Problem 23
Question
Methanol, \(\mathrm{CH}_{3} \mathrm{OH}\), has a normal boiling point of \(64.7^{\circ} \mathrm{C}\) and a vapor pressure of \(100 \mathrm{mmHg}\) at \(21.2^{\circ} \mathrm{C}\). Formaldehyde, \(\mathrm{H}_{2} \mathrm{C}=\mathrm{O},\) has a normal boiling point of \(-19.5^{\circ} \mathrm{C}\) and a vapor pressure of \(100 \mathrm{mmHg}\) at \(-57.3^{\circ} \mathrm{C} .\) Explain why these two compounds have different boiling points and require different temperatures to achieve the same vapor pressure.
Step-by-Step Solution
Verified Answer
Methanol has stronger intermolecular forces than formaldehyde, leading to a higher boiling point and requiring a higher temperature to reach the same vapor pressure.
1Step 1: Understand Boiling Point
The boiling point of a substance is the temperature at which its vapor pressure equals the atmospheric pressure. For methanol and formaldehyde, the differences in boiling points indicate the strength of intermolecular forces acting within the liquids—stronger forces require more energy (higher temperature) to overcome.
2Step 2: Compare Intermolecular Forces
Methanol (\(\mathrm{CH}_3 \mathrm{OH}\)) can form hydrogen bonds due to its OH group, whereas formaldehyde (\(\mathrm{H}_2\mathrm{C} \!=\mathrm{O}\)) cannot form hydrogen bonds as effectively as methanol. This makes the intermolecular forces within methanol stronger than those within formaldehyde.
3Step 3: Impact on Vapor Pressure
Stronger intermolecular forces in methanol result in a lower vapor pressure at a given temperature compared to substances with weaker forces. This means methanol requires a higher temperature to reach the same vapor pressure as formaldehyde.
4Step 4: Relationship with Temperature and Vapor Pressure
At \(64.7^{\circ}\mathrm{C}\), methanol's vapor pressure matches atmospheric pressure, meaning it has reached its boiling point. Conversely, formaldehyde, with weaker forces, boils at a much lower temperature, \(-19.5^{\circ} \mathrm{C}\). When both are at \(100 \, \mathrm{mmHg}\), methanol is at a significantly higher temperature (\(21.2^{\circ} \mathrm{C}\)) than formaldehyde (\(-57.3^{\circ} \mathrm{C}\)).
Key Concepts
Boiling PointVapor PressureHydrogen Bonding
Boiling Point
The boiling point is an essential concept in understanding the transition between liquid and gas phases of a substance. It is defined as the temperature at which a liquid's vapor pressure matches the external atmospheric pressure, leading to the formation of bubbles within the liquid. The boiling point reveals a lot about the forces holding a liquid together.
For substances like methanol and formaldehyde, the boiling point differences highlight variations in intermolecular forces. Methanol has a boiling point of 64.7^{ ext{o}} ext{C}, while formaldehyde boils at -19.5^{ ext{o}} ext{C}.
For substances like methanol and formaldehyde, the boiling point differences highlight variations in intermolecular forces. Methanol has a boiling point of 64.7^{ ext{o}} ext{C}, while formaldehyde boils at -19.5^{ ext{o}} ext{C}.
- Methanol's higher boiling point suggests stronger intermolecular forces, requiring more energy to reach the same vapor pressure as formaldehyde.
- Conversely, formaldehyde's lower boiling point indicates weaker molecular attractions, thus less energy is needed to achieve the boiling state.
Vapor Pressure
Vapor pressure is a measure of a liquid's tendency to evaporate. At any given temperature, molecules in a liquid can gain enough energy to break free from intermolecular attractions and enter the gas phase. The vapor pressure reflects how easily this process occurs.
Methanol and formaldehyde illustrate how variations in intermolecular forces influence vapor pressure. At the same vapor pressure of 100 mmHg, methanol is at a substantially higher temperature (21.2°C) compared to formaldehyde (-57.3°C).
Methanol and formaldehyde illustrate how variations in intermolecular forces influence vapor pressure. At the same vapor pressure of 100 mmHg, methanol is at a substantially higher temperature (21.2°C) compared to formaldehyde (-57.3°C).
- Methanol's stronger intermolecular forces mean it retains its molecules more tightly, leading to lower vapor pressure at the same temperature than formaldehyde.
- For formaldehyde, weaker intermolecular attractions result in a higher vapor pressure, even at lower temperatures.
Hydrogen Bonding
Hydrogen bonding is a special type of strong intermolecular force that occurs when hydrogen is covalently bonded to electronegative atoms like oxygen, nitrogen, or fluorine. This bonding accounts for higher boiling points and affects vapor pressure substantially.
In methanol (CH₃OH), hydrogen bonding is prevalent due to the presence of the hydroxyl (OH) group. This enables methanol molecules to form strong attractions with each other, elevating its boiling point and influencing its vapor pressure.
In methanol (CH₃OH), hydrogen bonding is prevalent due to the presence of the hydroxyl (OH) group. This enables methanol molecules to form strong attractions with each other, elevating its boiling point and influencing its vapor pressure.
- Methanol forms hydrogen bonds easily, leading to stronger intermolecular forces, thus requiring more energy (higher temperature) to transition to the gas phase.
- In contrast, formaldehyde (H₂C=O) lacks the OH group and does not form hydrogen bonds as effectively, resulting in weaker intermolecular forces.
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