Problem 23
Question
Write the structural formula of 4-chloro-2-pentene.
Step-by-Step Solution
Verified Answer
The structure is: \( \text{CH}_3-\text{CH}=\text{CH}-\text{CH}(-\text{Cl})-\text{CH}_3 \).
1Step 1: Identify the Base Hydrocarbon
First, identify the base hydrocarbon – pentene, which is an alkene with five carbon atoms and a double bond. Since 'pent' refers to five carbon atoms and 'ene' refers to a double bond, the base structure is a five-carbon chain.
2Step 2: Locate the Double Bond
Determine the position of the double bond from the name '2-pentene'. Here, '2' indicates that the double bond starts at the second carbon atom. So, the double bond is between the second and third carbon atoms in the chain.
3Step 3: Add the Substituent
Add the chlorine atom to the structure at the position indicated – '4-chloro'. Thus, attach the chlorine atom to the fourth carbon in the pentene chain.
4Step 4: Draw the Structural Formula
Draw the full structural formula by placing the carbon chain with the double bond positioned from the second carbon, and attach the chlorine to the fourth carbon. The resulting structure will show the positions of hydrogen atoms to satisfy the carbon valences: \[ \text{CH}_3-\text{CH}=\text{CH}-\text{CH}(-\text{Cl})-\text{CH}_3 \].
Key Concepts
Hydrocarbon ChainsStructural FormulasDouble Bonds
Hydrocarbon Chains
Hydrocarbon chains are the backbone of organic chemistry. They consist of carbon atoms linked together in various configurations, with hydrogen atoms attached to balance the carbon valences. At their core, hydrocarbons can be classified into several groups based on the types of bonds and the shapes of the chains. Here are some critical points to understand about hydrocarbon chains:
- Alkanes: These are saturated hydrocarbons with only single bonds. They follow a general formula of \(C_nH_{2n+2}\).
- Alkenes: Unsaturated hydrocarbons that contain at least one double bond, like pentene. Their general formula is \(C_nH_{2n}\).
- Alkynes: These are unsaturated hydrocarbons with one or more triple bonds, with the formula \(C_nH_{2n-2}\).
- Cyclic Hydrocarbons: Carbon chains that form ring structures are called cyclic hydrocarbons and can include any of the above bond types.
Structural Formulas
Structural formulas are visual representations of molecules, showing how atoms are arranged and bonded. This map helps chemists understand and predict how molecules will react.
To build the structural formula, follow these steps:
To build the structural formula, follow these steps:
- Select the Carbon Skeleton: Identify the main carbon chain (e.g., the pentene in our exercise).
- Identify Key Bonds: Mark any significant bonds, like double bonds, that need highlighting on the skeletal structure.
- Add Substituents: Place additional atoms or groups that branch off from the main carbon chain, like the chlorine in '4-chloro'.
- Complete with Hydrogen Atoms: Fill in any remaining valences with hydrogen atoms to complete the stable configuration of each carbon atom.
Double Bonds
Double bonds are a defining feature of alkenes. In hydrocarbon chains, they consist of two pairs of shared electrons between two carbon atoms. The presence of a double bond affects both the physical and chemical properties of a molecule.
- Structure and Geometry: Double bonds create a planar configuration, restricting the rotation around the bond axis. This gives each carbon atom in the bond a sp2 hybridization, leading to a 120-degree bond angle.
- Reactivity: Double bonds are points of higher reactivity compared to single bonds. They can easily participate in reactions such as addition reactions, where other atoms or groups add across the double bond.
- Stability: While double bonds signal unsaturation, making the molecule less stable than single-bonded variants, they also provide essential reactive sites for chemical reactions.
Other exercises in this chapter
Problem 21
The compound 1, 2-butadiene has (a) only \(s p\) hybridized carbon atoms (b) only \(s p^{2}\) hybridized carbon atoms (c) both \(s p\) and \(s p^{2}\) hybridize
View solution Problem 22
Molecule in which the distance between the two adjacent carbon atoms is largest is (a) Ethane (b) Ethene (c) Ethyne (d) Benzene
View solution Problem 24
In an estimation of bromine by Carius method, \(1.6 \mathrm{~g}\) of an organic compound gave \(1.88 \mathrm{~g}\) of \(\mathrm{AgBr}\). The mass percentage of
View solution Problem 25
The valence atomic orbitals on carbon in silver acetylide is .............. hybridized.
View solution