain
The domain of any exponential function is all real numbers, since you can substitute any real number into \( x \) without any restrictions. Therefore, the domain of \( f(x) = e^x + 2 \) is \[ (-\infty, \infty) \]
4Step 4: Determine Range
Since the function is shifted up by 2 units, the smallest value \( e^x \) can take is 2 when \( e^x \) approaches zero. Thus, the range of \( f(x) = e^x + 2 \) is:\[ (2, \infty) \]
5Step 5: Identify Horizontal Asymptote
In the original function \( e^x \), the horizontal asymptote is \( y = 0 \). With the vertical shift of +2, the new horizontal asymptote is now:\[ y = 2 \]
6Step 6: Sketch the Graph
To sketch the graph of \( f(x) = e^x + 2 \):1. Start by sketching the graph of \( e^x \).2. Move the entire graph up by 2 units.3. Ensure the curve approaches but never touches the horizontal asymptote \( y = 2 \).4. Indicate the domain as all x-values and range beginning just above the horizontal asymptote at \( y = 2 \).
Key Concepts
Domain and RangeVertical ShiftHorizontal Asymptote
Domain and Range
The domain of an exponential function, such as our function \(f(x) = e^x + 2\), includes all real numbers. This means you can plug any value of \(x\) into the function without restriction, and it will produce a corresponding \(y\) value.
- Domain: \((-\infty, \infty)\)
- Range: \((2, \infty)\)
Vertical Shift
A vertical shift occurs when the entire graph of a function moves up or down by a certain number of units. For the function \(f(x) = e^x + 2\), the graph of the basic exponential function \(e^x\) is shifted upwards by 2 units.
- This transformation is uniform across all x-values.
- The shape of the exponential curve remains unchanged but is repositioned vertically.
Horizontal Asymptote
A horizontal asymptote in a function is a horizontal line that the graph approaches as \(x\) goes to positive or negative infinity. In simpler terms, it's the \(y\) value that the outputs get closer to but never quite reach.For the base function \(e^x\), the horizontal asymptote is \(y = 0\). This means as \(x\) becomes very large or very small, \(e^x\) gets closer and closer to 0 but never actually reaches it.In the function \(f(x) = e^x + 2\), the vertical shift has moved this horizontal asymptote up by 2 units:
- Horizontal Asymptote: \(y = 2\)
Other exercises in this chapter
Problem 232
For the following exercises, evaluate the given exponential functions as indicated, accurate to two significant digits after the decimal. $$f(x)=e^{x} \text { a
View solution Problem 232
Evaluate the given exponential functions as indicated, accurate to two significant digits after the decimal. \(f(x)=e^{x}\) a. \(x=2\) b. \(x=-3.2\) c. \(x=\pi\
View solution Problem 239
Sketch the graph of the exponential function. Determine the domain, range, and horizontal asymptote. \(\quad f(x)=e^{x}+2\)
View solution Problem 240
For the following exercises, sketch the graph of the exponential function. Determine the domain, range, and horizontal asymptote. $$f(x)=-2^{x}$$
View solution