Problem 23
Question
Solve the equation or write no real solution. Write the solutions as integers if possible. Otherwise, write them as radical expressions. $$ x^{2}=225 $$
Step-by-Step Solution
Verified Answer
The solutions are x = 15 and x = -15.
1Step 1: Rewrite the equation
First, rewrite the given equation as \(x^{2}-225=0\) to see it more clearly as difference of squares.
2Step 2: Apply the square root property
Secondly, apply the square root property to solve for x. This property tells us that if \(x^2 = c\), then \(x = \sqrt{c}\) or \(x = - \sqrt{c}\). Therefore the equation can be written as \(x = \sqrt{225}\) or \(x = - \sqrt{225}\).
3Step 3: Simplify and solve for x
Lastly, simplify and solve for x. Since square root of 225 equals 15, the two solution for the equation are \(x = 15\) and \(x = -15\).
Key Concepts
Difference of SquaresSquare Root PropertyRadical Expressions
Difference of Squares
The difference of squares is a specific way of factoring where you have two squares subtracted from one another. It follows the pattern \( a^2 - b^2 = (a + b)(a - b) \). This concept is essential when dealing with quadratic equations like \( x^2 = 225 \), which can be rewritten as \( x^2 - 225 = 0 \). This form reveals itself as a difference of squares because it can be seen as \( x^2 - 15^2 = 0 \). Here:
- \( a = x \)
- \( b = 15 \)
Square Root Property
The square root property simplifies solving equations that have the form \( x^2 = c \). According to this property, you can solve the equation by taking the square root of both sides. This results in two possible solutions: one positive and one negative. For example, if we have \( x^2 = 225 \), applying the square root property means calculating \( x = \pm \sqrt{225} \). Here:
- \( x = \sqrt{225} \) which simplifies to \( x = 15 \)
- \( x = -\sqrt{225} \) which simplifies to \( x = -15 \)
Radical Expressions
Radical expressions involve roots, such as square roots, cube roots, etc. In our case, we focused on square roots. When a number is not a perfect square, its square root is represented as a radical expression, like \( \sqrt{c} \). However, for our solution \( \sqrt{225} \), since 225 is a perfect square (being equal to \( 15^2 \)), the radical form simplifies neatly to an integer, 15.
Radical expressions maintain their importance especially when solutions do not neatly reduce to integers. If \( x^2 = c \) had \( c \) as a non-perfect square, then \( x = \sqrt{c} \) would remain a radical.Understanding radical expressions can help:
Radical expressions maintain their importance especially when solutions do not neatly reduce to integers. If \( x^2 = c \) had \( c \) as a non-perfect square, then \( x = \sqrt{c} \) would remain a radical.Understanding radical expressions can help:
- Represent solutions to equations where an exact integer isn’t possible.
- Simplify algebraic manipulations and provide exact forms.
Other exercises in this chapter
Problem 23
Determine whether the equation has two solutions, one solution, or no real solution. \(2 x^{2}-4 x+3=0\)
View solution Problem 23
Simplify the expression. $$ \sqrt{18} $$
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Write the equation in words. $$ \sqrt{1}=1 $$
View solution Problem 24
Sketch the graph of the function. Plot the given point and determine whether the point lies inside or outside the parabola. $$ \begin{aligned} &y=4 x^{2}-x+1\\\
View solution