Problem 233
Question
\(\mathrm{pH}\) of \(10^{-10} \mathrm{M} \mathrm{HCl}\) solution at \(25^{\circ} \mathrm{C}\) is approximately
Step-by-Step Solution
Verified Answer
The pH is approximately 7.
1Step 1: Understanding the problem
We need to determine the pH of a very dilute HCl solution, specifically a solution with a concentration of \(10^{-10} \text{ M}\) at \(25^{\circ} \text{C}\). Since this concentration is extremely low, we must take the \[H^+\] from water into consideration.
2Step 2: Water contribution
Water autoionizes to produce hydrogen ions \[H^+\] and hydroxide ions \text{OH}^-\. At \(25^{\circ} \text{C},\) the concentration of hydrogen ions from water is \(10^{-7} \text{ M}.\)
3Step 3: Combining contributions
The effective concentration of hydrogen ions \([H^+]_{\text{eff}}\) is the sum of contributions from both the water itself and the acid: \[ [H^+]_{\text{eff}} = [H^+]_{\text{water}} + [HCl] = 10^{-7} \text{ M} + 10^{-10} \text{ M}\] which simplifies to \([H^+]_{\text{eff}} \approx 10^{-7} \text{ M}\) since \(10^{-10} \text{ M}\) is negligible.
4Step 4: Calculating pH
Since the effective concentration of hydrogen ions \([H^+]_{\text{eff}}\) is \(10^{-7} \text{ M},\) the pH is calculated using the formula: \[ \text{pH} = -\log_{10}([H^+]_{\text{eff}}) = -\log_{10}(10^{-7}) = 7.\]
Key Concepts
dilute solutionwater autoionizationhydrogen ion concentrationhydrochloric acid dilution
dilute solution
A dilute solution is defined as one with a relatively low concentration of solute compared to the solvent. In our exercise, we are examining a dilute solution of hydrochloric acid (
(HCl)
), with a concentration of just
(10^{-10} ext{ M}).
When solutions are this diluted, certain unique properties emerge because the impact of the solute molecules is minimal.
- The behavior of dilute solutions can significantly differ from more concentrated solutions.
- In such dilute solutions, additional factors, such as the self-ionization of water, become significant.
- The interaction between solute and solvent is often less impactful, leading to properties of the solvent playing a more dominant role.
water autoionization
Water autoionization is a natural process where water (
(H_2O)
) molecules spontaneously split into hydrogen ions (
(H^+)
) and hydroxide ions (
(OH^-)
). This is an essential process to consider, especially in very dilute solutions like the one we're looking at with
(10^{-10} ext{ M})
HCl.
- Even without any added solute, water itself can dissociate to produce ions.
- At (25^{ ext{o}} ext{C}), the concentration of (H^+) produced by water is around (10^{-7} ext{ M}).
- This means that in very dilute solutions, the quantity of hydrogen ions from water can outnumber those from the acid.
hydrogen ion concentration
Hydrogen ion concentration in a solution is crucial to determining the pH, which measures how acidic or basic a solution is. For solutions at room temperature (
(25^{ ext{o}} ext{C})),
the neutrality point is around a
([H^+] = 10^{-7} ext{ M}).
In the context of this exercise:
- The initial concentration of (HCl) is negligible at (10^{-10} ext{ M}).
- Given the chemical environment, it's the hydrogen ions from water that primarily define the ([H^+]).
- The effective concentration of ([H^+]_{ ext{eff}}) used for pH calculation thus essentially remains heavily influenced by water autoionization.
hydrochloric acid dilution
Hydrochloric acid (HCl) is known as a strong acid, which means it dissociates completely into its ions in solution. However, when it's extremely dilute, as in this exercise with
(10^{-10} ext{ M}),
its behavior can be surprising.
- Despite being a strong acid, in highly dilute concentrations, its contribution of (H^+) ions is minimal.
- The stronger interaction is that of water itself, which generates more (H^+) ions through autoionization.
- Therefore, it's important for students to recognize that the dissociation power of strong acids like HCl can be overshadowed at extreme dilution.
Other exercises in this chapter
Problem 227
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A certain buffer solution contains equal conc. of \(\mathrm{X}^{-}\) and HX. The \(\mathrm{K}\) of \(\mathrm{HX}\) is \(10^{-7} .\) The \(\mathrm{pH}\) of the b
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