Problem 23
Question
Simplify the expression, writing your answer using positive exponents only. $$ \frac{3 x^{3}}{2 x^{4}} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(\frac{3}{2x}\).
1Step 1: Recall the rules of exponents
When dividing terms with the same base, subtract the exponents. In this case, the base is x. So, we will apply this rule to simplify the expression.
2Step 2: Divide the terms
We will divide the coefficients (the numbers) and the terms with the same base (the x's). This operation will result in:
\[
\frac{3}{2} \cdot \frac{x^3}{x^4}
\]
3Step 3: Subtract the exponents
The next step is to subtract the exponents of the terms with the same base, x.
\[
\frac{3}{2} \cdot x^{3-4}
\]
4Step 4: Simplify the expression
Now, we simplify the expression by calculating the exponent.
\[
\frac{3}{2} \cdot x^{-1}
\]
5Step 5: Rewrite using positive exponents only
To rewrite the expression using positive exponents only, we move the term with the negative exponent to the denominator.
\[
\frac{3}{2x}
\]
The final simplified expression is \(\frac{3}{2x}\).
Key Concepts
Exponent RulesPositive ExponentsDivision of Algebraic Expressions
Exponent Rules
Exponent rules are fundamental for simplifying expressions with powers. A key rule is when dividing like terms with the same base, subtract their exponents. For example, consider \(\frac{x^a}{x^b} = x^{a-b}\). This rule simplifies expressions by reducing the power of the variable. Remember that all terms must have the same base to apply this rule effectively.
Subtraction of exponents is just the beginning. It helps in understanding more complex expressions where multiple exponents interact. Pay attention to the base of each term as this defines how and when you can apply these rules.
Subtraction of exponents is just the beginning. It helps in understanding more complex expressions where multiple exponents interact. Pay attention to the base of each term as this defines how and when you can apply these rules.
Positive Exponents
Expressions are often required to be simplified using only positive exponents. Negative exponents indicate reciprocal or division.
For instance, \(x^{-n}\) is equivalent to \(\frac{1}{x^n}\). This transformation eliminates negative exponents and leaves the expression cleaner and sometimes simpler to use.
Writing with positive exponents is essential for clarity. In the given exercise, rewriting \(x^{-1}\) as \(\frac{1}{x}\) allows for a straightforward interpretation, easing evaluation and further calculations.
For instance, \(x^{-n}\) is equivalent to \(\frac{1}{x^n}\). This transformation eliminates negative exponents and leaves the expression cleaner and sometimes simpler to use.
Writing with positive exponents is essential for clarity. In the given exercise, rewriting \(x^{-1}\) as \(\frac{1}{x}\) allows for a straightforward interpretation, easing evaluation and further calculations.
Division of Algebraic Expressions
Dividing algebraic expressions involves breaking down both coefficients and variable terms. Begin by dividing the coefficients: the numbers in front of variables. For the expression \(\frac{3}{2}\), it's straightforward.
Next, tackle the variable terms following exponent rules. With the same base, subtract the exponents to simplify these terms. In this example \(x^{3-4}\), which becomes \(x^{-1}\).
Finally, ensure the expression is written properly. Simplifying includes rewriting any negative exponents using positive terms. This often involves placement in the denominator, turning \(x^{-1}\) into \(\frac{1}{x}\), leaving the final result as \(\frac{3}{2x}\).
Division might initially seem challenging, but breaking it into manageable steps ensures accuracy, achieving a clean, simplified form.
Next, tackle the variable terms following exponent rules. With the same base, subtract the exponents to simplify these terms. In this example \(x^{3-4}\), which becomes \(x^{-1}\).
Finally, ensure the expression is written properly. Simplifying includes rewriting any negative exponents using positive terms. This often involves placement in the denominator, turning \(x^{-1}\) into \(\frac{1}{x}\), leaving the final result as \(\frac{3}{2x}\).
Division might initially seem challenging, but breaking it into manageable steps ensures accuracy, achieving a clean, simplified form.
Other exercises in this chapter
Problem 23
Carry out the indicated operation and write your answer using positive exponents only. $$ \frac{4^{1 / 2}}{4^{5 / 2}} $$
View solution Problem 23
Solve the given equation. $$ \frac{2}{y-1}=4 $$
View solution Problem 23
In Exercises, factor the polynomial. If the polynomial is prime, state it. $$ x^{2}+6 x y+y^{2} $$
View solution Problem 23
State the real number property that iustifies the statement $$ (2 x+3 y)+(x+4 y)=2 x+[3 y+(x+4 y)] $$
View solution