Problem 23
Question
Let $$A=\left[\begin{array}{rr}-3 & -7 \\\2 & -9 \\\5 & 0\end{array}\right] \text { and } B=\left[\begin{array}{rr}-5 & -1 \\\0 & 0 \\\3 & -4\end{array}\right]$$ Solve each matrix equation for \(X\). $$B-X=4 A$$
Step-by-Step Solution
Verified Answer
The matrix \(X\) that satisfies the equation \(B -X = 4A\) is \(X = \left[\begin{array}{rr}7 & 27 \\ -8 & 36 \\ -17 & -4\end{array}\right]\).
1Step 1: Write the given equation
To start, write down the equation provided in the exercise: \(B - X = 4A\).
2Step 2: Rewrite the equation for \(X\)
Rearrange the equation with the intention of isolating \(X\) on one side. This can be done by adding \(X\) to both sides and subtracting \(4A\) from both sides to get: \(X = B - 4A\).
3Step 3: Substitute the known matrices into the equation
Substitute the given matrices \(A\) and \(B\) into the equation. \(X = B - 4A = \left[ \begin{array}{rr}-5 & -1 \\0 & 0 \\3 & -4\end{array}\right] - 4\left[\begin{array}{rr}-3 & -7 \\2 & -9 \\5 & 0\end{array}\right]\).
4Step 4: Calculate 4A
Calculate \(4A\) by multiplying every element in matrix \(A\) by 4: \(4A = \left[\begin{array}{rr}-12 & -28 \\8 & -36 \\20 & 0\end{array}\right]\).
5Step 5: Subtract \(4A\) from \(B\)
Subtract matrix \(4A\) from matrix \(B\) by subtracting the corresponding elements: \(X = B - 4A = \left[\begin{array}{rr}-5 -(-12) & -1 -(-28) \\0 -8 & 0 -(-36) \\3 -20 & -4 -0\end{array}\right]\).
6Step 6: Calculate the elements in \(X\)
Perform the subtraction operation for each element to obtain \(X\): \(X = \left[\begin{array}{rr}7 & 27 \\ -8 & 36 \\ -17 & -4\end{array}\right]\).
Key Concepts
Matrix MultiplicationMatrix SubtractionLinear Algebra
Matrix Multiplication
Matrix multiplication is a fundamental operation in linear algebra. It involves multiplying rows of the first matrix by columns of the second matrix. The product of two matrices, say matrix \(A\) and matrix \(B\), is possible only if the number of columns in \(A\) is equal to the number of rows in \(B\). This operation results in a new matrix whose dimensions are the number of rows in \(A\) by the number of columns in \(B\). To perform matrix multiplication:
- Take each row of the first matrix.
- Multiply its elements with the corresponding elements of a column in the second matrix.
- Add the products to get the final value which is placed in the resultant matrix.
Matrix Subtraction
Matrix subtraction is an operation similar to the concept of subtracting numbers. However, it applies to matrices by subtracting corresponding elements. For two matrices to be subtracted, they must have the same dimensions. Here's how matrix subtraction works:
- The matrices should have the same number of rows and columns.
- Subtract the corresponding elements from each entry in the matrices.
- The resulting matrix will have the same dimensions as the original matrices.
Linear Algebra
Linear algebra is an essential branch of mathematics that focuses on linear equations, matrices, determinants, vectors, and vector spaces. Matrix operations, as seen in the exercise, are core components of linear algebra. They allow us to handle systems of linear equations efficiently.
Its applications span various fields such as engineering, physics, computer science, and statistics. In linear algebra:
Its applications span various fields such as engineering, physics, computer science, and statistics. In linear algebra:
- Matrices represent systems of linear equations.
- Operations like matrix multiplication and subtraction help solve these equations.
- Concepts like eigenvalues, eigenvectors, and transformations are fundamental.
Other exercises in this chapter
Problem 22
Use Gaussian elimination to find the complete solution to each system of equations, or show that none exists. $$ \left\\{\begin{aligned} 2 w-3 x+4 y+z &=7 \\ w-
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Evaluate each determinant. $$\left|\begin{array}{rrr}3 & 0 & 0 \\\2 & 1 & -5 \\\2 & 5 & -1\end{array}\right|$$
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