Problem 234
Question
A 12 -in. spring is stretched to 15 in. by a force of \(75 \mathrm{lb}\). What is the spring constant?
Step-by-Step Solution
Verified Answer
The spring constant is 25 lb/in.
1Step 1: Understand Hooke's Law
The exercise involves a spring, so we need to use Hooke's Law. Hooke's Law is given by the equation \( F = k \cdot x \), where \( F \) is the force applied to the spring, \( k \) is the spring constant, and \( x \) is the amount of stretch (or compression) from the spring's original length.
2Step 2: Identify Given Values
We know the original length of the spring is 12 inches, and it is stretched to 15 inches. The force applied is 75 pounds. This means the spring is stretched by \( x = 15 - 12 = 3 \) inches.
3Step 3: Convert Units if Necessary
Ensure that all units are compatible. Since the force is in pounds and the stretch is in inches, there is no need for unit conversion here. We can directly substitute these values into Hooke's Law equation.
4Step 4: Rearrange Hooke's Law to Solve for the Spring Constant
Rearrange the formula \( F = k \cdot x \) to solve for the spring constant: \( k = \frac{F}{x} \).
5Step 5: Substitute Values
Substitute the known values into the equation: \( k = \frac{75}{3} \).
6Step 6: Calculate the Spring Constant
Perform the division: \( k = 25 \). Thus, the spring constant is 25 pounds per inch.
Key Concepts
Understanding the Spring ConstantForce and Displacement in SpringsUnit Conversion ImportanceEffective Physics Problem Solving
Understanding the Spring Constant
The spring constant, often denoted as \( k \), is a crucial concept when analyzing the behavior of springs. It describes the stiffness of a spring.
- A higher spring constant indicates that a spring is stiffer and requires more force to stretch or compress it by a certain amount.
- A lower spring constant means the spring is more flexible.
Force and Displacement in Springs
In Hooke's Law, force \( F \) and displacement \( x \) have a direct relationship. Force is measured in pounds (lb) or newtons (N), while displacement refers to how much the spring is stretched or compressed from its original length, often measured in meters (m) or inches (in).When solving problems involving springs:
- Identify the initial and final lengths of the spring to calculate displacement: \( x = \text{final length} - \text{original length} \).
- Ensure that force is exerted in a manner to stretch or compress the spring.
Unit Conversion Importance
Unit consistency is crucial when applying physical formulas like Hooke's Law. Inconsistent units can lead to incorrect calculations and results.
For this particular exercise:
- Check that all measurements are in compatible units before performing calculations. Here, no conversion was needed because both the force and the displacement used pounds and inches respectively.
- When dealing with mixed units, such as converting inches to meters or pounds to newtons, use known conversion factors. For instance, 1 inch is 0.0254 meters.
Effective Physics Problem Solving
Approaching physics problems systematically can simplify complex problems. Here's a structured approach:
1. **Understand the Problem:** Identify the physical laws that apply. Here, Hooke's Law was crucial.
2. **Extract Information:** Gather all known values and what needs to be found. Translate word problems into variables.
3. **Check Units:** Ensure all measurements are in compatible units to prevent calculation errors.
4. **Apply Mathematical Models:** Use relevant formulas to solve for the unknowns. Rearrange equations if necessary to isolate the desired variable.
5. **Perform Calculations:** Carefully substitute values, keeping track of each step.
6. **Verify Results:** Double-check calculations and consider if results make sense contextually.
This step-by-step method can be adapted to tackle a wide range of physics exercises, ensuring clarity and precision.
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Problem 233
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