Problem 23
Question
Solve each equation by the method of your choice. Simplify irrational solutions, if possible. $$2 x^{2}-x=1$$
Step-by-Step Solution
Verified Answer
The solutions to the equation \(2x^2-x=1\) are \(x = 1\) and \(x = -0.5\).
1Step 1: Rearrange the Equation
The given equation can be rearranged into the standard form of a quadratic equation \(ax^2+bx+c=0\). Here, a=2, b=-1 and c=-1 so, the equation becomes \(2x^2-x-1=0\).
2Step 2: Determination of the Roots
Use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) to find the roots of the quadratic equation. Substitute a=2, b=-1, c=-1 into the formula to get \(x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4*2*-1}}{2*2}\), which further simplifies to \(x = \frac{1 \pm \sqrt{1+8}}{4}\). After calculating the square root, the equation becomes \(x = \frac{1 \pm \sqrt{9}}{4}\).
3Step 3: Simplify the roots
Now simplify the roots by solving each part of the equation. So, the roots of \(x\) will be \(x = \frac{1+3}{4}\) or \(x = \frac{1-3}{4}\). Thus, the roots will be \(x = 1\) or \(x = -0.5\).
Key Concepts
Quadratic FormulaSimplifying EquationsRoots of Equations
Quadratic Formula
The quadratic formula is a powerful tool used for solving quadratic equations, which have the general form \(ax^2 + bx + c = 0\). The formula itself is given by:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula helps us find the roots of the equation, which are the values of \(x\) that make the equation true.
- \(b^2 - 4ac\) is called the discriminant. It tells us about the nature of the roots:
- If \(b^2 - 4ac > 0\), there are two real and distinct roots.
- If \(b^2 - 4ac = 0\), there is one real double root.
- If \(b^2 - 4ac < 0\), the roots are complex.
Simplifying Equations
Simplifying equations involves reducing an expression or equation to its simplest form. This makes it easier to solve or understand. In the context of quadratic equations, simplification often involves:
- Combining like terms: Making sure terms with the same variable are added or subtracted correctly.
- Factoring: If applicable, rewriting the quadratic equation as a product of its linear factors.
- Using the quadratic formula: This often includes simplifying the expression within and outside the square root.
Roots of Equations
The roots of an equation, also known as solutions, are the values of the variable that satisfy the equation. For quadratic equations, these roots may be real or complex, as indicated by the discriminant \(b^2 - 4ac\).
- Real Roots: These occur when the discriminant is zero or positive, allowing for square root calculations.
- Complex Roots: These arise when the discriminant is negative, as the square root of a negative number involves imaginary units.
Other exercises in this chapter
Problem 23
Evaluate each function at the given values. \(f(x)=\frac{x}{|x|}\) a. \(f(6)\) b. \(f(-6)\)
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Find the vertex for the parabola whose equation is given. $$y=x^{2}+6 x$$
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Solve quadratic equation by completing the square. \(x^{2}+3 x-1=0\)
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Solve each quadratic equation by the square root property. If possible, simplify radicals or rationalize denominators. $$(3 x+2)^{2}=9$$
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