Problem 23
Question
Which among the following compounds will give mixture of two ketones on hydration with \(\mathrm{HOH} / \mathrm{H}_{2} \mathrm{SO}_{4} / \mathrm{HgSO}_{4}\) : (a) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{C}=\mathrm{C}-\mathrm{CH}_{3}\) b) \(\mathrm{CH}_{3}-\mathrm{C}=\mathrm{C}-\mathrm{CH}_{3}\) (c) \(\mathrm{C}_{2} \mathrm{H}_{5}-\mathrm{C}=\mathrm{C}-\mathrm{C}_{2} \mathrm{H}_{5}\) d) All of these
Step-by-Step Solution
Verified Answer
Compound (a) will give a mixture of two ketones on hydration.
1Step 1: Understanding the Reaction
The reaction involves hydration of alkynes in the presence of dilute sulfuric acid (\(\mathrm{H}_2\mathrm{SO}_4\)) with mercuric sulfate (\(\mathrm{HgSO}_4\)) as a catalyst. This typically results in the Markovnikov addition of water, forming enols that tautomerize into ketones.
2Step 2: Analyzing Compound (a)
For compound \((a)\), \(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{C}\equiv\mathrm{C}-\mathrm{CH}_3\), hydration occurs at the internal triple bond, yielding two possible keto tautomer products: 2-pentanone and 3-pentanone.
3Step 3: Analyzing Compound (b)
In compound \((b)\), \(\mathrm{CH}_3-\mathrm{C}\equiv\mathrm{C}-\mathrm{CH}_3\), hydration of the internal alkyne results first in an enol, which tautomerizes into a single ketone: acetone.
4Step 4: Analyzing Compound (c)
For compound \((c)\), \(\mathrm{C}_2\mathrm{H}_5-\mathrm{C}\equiv\mathrm{C}-\mathrm{C}_2\mathrm{H}_5\), hydration also yields an enol that will tautomerize into a single ketone product: 3-pentanone.
5Step 5: Conclusion
Only compound \((a)\) produces a mixture of two ketones upon hydration under the given conditions due to the potential for different tautomers, unlike \((b)\) and \((c)\) that produce only one ketone each.
Key Concepts
Markovnikov AdditionTautomerizationKetone FormationOrganic Chemistry Reactions
Markovnikov Addition
When discussing the hydration of alkynes, a key principle is Markovnikov addition. This rule guides how different atoms or groups attach to a carbon-carbon multiple bond. In our scenario, an alkyne is the starting material. The presence of \(\mathrm{H}_2\mathrm{SO}_4\) with \(\mathrm{HgSO}_4\) as a catalyst helps in adding water across the triple bond. During this process, the hydrogen atom in water preferentially bonds to the carbon already bearing the greater number of hydrogen atoms. This results in an intermediate enol, a compound with a hydroxyl group bonded to a double-bonded carbon atom.
Ultimately, the hydration process leads to the formation of a more stable ketone due to the tautomerization of the initial enol product.
Ultimately, the hydration process leads to the formation of a more stable ketone due to the tautomerization of the initial enol product.
Tautomerization
Tautomerization is an essential mechanism in organic chemistry reactions, particularly in alkyne hydration. The enol formed through Markovnikov addition is not very stable. As a result, it undergoes a process called tautomerization. This is a form of isomerization where the enol converts into its more stable form, a ketone. The mechanism involves a series of proton transfers, where the hydroxyl hydrogen shifts to the neighboring carbon, and the double bond shifts to create a carbonyl group (C=O).
- The original OH group transforms into a carbonyl group adjacent to the double bond.
- The enol-to-ketone shift is energetic-saving, making the ketone the predominant product.
Ketone Formation
In hydration reactions of alkynes, the end goal is to form a ketone. This chemical species contains a carbonyl group (C=O) bonded to two carbon-containing groups. The significance of ketone formation from alkynes cannot be understated. It is a straightforward method of converting simple molecules into more versatile and reactive species.
Upon hydration, many alkynes may initially form different enols. However, through the tautomerization process, these enols eventually convert to ketones.
Upon hydration, many alkynes may initially form different enols. However, through the tautomerization process, these enols eventually convert to ketones.
- Ketones serve as vital intermediates in organic synthesis.
- The transformation often results in fewer steps with high efficiency.
Organic Chemistry Reactions
Organic chemistry reactions, such as the hydration of alkynes, are central to understanding how various chemical transformations occur. These reactions involve breaking and forming bonds to convert reactant molecules into more useful products. The hydration of alkynes demonstrates several key principles:
- Reaction conditions: The use of \(\mathrm{H}_2\mathrm{SO}_4\) and \(\mathrm{HgSO}_4\) creates an environment conducive for water addition.
- Reactant structure: Alkynes have unique triple bonds that, when activated, allow for rich chemical transformations.
- Mechanistic pathways: Processes like Markovnikov addition and tautomerization illustrate the intricacies of reaction mechanisms.
Other exercises in this chapter
Problem 21
The dehydration of 2 -methylbutanol with concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}\) produces (a) 2-methylbutene as the major product (b) 2 -methylbut-2-ene
View solution Problem 22
Which of the following will give two isomeric monochloro derivatives ? (a) 2, 3-Dimethylbutane (b) \(n\)-Hexane (c) Isopentane (d) Ethane
View solution Problem 24
Calcium carbide reacts with water to produce (a) Ethane (b) Methane (c) Ethylene (d) Acetylene
View solution Problem 27
The product of acid catalyzed hydration of 2 -phenyl propene is (a) 3-pheny12-propanol (b) 1-phenyl-2-propanol (c) 2-phenyl-2-propanol (d) 2-phenyl-1-propanol
View solution