Problem 23
Question
\(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CMgCl}\) on reaction with \(\mathrm{D}_{2} \mathrm{O}\) produces (a) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CD}\) (b) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{OD}\) (c) \(\left(\mathrm{CD}_{3}\right)_{3} \mathrm{CD}\) (d) \(\left(\mathrm{CD}_{3}\right)_{3} \mathrm{OD}\)
Step-by-Step Solution
Verified Answer
The reaction produces \((\mathrm{CH}_{3})_{3} \mathrm{CD}\). (Option a)
1Step 1: Identify the Compound
We are working with tert-butyl magnesium chloride, which can be written as \((\mathrm{CH}_{3})_{3} \mathrm{C}^{-}\) with the \(\mathrm{Mg}^+\) cation. This compound is a type of Grignard reagent.
2Step 2: Determine the Reaction Type
Grignard reagents react with water through a proton exchange process, where the acidic hydrogen from water replaces the magnesium chloride group. In this case, water is replaced by heavy water \(\mathrm{D}_{2} \mathrm{O}\), hence deuterium \((\mathrm{D})\) ions are exchanged instead of hydrogen \((\mathrm{H})\) ions.
3Step 3: Exchange Magnesium Chloride Group
The \(\mathrm{MgCl}\) in the Grignard reagent \((\mathrm{CH}_{3})_{3} \mathrm{CMgCl}\) is replaced by a deuterium ion \((\mathrm{D})\) from the heavy water, leading to the formation of \((\mathrm{CH}_{3})_{3} \mathrm{CD}\).
4Step 4: Write the Final Product
After the exchange, the final product of the reaction is \((\mathrm{CH}_{3})_{3} \mathrm{CD}\). This shows that the \(\mathrm{D}_{2} \mathrm{O}\) provides \(\mathrm{D}^-\) ions which bond with the carbon atom previously connected to the Grignard reagent.
Key Concepts
Tert-butyl magnesium chlorideProton exchange processHeavy water (D2O)Deuterium ion exchange
Tert-butyl magnesium chloride
Tert-butyl magnesium chloride, denoted as \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CMgCl}\), is a specific type of Grignard reagent. This compound features a carbon atom lightly bound to magnesium chloride. Grignard reagents are notable for their reactivity with various substrates, particularly in forming carbon-carbon bonds. The carbon in the group, tert-butyl, refers to a tertiary butane structure, which is connected to the magnesium chloride.
- "Tert-butyl" indicates a carbon chain where the carbon atom connected to magnesium is bound to three methyl groups (\(\mathrm{CH}_3\)).
- The magnesium atom in Grignard reagents acts as a bridge between the carbon ion and other atoms during a reaction.
Proton exchange process
The proton exchange process is central to the reaction when a Grignard reagent interacts with water. This process involves the transfer of a proton, which is essentially a hydrogen ion (\(\mathrm{H}^+\)), from water to the organic component of the Grignard reagent. This exchange converts the reagent's magnesium-bound carbon into a hydrocarbon.
Role in the Reaction
- Grignard reagents like tert-butyl magnesium chloride react swiftly because the carbon-metal bond is highly polarized.
- The negative charge on the carbon makes it keen to bind with positive ions, such as protons from water molecules.
- However, in our reaction, heavy water \(\mathrm{D}_{2}\mathrm{O}\) replaces regular water, facilitating a deuterium ion exchange instead of just proton exchange.
Heavy water (D2O)
Heavy water, with the chemical formula \(\mathrm{D}_{2}\mathrm{O}\), is a form of water where each hydrogen atom is replaced by deuterium. Deuterium, a stable isotope of hydrogen, features an additional neutron compared to regular hydrogen.This additional neutron gives deuterium greater mass and alters the bonding characteristics of heavy water.
- Heavy water reacts similarly to regular water in many chemical processes but can yield different products due to the presence of deuterium.
- In reactions, the exchange of \(\mathrm{D}^+\) ions instead of \(\mathrm{H}^+\) ions influences the properties of the end product, such as molecular weight and stability.
Deuterium ion exchange
Deuterium ion exchange is a pivotal step in the reaction when a Grignard reagent reacts with \(\mathrm{D}_{2}\mathrm{O}\). This exchange involves the replacement of \(\mathrm{MgCl}\) in the reagent with \(\mathrm{D}^-\) from heavy water, creating a deuterium-substituted hydrocarbon.
Incorporation of Deuterium
- During the reaction with tert-butyl magnesium chloride, \(\mathrm{D}^-\) ions replace the \(\mathrm{Cl}^-\) associated with magnesium. This yields \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CD}\) as the final product.
- Deuterium adds unique physical properties to the compound, including altered spectral characteristics and slight increases in stability.
- This process demonstrates how deuterium can label compounds, which is valuable for tracing chemical pathways or studying reaction mechanisms.
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