Problem 23
Question
Use a calculator to solve the given equations. If there are no real roots, state this as the answer. \(6 R^{2}=18-7 R\)
Step-by-Step Solution
Verified Answer
The quadratic equation has two real roots: approximately 1.24 and -2.41.
1Step 1: Rearrange the Equation
First, rewrite the equation to bring all terms to one side. Start with the original equation: \[ 6R^2 = 18 - 7R \]Subtract \(18\) and add \(7R\) to both sides to get:\[ 6R^2 + 7R - 18 = 0 \]
2Step 2: Identify Quadratic Coefficients
Identify the coefficients in the quadratic equation \(6R^2 + 7R - 18 = 0\). These are:- \(a = 6\)- \(b = 7\)- \(c = -18\)
3Step 3: Use the Quadratic Formula
Use the quadratic formula \( R = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) to solve for \(R\). Plug in the values of \(a\), \(b\), and \(c\):\[ R = \frac{-7 \pm \sqrt{7^2 - 4 \times 6 \times (-18)}}{2 \times 6} \]
4Step 4: Calculate the Discriminant
Calculate the discriminant \(D = b^2 - 4ac\):\[ D = 7^2 - 4 \times 6 \times (-18) \]\[ D = 49 + 432 \]\[ D = 481 \]Since 481 is positive, there are two real roots.
5Step 5: Compute the Roots
Using the quadratic formula, compute the roots:\[ R = \frac{-7 \pm \sqrt{481}}{12} \]Calculate each possibility:\[ R_1 = \frac{-7 + \sqrt{481}}{12}, \quad R_2 = \frac{-7 - \sqrt{481}}{12} \]
6Step 6: Use a Calculator to Find the Values
Use a calculator to find the decimal values of the roots. Compute the values:\[ R_1 \approx \frac{-7 + 21.93}{12} \approx 1.24\]\[ R_2 \approx \frac{-7 - 21.93}{12} \approx -2.41\]
Key Concepts
Quadratic FormulaDiscriminantReal RootsCalculator Usage
Quadratic Formula
The quadratic formula is a cornerstone in solving quadratic equations of the form \(ax^2 + bx + c = 0\). It provides a reliable way to find the roots, or solutions, when the equation can't be easily factored. The formula is given by: \[R = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] where
- \(a\), \(b\), and \(c\) are the coefficients of the equation,
- \(b^2 - 4ac\) is part of the formula known as the discriminant,
- \(\pm\) indicates there could be two solutions: one adding and the other subtracting the square root.
Discriminant
The discriminant is a crucial component of the quadratic formula. It is found under the square root in the formula:\[D = b^2 - 4ac\] Understanding the value of the discriminant helps in predicting the nature of the roots:
- If \(D > 0\), there are two distinct real roots, meaning the graph of the quadratic equation will intersect the x-axis at two points.
- If \(D = 0\), there is exactly one real root, or a repeated root, and the graph touches the x-axis at one point.
- If \(D < 0\), there are no real roots, as the graph does not cross or touch the x-axis. This indicates the roots are complex numbers.
Real Roots
Real roots refer to the x-values where the graph of a quadratic equation crosses the x-axis. A quadratic equation can have:
- No real roots if the discriminant is less than zero; in this case, the solutions are complex.
- One real root if the discriminant is zero; the parabola touches the x-axis at exactly one point.
- Two real roots if the discriminant is greater than zero; the parabola intersects the x-axis at two points.
Calculator Usage
Using a calculator for solving the quadratic equation is immensely helpful, especially when dealing with non-perfect square discriminants or large numbers. Here are some tips when using a calculator in this scenario:
- Ensure your calculator is in the correct mode for operations—in most cases, standard or real number mode.
- Step by step, input values from the quadratic formula, especially when dealing with complex under-the-root calculations.
- First compute the discriminant, log the result, and then proceed with finding the roots.
- Divide the computation into manageable parts to avoid errors, calculate \(b^2\), \(-4ac\), and the whole \(\sqrt{481}\) separately before putting them together.
- Use the memory functions of the calculator to store intermediate results if available.
Other exercises in this chapter
Problem 22
Solve the given quadratic equations by factoring. $$A^{2}+8 A+16=0$$
View solution Problem 22
Solve the given quadratic equations by completing the square. Exercises \(11-14\) and \(17-20\) may be checked by factoring. $$3 x^{2}=3-4 x$$
View solution Problem 23
solve the given quadratic equations, using the quadratic formula. Exercises \(5-8\) are the same as Exercises \(11-14\) of Section 7.2. $$s^{2}=9+s(1-2 s)$$
View solution Problem 23
In Exercises \(11-30,\) solve the given quadratic equations by completing the square. Exercises \(11-14\) and \(17-20\) may be checked by factoring. $$2 y^{2}-y
View solution