Problem 23
Question
Solve each formula for the specified variable. \(S=2 \pi r h+2 \pi r^{2}\) for \(h\)
Step-by-Step Solution
Verified Answer
\(h = \frac{S - 2 \pi r^2}{2 \pi r}\)
1Step 1: Identify the Equation
The given formula is related to the surface area of a cylinder:\[ S = 2 \pi r h + 2 \pi r^2 \]Our task is to solve this equation for \( h \).
2Step 2: Isolate the Term Involving h
Subtract the term not involving \( h \) from both sides to get the term with \( h \) alone:\[ S - 2 \pi r^2 = 2 \pi r h \]
3Step 3: Solve for h
Divide both sides of the equation by \( 2 \pi r \) to solve for \( h \):\[ h = \frac{S - 2 \pi r^2}{2 \pi r} \]
Key Concepts
Formulas in GeometrySurface Area of a CylinderIsolating Variables
Formulas in Geometry
Geometry uses specific formulas to calculate measurements related to shapes. These formulas are essential for determining various properties, such as perimeter, area, volume, and surface area. Each geometric shape, like a square or a circle, has its own set of formulas. For example,
- The formula for the area of a rectangle is length times width: \( A = l \times w \).
- The circumference of a circle is given by \( C = 2 \pi r \), where \( r \) is the radius.
Surface Area of a Cylinder
A cylinder's surface area includes the areas of its two circular bases and the curved surface that connects these bases. The formula to calculate it is: \[ S = 2 \pi r h + 2 \pi r^2 \]. Here,
- The term \( 2 \pi r h \) represents the curved surface area.
- The term \( 2 \pi r^2 \) accounts for the two bases (top and bottom).
Isolating Variables
Isolating variables means getting a specific variable by itself on one side of the equation. This is crucial when solving for unknowns. In our exercise, the goal was to extract \( h \) from the equation:
- First, identify terms not involving \( h \) and move them to the other side using subtraction. This simplifies the equation.
- Next, divide the remaining terms by the coefficient linked to \( h \), which in this case is \( 2 \pi r \).
Other exercises in this chapter
Problem 23
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