Problem 23
Question
Would you expect the \(S_{\mathrm{N}} 2\) reaction of sodium cyanide with methyl bromide to be faster, slower, or about the same with \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{~S}=\mathrm{O}\) or ethanol as solvent? Explain.
Step-by-Step Solution
Verified Answer
The reaction is faster in \((\text{CH}_3)_2\text{SO})\) than in ethanol.
1Step 1: Understanding the Reactants and Reaction Type
In an \( S_N2 \) reaction, sodium cyanide (\( ext{NaCN} \)) acts as the nucleophile and attacks methyl bromide (\( ext{CH}_3 ext{Br} \)) resulting in the substitution of the bromide ion with a cyanide group.
2Step 2: Role of Solvent in Reaction Rate
The solvent can influence the reaction rate. For \( S_N2 \) reactions, polar aprotic solvents are usually ideal because they do not solvate anions effectively, allowing the nucleophile to react more freely.
3Step 3: Solvent Evaluation - Dimethyl Sulfoxide (\(( ext{CH}_3)_2 ext{SO})\)
Dimethyl sulfoxide (\(( ext{CH}_3)_2 ext{SO})\) is a polar aprotic solvent. It does not solvate ions strongly, making it ideal for \( S_N2 \) reactions as it enhances the nucleophilicity of \( ext{CN}^- \) ions, leading to a faster reaction.
4Step 4: Solvent Evaluation - Ethanol
Ethanol is a polar protic solvent. It can solvate the \( ext{CN}^- \) ions, reducing their nucleophilicity and making them less effective in attacking the methyl group, slowing down the \( S_N2 \) reaction.
5Step 5: Comparing Reaction Speeds by Solvent
Given that \(( ext{CH}_3)_2 ext{SO} \) does not solvate the \( ext{CN}^- \) anion as strongly as ethanol does, the \( S_N2 \) reaction with dimethyl sulfoxide as the solvent will be faster compared to ethanol.
Key Concepts
NucleophilePolar Aprotic SolventReaction Rate
Nucleophile
A nucleophile is a chemical species that donates an electron pair to form a chemical bond in reaction processes, such as the S_N2 reaction. Nucleophiles are important in substitution reactions because they seek positive or electron-deficient centers to donate their electrons. In the given exercise, sodium cyanide (\( \text{NaCN} \)) acts as the nucleophile. It holds a negatively charged cyanide ion (\( \text{CN}^- \)), which is eager to attack the slightly positive carbon in methyl bromide (\( \text{CH}_3\text{Br} \)). This attack involves the nucleophile pushing out the leaving group, which in this case is the bromide ion (\( \text{Br}^- \)). Key characteristics of nucleophiles include:
- An ability to donate electrons
- Presence of lone pairs or pi electrons
- Higher reactivity with softer, less hindered electrophiles
Polar Aprotic Solvent
Solvents have a critical influence on the S_N2 reaction mechanism, primarily through their interaction with the nucleophile. A polar aprotic solvent is particularly effective in these reactions because it does not form hydrogen bonds with anions. Aprotic solvents like dimethyl sulfoxide (\((\text{CH}_3)_2\text{SO}\)), mentioned in the exercise, are polar enough to dissolve the nucleophile but do not stabilize the charged species, allowing them to remain potent. Features of polar aprotic solvents include:
- High polarity to dissolve reactants
- Lack of hydrogen-bonding capacity with nucleophiles
- Ability to increase the reaction rate by not hindering nucleophiles
Reaction Rate
The rate of an S_N2 reaction depends heavily on the nature of the nucleophile, the solvent used, and the structure of the substrate. In the given S_N2 reaction involving sodium cyanide and methyl bromide, the speed at which these reactants convert to products is a direct reflection of these factors. The important determinants of an S_N2 reaction rate are:
- Strength and concentration of the nucleophile
- Polar aprotic solvents providing less hindrance to nucleophiles
- The structure and size of the electrophile or substrate
Other exercises in this chapter
Problem 21
Explain each of the following observations: a. Methyl sulfide \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{~S}\) reacts with \(\mathrm{C}_{6} \mathrm{H}_{5} \math
View solution Problem 22
Classify the following solvents according to effectiveness for solvation of (i) cations and (ii) anions: a. 2 -propanone, \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\)
View solution Problem 24
An alternative mechanism for \(E 2\) elimination is the following: $$ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{Cl}+\mathrm{OH}^{\ominus} \stackrel{\text { fast }
View solution Problem 25
Write equations and mechanisms for all the products that might reasonably be expected from the reaction of 2 chlorobutane with a solution of potassium hydroxide
View solution