Problem 23
Question
Perform the following calculations and retain the appropriate number of significant figures in each result. (a) \(\left(38.4 \times 10^{-3}\right) \times\left(6.36 \times 10^{5}\right)=\) (b) \(\frac{\left(1.45 \times 10^{2}\right) \times\left(8.76 \times 10^{-4}\right)}{\left(9.2 \times 10^{-3}\right)^{2}}=\) (c) \(24.6+18.35-2.98=\) (d) \(\left(1.646 \times 10^{3}\right)-\left(2.18 \times 10^{2}\right)+\left[\left(1.36 \times 10^{4}\right)\right.\) [Hint: The significant figure rule for the extraction of a root is the same as for multiplication.] \(\left.\times\left(5.17 \times 10^{-2}\right)\right]=\) (e) \(\frac{-7.29 \times 10^{-4}+\sqrt{\left(7.29 \times 10^{-4}\right)^{2}+4(1.00)\left(2.7 \times 10^{-5}\right)}}{2 \times(1.00)}\)
Step-by-Step Solution
VerifiedKey Concepts
Multiplication and Division Rules
Let's break it down with part (a) from our exercise:
- The expression is \( (38.4 \times 10^{-3}) \times (6.36 \times 10^{5}) \).
- Here, \( 38.4 \times 10^{-3} \) has 3 significant figures and \( 6.36 \times 10^{5} \) also has 3 significant figures.
- Thus, the final answer should be rounded to 3 significant figures.
- The expression is \( \frac{(1.45 \times 10^{2}) \times (8.76 \times 10^{-4})}{(9.2 \times 10^{-3})^{2}} \).
- The significant figures of the terms are as follows: \( 1.45 \times 10^{2} \) has 3 significant figures, \( 8.76 \times 10^{-4} \) also has 3 significant figures, and \( 9.2 \times 10^{-3} \) has 2 significant figures.
- The calculated result should, therefore, be reported with 2 significant figures, as 9.2 limits the precision.
Addition and Subtraction Precision
Consider part (c) of the exercise:
- The calculation is \( 24.6 + 18.35 - 2.98 \).
- Here, the decimal places are: 1 for 24.6, 2 for 18.35, and 2 for 2.98.
- The number with the least decimal places is 24.6, which has 1 decimal place.
- Therefore, the result should be rounded to 1 decimal place, giving us 40.0 after calculations.
Rounding Off
Here's how you round a number:
- Identify which digit will be the last one retained based on your significant figures or decimal place requirements.
- If the digit immediately following this is 5 or higher, round the last retained digit up by one.
- Otherwise, leave the last retained digit as it is.
- Our result is \(0.000183\) and needs to be rounded to match the least number of decimal places in the operation components, which here is 2.
- This means the final value should be \(0.00\), reflecting that only zeros appear in the first two decimal places.