Problem 238
Question
An urn contains eight red chips, six white chips, and four blue chips. A sample of size 3 is drawn without replacement. Let \(X\) denote the number of red chips in the sample and \(Y\), the number of white chips. Find an expression for \(p_{Y \mid x}(y)\).
Step-by-Step Solution
Verified Answer
The expression for \(p_{Y \mid x}(y)\) can be calculated as \(\frac{\binom{6}{y} \binom{18-x-y}{3-x-y}}{\binom{18-x}{3-x}}\).
1Step 1: Recognize the type of problem
This problem is a conditional probability calculation in a multinomial setting. A multinomial setting is where each experiment or trial could have more than two possible outcomes, and each outcome may be categorized into one of multiple categories. One may identify this setting by recognizing that there are more than two types of chips in the urn and that a sample is drawn without replacement, affecting the probabilities of subsequent draws.
2Step 2: Understand the variables
Here, \(X\) and \(Y\) are the random variables denoting the number of red chips and white chips drawn, respectively. \(p_{Y \mid x}(y)\) is a conditional probability, asking what the probability of drawing \(y\) white chips is given that \(x\) red chips have already been drawn.
3Step 3: Calculate the total number of chips
In total, the urn contains 18 chips (8 red, 6 white, 4 blue). This total figure will be necessary to determine the number of ways to choose remaining chips after certain chips have been drawn.
4Step 4: Calculate the conditional probability using combinations
The expression for \(p_{Y \mid x}(y)\) can be calculated as the number of ways to draw \(y\) white chips out of the available pool of chips, divided by the total number of ways to draw the remaining chips after \(x\) red chips have been drawn. This can be represented as \(\frac{\binom{6}{y} \binom{18-x-y}{3-x-y}}{\binom{18-x}{3-x}}\), where \(\binom{n}{k}\) is the binomial coefficient 'n choose k', representing the number of ways to draw \(k\) objects from a pool of \(n\) without order mattering.
Key Concepts
Multinomial DistributionBinomial CoefficientCombinatorial Analysis
Multinomial Distribution
A multinomial distribution is an extension of the binomial distribution. It applies to scenarios where each trial can result in more than two possible outcomes. Think about drawing different colored chips from an urn, as in our exercise. You're not just checking if you draw a chip or not; instead, you have multiple categories: red, white, and blue chips.
In this type of distribution:
In this type of distribution:
- Each trial is independent.
- There can be more than two outcomes.
- The category probabilities add up to 1.
Binomial Coefficient
The binomial coefficient, often read as 'n choose k', is used to determine the number of ways to choose 'k' elements from a set of 'n' elements, without considering the order of the elements. It is written mathematically as \(\binom{n}{k}\) which translates to \[\frac{n!}{k!(n-k)!}.\]
In our exercise, this concept helps us calculate how many different ways we can choose a specific number of white or red chips. For instance, \(\binom{6}{y}\) tells us how many ways we can select 'y' white chips out of 6 available white chips. The binomial coefficient is a fundamental tool in combinatorial calculations because it simplifies the process of counting combinations in probability problems.
The real power of the binomial coefficient comes when applied to problems that involve conditional settings, like in our exercise where determining \(\binom{18-x-y}{3-x-y}\) helps find how the remaining chips can be picked once some have already been chosen.
In our exercise, this concept helps us calculate how many different ways we can choose a specific number of white or red chips. For instance, \(\binom{6}{y}\) tells us how many ways we can select 'y' white chips out of 6 available white chips. The binomial coefficient is a fundamental tool in combinatorial calculations because it simplifies the process of counting combinations in probability problems.
The real power of the binomial coefficient comes when applied to problems that involve conditional settings, like in our exercise where determining \(\binom{18-x-y}{3-x-y}\) helps find how the remaining chips can be picked once some have already been chosen.
Combinatorial Analysis
Combinatorial analysis is a strategy in mathematics for counting, arranging, and analyzing arrangements of a set. It provides the mathematical background needed to solve problems involving selection and arrangement possibilities, like those found in our chip-drawing exercise.
When we deal with problems involving different arrangements of items—such as determining how to choose 3 chips from a collection of 18—combinatorial analysis becomes essential. It helps break down the complicated task of counting into more manageable parts using principles such as permutations and combinations.
This kind of analysis allows you to:
When we deal with problems involving different arrangements of items—such as determining how to choose 3 chips from a collection of 18—combinatorial analysis becomes essential. It helps break down the complicated task of counting into more manageable parts using principles such as permutations and combinations.
This kind of analysis allows you to:
- Calculate total possible outcomes.
- Determine probabilities for specific events.
- Solve conditional probability questions efficiently by narrowing down possible scenarios.
Other exercises in this chapter
Problem 236
Suppose \(X\) and \(Y\) have the joint pdf \(p_{X, Y}(x, y)=\) \(\frac{x+y+x y}{21}\) for the points \((1,1),(1,2),(2,1),(2,2)\), where \(X\) denotes a "message
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Suppose a die is rolled six times. Let \(X\) be the total number of 4 's that occur and let \(Y\) be the number of 4 's in the first two tosses. Find \(p_{Y \mi
View solution Problem 239
Five cards are dealt from a standard poker deck. Let \(X\) be the number of aces received, and \(Y\) the number of kings. Compute \(P(X=2 \mid Y=2)\).
View solution Problem 240
Given that two discrete random variables \(X\) and \(Y\) follow the joint pdf \(p_{X, Y}(x, y)=k(x+y)\), for \(x=1,2,3\) and \(y=1,2,3\), (a) Find \(k\). (b) Ev
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