Problem 23
Question
Which one of the following ions exhibits colour in aqueous solution? (a) \(\mathrm{Ti}^{4+}\) (b) \(\mathrm{Zn}^{2+}\) (c) \(\mathrm{Ni}^{2+}\) (d) \(\mathrm{Sc}^{3+}\)
Step-by-Step Solution
Verified Answer
(c) }{2+} is colored due to unpaired electrons.
1Step 1: Identify Electron Configuration
To determine whether an ion exhibits color in aqueous solution, check its electron configuration. Transition metal ions with unpaired electrons are typically colored due to d-d transitions. Let's find the electron configurations for the ions.
- 0^{4+}": Electron configuration ends in [Ar] (no d-electrons).
- }{2+}": Electron configuration ends in [Ar]3d^{10} (no unpaired electrons).
- }{2+}": Electron configuration ends in [Ar]3d^{8} (unpaired electrons present).
- }{3+}": Electron configuration ends in [Ar] (no d-electrons).
2Step 2: Determine Color Presence
Transition metal ions exhibit color if they have unpaired d-electrons. From the electron configurations:
- ^4+}{2+}}{3+}}{2+}}{8} configuration, indicating unpaired electrons, which are needed for color.
3Step 3: Select the Ion with Color
Based on the analysis, }{2+} has unpaired electrons, making it the only ion that exhibits color. Therefore, }{2+} is colored in aqueous solution.
Key Concepts
Electron ConfigurationTransition Metal Ionsd-d Transitions
Electron Configuration
Understanding electron configuration is key to knowing why certain ions display color in solution. Electrons are arranged in an atom in energy levels or shells, with each shell further divided into subshells and orbitals. Notably, the d-block elements, known as transition metals, can have partially filled d orbitals. When these d orbitals contain electrons, they can interact with light, leading to color.
For ions:
- Check their electron configurations by writing them out from their atomic numbers.
- Remove electrons according to their charge (typically starting from the outermost shell first), which usually means losing s orbital electrons before d electrons.
- ext{ ext{Ti}^{4+}}: No d electrons (similar electronic configuration to Argon),
- ext{ ext{Zn}^{2+}}: Full d orbital (3d^{10}),
- ext{ ext{Ni}^{2+}}: Partially filled d orbitals (3d^{8}),
- ext{ ext{Sc}^{3+}}: No d electrons (similar electronic configuration to Argon),
Transition Metal Ions
Transition metal ions are fascinating due to their unique electronic structures. They are elements found in the d-block of the periodic table, specifically from groups 3 to 12. These metals often form colored compounds, especially in ion form, due to their partially filled d orbitals. The presence of unpaired d electrons is crucial for their colorful properties.
When we consider ions such as
- ext{Fe}^{2+}
- ext{Cu}^{2+}
- ext{Co}^{2+}
- The electrons can absorb visible light energy, transitioning between different d-orbital energy levels.
- This absorbed energy can change which light is reflected, making solutions appear colored.
d-d Transitions
d-d transitions are a fascinating phenomenon explaining the colors seen in transition metal ions. A d-d transition occurs when an electron jumps from a lower energy d orbital to a higher energy d orbital.
Here's how it works:
- The electrons in the d orbitals of transition metals absorb specific wavelengths of light to transition to a higher energy level.
- When specific wavelengths are absorbed, the complementary colors are reflected, and that's the color we see.
- This transition is only possible with the presence of unpaired d electrons, a trait specific to many transition metals.
- When light hits a transition metal ion in a solution, electronic transitions between d orbitals can occur if conditions are right (unpaired electrons present).
- The absorbed part of the spectrum determines the color appearing to our eyes.
Other exercises in this chapter
Problem 21
Iron loses its magnetic property at (a) melting point (b) curie point (c) \(1000 \mathrm{~K}\) (d) boiling point
View solution Problem 22
In the extraction of zinc, the formation of blue flame is due to the burning of (a) \(\bar{C}\) (b) \(\mathrm{CO}\) (c) \(\mathrm{Zn}\) (d) \(\mathrm{ZnO}\)
View solution Problem 24
The number of un-paired electrons in \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}\right]\) \(\mathrm{SO}_{4}\) (a) 1 (b) 2 (c) 3 (d
View solution Problem 25
Which one of the following ions is colourless in its aqueous solution? (a) \(\mathrm{Ti}^{3+}\) (b) \(\mathrm{Cu}^{2+}\) (c) \(\mathrm{Ni}^{2+}\) (d) \(\mathrm{
View solution