Problem 23
Question
Using Properties of Logarithms In Exercises \(21-36\) , find the exact value of the logarithmic expression without using a calculator. (If this is not possible, then state the reason.) $$\log _{2} \sqrt[4]{8}$$
Step-by-Step Solution
Verified Answer
The exact value is \(3/4\).
1Step 1: Rewrite Fourth Root as Fractional Power
The fourth root of 8 can be rewritten as a power with a fractional exponent. This would give \(\log_2 (8^{1/4})\).
2Step 2: Implement Property of Logarithms
By the power rule for logarithms, which states \(\log_b{a^k} = k\log_b{a}\), this expression can be written as \(1/4 \times \log_2 8\).
3Step 3: Evaluate Logarithm
The log base 2 of 8 is 3 because \(2^3 = 8\). Thus, this evaluates to \(1/4 \times 3\).
4Step 4: Simplify Fraction
Simplify \(1/4 \times 3\) to get the final answer.
Key Concepts
Properties of LogarithmsPower Rule for LogarithmsFractional ExponentLogarithmic Expressions
Properties of Logarithms
Logarithms have several useful properties that make them a powerful tool in mathematics. These properties allow us to simplify and evaluate logarithmic expressions more easily. One of the key properties is the product property, which states that the logarithm of a product is the sum of the logarithms of the factors:
- \( \log_b{(MN)} = \log_b{M} + \log_b{N} \)
- \( \log_b{ \left( \frac{M}{N} \right) } = \log_b{M} - \log_b{N} \)
- \( \log_b{a^k} = k\log_b{a} \)
Power Rule for Logarithms
The power rule for logarithms is a convenient shortcut that helps handle expressions where a term is raised to a power. According to this rule, when you have a logarithm of a power, such as \( \log_b{a^k} \), it can be simplified by bringing the exponent \( k \) in front of the logarithm:
In the exercise given, we used this rule to rewrite the expression \( \log_2{(8^{1/4})} \) as \( \frac{1}{4} \log_2{8} \). By leveraging the power rule, we reduce the complexity of solving for the logarithm, allowing us to efficiently evaluate expressions without any advanced calculation tools.
- \( \log_b{a^k} = k \log_b{a} \)
In the exercise given, we used this rule to rewrite the expression \( \log_2{(8^{1/4})} \) as \( \frac{1}{4} \log_2{8} \). By leveraging the power rule, we reduce the complexity of solving for the logarithm, allowing us to efficiently evaluate expressions without any advanced calculation tools.
Fractional Exponent
Fractional exponents are a way of expressing roots as powers, which can be crucial in simplifying logarithmic expressions. For instance, the fourth root of a number \( N \) can be written with a fractional exponent as \( N^{1/4} \).
This form is particularly useful in logarithmic calculations due to logarithmic properties.
By expressing roots as fractional exponents, we can utilize the power property of logarithms, making expressions easier to evaluate. In the context of the exercise, we took the fourth root of 8 and wrote it as \( 8^{1/4} \).
This step allowed us to apply the power rule for logarithms directly, facilitating the simplification of the entire expression. Understanding how to work with fractional exponents can greatly ease the manipulation and computation of advanced mathematical problems.
This form is particularly useful in logarithmic calculations due to logarithmic properties.
By expressing roots as fractional exponents, we can utilize the power property of logarithms, making expressions easier to evaluate. In the context of the exercise, we took the fourth root of 8 and wrote it as \( 8^{1/4} \).
This step allowed us to apply the power rule for logarithms directly, facilitating the simplification of the entire expression. Understanding how to work with fractional exponents can greatly ease the manipulation and computation of advanced mathematical problems.
Logarithmic Expressions
Logarithmic expressions can often appear daunting, but they usually break down into simpler calculations using the right properties and rules. These expressions involve the operation of taking the logarithm of a number and can be expressed in different bases.
A critical aspect is choosing the correct properties or rules to simplify or evaluate them. In this exercise involving \( \log_2 \sqrt[4]{8} \), we expressed the root as \( 8^{1/4} \), applied the power rule, and found \( \log_2 8 \) equals 3 since \( 2^3 = 8 \).
Logarithmic expressions harness the power of inverse exponentiation, allowing us to solve equations involving exponential growth or decay. By mastering the properties and rules of logarithms, one can tackle complex logarithmic operations smoothly and efficiently, turning seemingly intricate problems into straightforward tasks.
A critical aspect is choosing the correct properties or rules to simplify or evaluate them. In this exercise involving \( \log_2 \sqrt[4]{8} \), we expressed the root as \( 8^{1/4} \), applied the power rule, and found \( \log_2 8 \) equals 3 since \( 2^3 = 8 \).
Logarithmic expressions harness the power of inverse exponentiation, allowing us to solve equations involving exponential growth or decay. By mastering the properties and rules of logarithms, one can tackle complex logarithmic operations smoothly and efficiently, turning seemingly intricate problems into straightforward tasks.
Other exercises in this chapter
Problem 22
Use a calculator to evaluate \(f(x)=\log x\) at the indicated value of \(x .\) Round your result to three decimal places. \(x=\frac{1}{500}\)
View solution Problem 22
Complete the table assuming continuously compounded interest. $$ \begin{array}{llll} \text { Isotope} & \text { Half-Life } & \text { Initial Quantity } & \text
View solution Problem 23
Using the One-to-One Property In Exercises \(23-26\) use the One-to-One Property to solve the equation for \(x .\) $$3^{x+1}=27$$
View solution Problem 23
Solve the exponential equation algebraically. Approximate the result to three decimal places. \(3^{2 x}=80\)
View solution