Problem 23
Question
The planar structure of \(\mathrm{BF}_{3}\) can be explain by the fact that \(\mathrm{BF}_{3}\) is (a) sp hybridized (b) sp \(^{2}\) hybridized (c) sp \(^{3}\) hybridized (d) sp \(^{3}\) hybridized
Step-by-Step Solution
Verified Answer
The planar structure of \(\mathrm{BF}_{3}\) is due to \(\text{sp}^2\) hybridization.
1Step 1: Analyze the Given Molecule
The molecule in question is \(\mathrm{BF}_{3}\), or boron trifluoride. It is a compound of boron surrounded by three fluorine atoms.
2Step 2: Determine the Central Atom's Electron Configuration
Boron, the central atom, has an atomic number of 5, with an electron configuration of \([1s^2 2s^2 2p^1]\). This suggests boron has three valence electrons available for bonding.
3Step 3: Calculate the Number of Hybrid Orbitals
In \(\mathrm{BF}_{3}\), boron forms three sigma bonds with fluorine atoms. This requires three equivalent hybrid orbitals, indicating \(\mathrm{sp}^2\) hybridization, since \(\mathrm{sp}^2\) provides three hybrid orbitals: one \(s\) and two \(p\).
4Step 4: Relate Hybridization to Molecular Shape
\(\mathrm{sp}^2\) hybridization results in a trigonal planar shape, which corresponds to \(\mathrm{BF}_{3}\)'s planar structure.
5Step 5: Confirm with VSEPR Theory
According to VSEPR theory, the geometry of three bonded pairs around the central atom, with no lone pairs, results in a trigonal planar shape, consistent with \(\mathrm{sp}^2\) hybridization.
Key Concepts
BF3 molecular geometrysp2 hybridizationVSEPR theory
BF3 molecular geometry
Borondifluoride, or \( \text{BF}_3 \), is a molecule that showcases a simple yet elegant geometry known as trigonal planar. This geometry occurs because of how the atoms are arranged around the central atom, boron. In \( \text{BF}_3 \), the boron atom is surrounded equally by three fluorine atoms. This creates a flat triangular shape where each fluorine atom is at each corner of the triangle.
In this structure, the bond angles are all 120°, providing symmetry and balance. The boron atom is on the same plane as the three fluorine atoms, hence the name "planar." This arrangement minimizes repulsion between the bonding pairs, resulting in a stable molecular structure. The planar structure is essential for \( \text{BF}_3 \) as it plays a role in its reactivity and interaction with other molecules, particularly in chemical reactions where it often acts as a Lewis acid.
In this structure, the bond angles are all 120°, providing symmetry and balance. The boron atom is on the same plane as the three fluorine atoms, hence the name "planar." This arrangement minimizes repulsion between the bonding pairs, resulting in a stable molecular structure. The planar structure is essential for \( \text{BF}_3 \) as it plays a role in its reactivity and interaction with other molecules, particularly in chemical reactions where it often acts as a Lewis acid.
sp2 hybridization
To understand \( \text{BF}_3 \)'s geometry, we need to examine the concept of \( \text{sp}^2 \) hybridization. Hybridization is a process that describes the mixing of atomic orbitals to produce new hybrid orbitals. These hybrids are key in forming molecular bonds. When we say \( \text{sp}^2 \) hybridization, we refer to the blending of one s orbital and two p orbitals from the boron atom.
This process creates three equivalent \( \text{sp}^2 \) hybrid orbitals. Each of these orbitals forms a sigma bond with an orbital from a fluorine atom in \( \text{BF}_3 \).
This process creates three equivalent \( \text{sp}^2 \) hybrid orbitals. Each of these orbitals forms a sigma bond with an orbital from a fluorine atom in \( \text{BF}_3 \).
- The hybrid orbitals align 120° apart, creating a planar and symmetrical molecular structure.
- The remaining unhybridized p orbital doesn’t participate in bonding directly, but its presence is crucial for other chemical properties like electronic interactions.
VSEPR theory
Valence Shell Electron Pair Repulsion (VSEPR) theory is a model used to predict the shape of molecules. The theory is based on an intuitive understanding: Because electron pairs repel each other, molecules adjust their shape so that these repulsions are minimized. In \( \text{BF}_3 \), VSEPR theory helps explain its planar geometry.
This theory elegantly complements the concept of \( \text{sp}^2 \) hybridization, as both show how electrons strive for a balance that dictates overall molecular geometry. VSEPR provides a useful framework for predicting molecular shapes just by considering electron pair interactions, making it an invaluable tool in chemistry.
- The boron atom in \( \text{BF}_3 \) forms three bonding pairs with fluorine atoms.
- There are no lone pairs on the boron, which is crucial because lone pairs typically have stronger repulsive forces compared to bonding pairs.
This theory elegantly complements the concept of \( \text{sp}^2 \) hybridization, as both show how electrons strive for a balance that dictates overall molecular geometry. VSEPR provides a useful framework for predicting molecular shapes just by considering electron pair interactions, making it an invaluable tool in chemistry.
Other exercises in this chapter
Problem 21
The ratio of \(\pi\) and \(\sigma\) bonds in benzene is (a) \(1: 2\) (b) \(1: 4\) (c) \(1: 6\) (d) \(1: 6\)
View solution Problem 22
The bond length between \(\mathrm{C}-\mathrm{C}\) bond in \(\mathrm{sp}^{3}\) hybridized molecule is (a) \(1.2 \AA\) (b) \(1.39 \AA\) (c) \(1.33 \AA\) (d) \(1.5
View solution Problem 24
Dipole moment is shown by (a) 2 -methyl propane (b) trans-2-butene (c) cis-2-butene (d) carbon tetrachloride
View solution Problem 25
\(\mathrm{O}_{2}^{2+}\) has a bond order of (a) 1 (b) 2 (c) 3 (d) 4
View solution