Problem 23
Question
What volume of \(0.350 \mathrm{M} \mathrm{CaF}_{2}\) solution is required to obtain \(0.00875\) mole of \(\mathrm{CaF}_{2} ?\)
Step-by-Step Solution
Verified Answer
The volume of the 0.350 M CaF₂ solution required to obtain 0.00875 moles of CaF₂ is 0.025 liters or 25 mL.
1Step 1: Identify the given information
We are given:
- Molarity (M) of CaF₂ solution: 0.350 M
- Moles of CaF₂: 0.00875
Our goal is to find the volume of the solution (in liters) containing the given amount of CaF₂.
2Step 2: Use the molarity equation to find the volume
We'll use the formula:
Molarity (M) = moles of solute / volume of solution (L)
Rearrange the formula to solve for the volume:
Volume of solution (L) = moles of solute / Molarity (M)
Now, plug the given values into the equation:
Volume of solution (L) = \( \frac{0.00875\text{ moles of CaF}_{2}}{0.350\text{ M}} \)
3Step 3: Calculate the volume of the solution
Divide the given values:
Volume of solution (L) = \( \frac{0.00875}{0.350} \) = 0.025 L
Therefore, 0.025 liters (25 mL) of the 0.350 M CaF₂ solution is required to obtain 0.00875 moles of CaF₂.
Key Concepts
Moles of soluteVolume of solutionConcentration calculation
Moles of solute
Moles of solute are the actual amount of substance we have in terms of the number of molecules or atoms. It is a fundamental concept in chemistry that allows us to count particles in a given mass and connect this mass to the macroscopic world of solutions. The term "mole" represents Avogadro's number, which is approximately 6.022 x 10²³ particles (atoms, molecules, ions, etc.).
To calculate moles, we typically use the formula:
In our exercise, we were provided with 0.00875 moles of CaF₂, which is directly used in the molarity equation to find the required volume of the solution. This helps identify the source quantity of the solute in the chemical process outlined.
To calculate moles, we typically use the formula:
- \( ext{moles} = \frac{ ext{mass}}{ ext{molar mass}} \)
In our exercise, we were provided with 0.00875 moles of CaF₂, which is directly used in the molarity equation to find the required volume of the solution. This helps identify the source quantity of the solute in the chemical process outlined.
Volume of solution
The volume of a solution refers to the overall space that the solute plus solvent occupy together. This could be expressed in liters, milliliters, or any other appropriate unit of volume measurement. Calculating volumes is critical when it’s necessary to dilute or concentrate solutions to meet specific requirements.
When solving for volume, knowing the moles of solute and the molarity of the solution lets us determine how much of the total solution we need.
In practical applications, understanding volume is important in laboratories, medicine, and industries where solution preparation is common.
When solving for volume, knowing the moles of solute and the molarity of the solution lets us determine how much of the total solution we need.
- The equation: \( ext{Volume of solution (L)} = \frac{ ext{moles of solute}}{ ext{Molarity (M)}} \), allows us to calculate volume.
In practical applications, understanding volume is important in laboratories, medicine, and industries where solution preparation is common.
Concentration calculation
Concentration is a measure of how much solute is present in a given amount of solution. This is often represented by molarity in the context of chemical solutions. Molarity (M) quantifies the concentration by expressing the moles of solute per liter of solution.
The molarity formula is:
In our specific problem, this formula helped us determine the volume of 0.350 M CaF₂ solution needed to get a certain number of moles. By calculating concentration, we ensure the solution has the desired chemical properties and behavior, which is critical in any scientific or industrial activity involving solutions.
The molarity formula is:
- \( ext{Molarity (M)} = \frac{ ext{moles of solute}}{ ext{volume of solution (L)}} \)
In our specific problem, this formula helped us determine the volume of 0.350 M CaF₂ solution needed to get a certain number of moles. By calculating concentration, we ensure the solution has the desired chemical properties and behavior, which is critical in any scientific or industrial activity involving solutions.
Other exercises in this chapter
Problem 20
Gasohol is a solution of gasoline and ethanol. Every liter of gasohol contains \(90.0 \mathrm{~mL}\) of ethanol dissolved in gasoline. Characterize the solute c
View solution Problem 22
How many moles of \(\mathrm{CaF}_{2}\) are there in \(25.0 \mathrm{~mL}\) of \(0.350 \mathrm{M} \mathrm{CaF}_{2}(a q) ?\)
View solution Problem 24
How many moles of glucose are there in \(255.0 \mathrm{~mL}\) of a \(0.998 \mathrm{M}\) solution of glucose?
View solution Problem 25
What volume of \(0.350 \mathrm{M} \mathrm{BaCl}_{2}\) solution is required to obtain \(0.500\) mole of \(\mathrm{BaCl}_{2}\) ?
View solution