Problem 23
Question
Problems 23-28 are about polar equations that give circles.] Convert \(r=\sin \theta\) into an \(x y\) equation. Multiply first by \(r\).
Step-by-Step Solution
Verified Answer
The Cartesian equation is \(x^2 + y^2 - y = 0\).
1Step 1: Understand the Polar Equation
The polar equation given is \(r = \sin \theta\). This means that the length of the radius \(r\) is equal to the sine of the angle \(\theta\).
2Step 2: Multiply by r
To convert the equation into Cartesian coordinates, first multiply both sides by \(r\), giving us \(r^2 = r \sin \theta\).
3Step 3: Substitute Cartesian Coordinates
Recall the conversions from polar to Cartesian coordinates: \(x = r \cos \theta\) and \(y = r \sin \theta\). Also, note that \(r^2 = x^2 + y^2\).
4Step 4: Replace Polar Terms with Cartesian Terms
Substitute \(r^2 = x^2 + y^2\) and \(r \sin \theta = y\) into the equation \(r^2 = r \sin \theta\). This gives us \(x^2 + y^2 = y\).
5Step 5: Rearrange the Equation
Rearrange the equation \(x^2 + y^2 = y\) to \(x^2 + y^2 - y = 0\). This is the equation of the circle in Cartesian coordinates.
Key Concepts
Cartesian CoordinatesEquation ConversionCircle Equations
Cartesian Coordinates
Cartesian coordinates are a way to determine every point in a two-dimensional plane using an ordered pair of numbers. These coordinates
For example, the point (3, 4) means moving 3 units along the x-axis and 4 units up the y-axis.
This system is pivotal for equations involving circles, lines, and parabolas, enabling easy visualization and translation from abstract equations to tangible plots.
- consist of an x-coordinate (horizontal direction)
- and a y-coordinate (vertical direction).
For example, the point (3, 4) means moving 3 units along the x-axis and 4 units up the y-axis.
This system is pivotal for equations involving circles, lines, and parabolas, enabling easy visualization and translation from abstract equations to tangible plots.
Equation Conversion
Equation conversion involves changing mathematical expressions from one form to another, often to simplify the problem-solving process. When dealing with polar to Cartesian conversions, it's important to understand the relationship between the coordinates.
For the problem where we have \(r = \sin \theta\), we aim to convert it into Cartesian form.
By initially multiplying the polar equation by \( r \), the expression becomes \(r^2 = r \sin \theta\).
Through substitution, we use \(r^2 = x^2 + y^2\) and \(r \sin \theta = y\), resulting in \(x^2 + y^2 = y\). Converting equations helps reveal further properties of the graph, such as symmetry and shape.
- The polar coordinate system uses \( r \) (distance from the origin) and \( \theta \) (angle from the positive x-axis).
- Cartesion conversions use the formulas \(x = r \cos \theta \)
- and \( y = r \sin \theta \).
For the problem where we have \(r = \sin \theta\), we aim to convert it into Cartesian form.
By initially multiplying the polar equation by \( r \), the expression becomes \(r^2 = r \sin \theta\).
Through substitution, we use \(r^2 = x^2 + y^2\) and \(r \sin \theta = y\), resulting in \(x^2 + y^2 = y\). Converting equations helps reveal further properties of the graph, such as symmetry and shape.
Circle Equations
Circle equations generally describe a circle in analytic geometry. They define all points on a plane at a specific distance (radius) from a center point. The standard form for a circle's equation is \((x-h)^2 + (y-k)^2 = r^2\), where
The translation of such an equation is crucial for accurate graph plotting and measuring relative distances and areas within geometry problems.
- \((h, k)\) is the circle's center,
- and \(r\) is its radius.
- For circles centered at the origin \((0,0)\),
- the equation simplifies to \(x^2 + y^2 = r^2\).
The translation of such an equation is crucial for accurate graph plotting and measuring relative distances and areas within geometry problems.
Other exercises in this chapter
Problem 22
Show that the triangle with vertices at \((0,0),\left(r_{1}, \theta_{1}\right),\) and \(\left(r_{2}, \theta_{2}\right)\) has area \(A=\frac{1}{2} r_{1} r_{2} \s
View solution Problem 23
Find the points where the two curves meet. \(r \sin \theta=1\) and \(r \cos (\theta-\pi / 4)=\sqrt{2}\) (straight lines)
View solution Problem 24
Find the equation of the tangent line to the circle \(r=\cos \theta\) at \(\theta=\pi / 6\)
View solution Problem 24
When is there a dimple in \(r=1+b \cos \theta\) ? From \(x=\) \((1+b \cos \theta) \cos \theta\) find \(d x / d \theta\) and \(d^{2} x / d \theta^{2}\) at \(\the
View solution