Problem 23
Question
Solve by extracting the roots. $$ 16 x 2=9 $$
Step-by-Step Solution
Verified Answer
The solutions are \(x = \frac{3}{4}\) and \(x = -\frac{3}{4}\).
1Step 1: Isolate the variable term
To begin solving the equation \(16x^2 = 9\), divide both sides of the equation by 16 to isolate the term with \(x^2\). This gives us \(x^2 = \frac{9}{16}\).
2Step 2: Take the square root of both sides
To solve for \(x\), take the square root of both sides of the equation \(x^2 = \frac{9}{16}\). This gives \(x = \pm \sqrt{\frac{9}{16}}\).
3Step 3: Simplify the square root
Simplify \(\sqrt{\frac{9}{16}}\) by finding the square root of the numerator and the denominator separately. \(\sqrt{9} = 3\) and \(\sqrt{16} = 4\), so \(\sqrt{\frac{9}{16}} = \frac{3}{4}\).
4Step 4: State the solutions
Since \(x = \pm \sqrt{\frac{9}{16}}\), the solutions are \(x = \frac{3}{4}\) and \(x = -\frac{3}{4}\). Therefore, the equation has two solutions: \(x = \frac{3}{4}\) and \(x = -\frac{3}{4}\).
Key Concepts
Quadratic EquationsSolving EquationsSimplifying Expressions
Quadratic Equations
Quadratic equations are fundamental in algebra, and they have a distinct form: \( ax^2 + bx + c = 0 \). These represent parabolas when graphed. Encountering quadratic equations can seem daunting at first, but understanding their structure is key. Each term in \( ax^2 + bx + c \) plays a role in defining the curve's shape and position.
Quadratics typically yield two solutions, which can be found using several methods, such as factoring, completing the square, or the quadratic formula. The square root method particularly comes in handy when dealing with equations missing the linear \( b \) term, like in our exercise.
Here's why quadratics are important:
Quadratics typically yield two solutions, which can be found using several methods, such as factoring, completing the square, or the quadratic formula. The square root method particularly comes in handy when dealing with equations missing the linear \( b \) term, like in our exercise.
Here's why quadratics are important:
- They model real-world scenarios like projectile motion.
- They feature two solutions, representing two possible states or conditions.
- They create a symmetrical curve, indicative of natural phenomena.
Solving Equations
Solving equations is about finding the values that make the equation true. The key steps involve simplifying, isolating terms, and performing operations both sides equally. These steps ensure you do not disrupt the equation's balance.
The particular equation \(16x^2 = 9\) highlights the use of the square root method. Here's how you solve it:
The particular equation \(16x^2 = 9\) highlights the use of the square root method. Here's how you solve it:
- First, isolate the \(x^2\) term by dividing both sides by 16. This step is crucial to remove any coefficients influencing the variable directly, leading to \(x^2 = \frac{9}{16}\).
- Next, take the square root of both sides. It’s important to remember that squaring a number is a reversible operation using square roots, and both positive and negative roots must be considered.
- Finally, interpret the square root: \( \sqrt{\frac{9}{16}} = \frac{3}{4} \). Hence, \(x = \pm \frac{3}{4}\).
Simplifying Expressions
Simplifying expressions involves condensing equations into their most basic form, making them easier to work with. This often includes reducing fractions, factoring, or finding common denominators. The goal is to make calculations clearer and solve problems efficiently.
In the given problem, simplifying \(\sqrt{\frac{9}{16}}\) showcases how to handle square roots effectively. Here's the process:
In the given problem, simplifying \(\sqrt{\frac{9}{16}}\) showcases how to handle square roots effectively. Here's the process:
- Identify separate components: Here, we recognize that both numerator (9) and denominator (16) are perfect squares.
- Calculate each square root individually: \(\sqrt{9} = 3\) and \(\sqrt{16} = 4\).
- Combine the results: This simplification yields \(\frac{3}{4}\).
Other exercises in this chapter
Problem 23
Use the quadratic formula to solve the following. $$x_{2}+2 x-5=0$$
View solution Problem 23
Perform the operations. $$ 2 i(7-4 i) $$
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Choose the appropriate method to solve the following. $$ 12 x 2-2 x+52=0 $$
View solution Problem 23
Graph. Find the vertex and the y-intercept. In addition, find the \(x\) - intercepts if they exist. $$ y=x 2-2 x-8 $$
View solution