Problem 23
Question
Plot on the same axes the given function along with the Maclaurin polynomials of orders \(1,2,3\), and \(4 .\) $$ e^{-x^{2}} $$
Step-by-Step Solution
Verified Answer
The function and its Maclaurin polynomials of orders 1, 2, 3, and 4 are plotted together.
1Step 1: Understand the Exercise
We are asked to plot the function \(e^{-x^2}\) along with its Maclaurin polynomials of orders 1, 2, 3, and 4. A Maclaurin series is a Taylor series expansion of a function about 0.
2Step 2: Find the Maclaurin Series
The Maclaurin series for a function \(f(x)\) is given by \(\sum_{n=0}^{\infty} \frac{f^{(n)}(0)}{n!}x^n\). For \(f(x) = e^{-x^2}\), this will result in a series expansion.
3Step 3: Compute the First Few Derivatives
Calculate the necessary derivatives of \(f(x)\). \(f(x) = e^{-x^2}\), \(f'(x) = -2xe^{-x^2}\), \(f''(x) = (4x^2 - 2)e^{-x^2}\). Evaluate these at \(x = 0\) to get the coefficients for the series.
4Step 4: Find the Maclaurin Polynomials
Evaluate derivatives at \(x = 0\): - \(f(0) = 1\), - \(f'(0) = 0\), - \(f''(0) = -2\). Calculate the series: - Order 0: \(P_1(x) = 1\) - Order 1: \(P_2(x) = 1\) - Order 2: \(P_2(x) = 1 - x^2\) - Order 3: \(P_3(x) = 1 - x^2\) - Order 4: \(P_4(x) = 1 - x^2 + \frac{x^4}{2}\).
5Step 5: Plot the Functions
Using a graphing tool or software, plot \(e^{-x^2}\) and the polynomials \(P_1(x) = 1\), \(P_2(x) = 1\), \(P_3(x) = 1 - x^2\), and \(P_4(x) = 1 - x^2 + \frac{x^4}{2}\) on the same axes for some range, such as \([-2, 2]\). Observe how the polynomials approximate the function.
Key Concepts
Taylor Series ExpansionDerivative EvaluationPolynomial ApproximationGraphing Polynomials
Taylor Series Expansion
The Taylor Series Expansion is a key mathematical tool that helps approximate functions using polynomials. By expanding a function into a series of terms based on its derivatives at a single point, we can create a polynomial that closely resembles the original function.
For a function centered at zero, the expansion is known as the Maclaurin series. Given a function \( f(x) \), its Taylor series can be expressed as:
For a function centered at zero, the expansion is known as the Maclaurin series. Given a function \( f(x) \), its Taylor series can be expressed as:
- \( f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \ldots \)
- When \( a = 0 \), the series simplifies to the Maclaurin series: \( f(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \ldots \)
Derivative Evaluation
Derivative Evaluation is critical in computing the Taylor or Maclaurin series. Derivatives provide the coefficients for each term in the polynomial expansion. Calculating these derivatives can sometimes be straightforward, but they can also become quite complex.
The derivatives of a function \( f(x) \) give rate information about how \( f \) changes at a point. In the context of a Maclaurin series, these derivatives are evaluated at \( x = 0 \). For example, if \( f(x) = e^{-x^2} \):
The derivatives of a function \( f(x) \) give rate information about how \( f \) changes at a point. In the context of a Maclaurin series, these derivatives are evaluated at \( x = 0 \). For example, if \( f(x) = e^{-x^2} \):
- \( f(0) = 1 \) (function value at zero)
- \( f'(0) = 0 \) (first derivative at zero)
- \( f''(0) = -2 \) (second derivative at zero)
Polynomial Approximation
Polynomial Approximation is a powerful technique for representing complex functions as sums of simpler polynomial expressions. This allows for smoother calculations and simulations when working with these functions.
Consider a function like \( e^{-x^2} \), which can be difficult to graph and compute exactly. By approximating it with a Maclaurin polynomial, you use a simpler polynomial function that behaves similarly near \( x = 0 \):
Consider a function like \( e^{-x^2} \), which can be difficult to graph and compute exactly. By approximating it with a Maclaurin polynomial, you use a simpler polynomial function that behaves similarly near \( x = 0 \):
- Order 0: \( P_1(x) = 1 \)
- Order 1: \( P_2(x) = 1 \)
- Order 2: \( P_3(x) = 1 - x^2 \)
- Order 4: \( P_4(x) = 1 - x^2 + \frac{x^4}{2} \)
Graphing Polynomials
Graphing Polynomials, particularly in the context of Taylor or Maclaurin series, offers a visual understanding of how well a series can approximate a function. By plotting the original function alongside its polynomial approximations, you can compare how closely the polynomials match the function's behavior.
For instance, to approximate \( e^{-x^2} \) using Maclaurin polynomials of varying degrees (like orders 1, 2, 3, and 4), one would plot each polynomial approximation of \( e^{-x^2} \) and set them against the actual curve of \( e^{-x^2} \). This comparison helps observe key characteristics:
For instance, to approximate \( e^{-x^2} \) using Maclaurin polynomials of varying degrees (like orders 1, 2, 3, and 4), one would plot each polynomial approximation of \( e^{-x^2} \) and set them against the actual curve of \( e^{-x^2} \). This comparison helps observe key characteristics:
- The fit is better near \( x = 0 \), the center of the series expansion.
- Higher order polynomials provide more accurate approximations over a larger area.
- The approximation tends to diverge from the original function as you move further from zero.
Other exercises in this chapter
Problem 22
Use any test developed so far, including any from Section \(9.2\), to decide about the convergence or divergence of the series. Give a reason for your conclusio
View solution Problem 22
Find an explicit formula a \(a_{n}=\) ____ for each sequence, determine whether the sequence converges or diverges, and, if it converges, find \(\lim _{n \right
View solution Problem 23
Find the Taylor series in \(x-a\) through the term \((x-a)^{3}\). \(1+x^{2}+x^{3}, a=1\)
View solution Problem 23
Determine convergence or divergence for each of the series. Indicate the test you use. \(\frac{1}{3}+\frac{2}{3^{2}}+\frac{3}{3^{3}}+\frac{4}{3^{4}}+\cdots\)
View solution