Problem 23
Question
$$\left(\frac{\sqrt{2}}{2}\right)^{10}\left[\cos \frac{10 \pi}{4}+i \sin \frac{10 \pi}{4}\right]=\frac{1}{32} i$$
Step-by-Step Solution
Verified Answer
The given expression equals \( \frac{1}{32} i \).
1Step 1: Simplify the Expression Inside the Exponent
First, let's simplify the fraction \( \frac{10\pi}{4} \). Dividing the numerator and the denominator by 2, we get \( \frac{5\pi}{2} \), which can be rewritten as \( 2\pi + \frac{\pi}{2} \). Since \( \cos(\theta) \) and \( \sin(\theta) \) are periodic with period \( 2\pi \), \[ \cos \left( \frac{5\pi}{2} \right) = \cos \left( \frac{\pi}{2} \right) = 0 \]\[ \sin \left( \frac{5\pi}{2} \right) = \sin \left( \frac{\pi}{2} \right) = 1 \]
Key Concepts
Trigonometric Form of Complex NumbersPolar CoordinatesEuler's FormulaDe Moivre's Theorem
Trigonometric Form of Complex Numbers
Complex numbers can be expressed in various ways, but one of the most valuable forms is the trigonometric form. This representation is perfect when you want to multiply, divide or find powers and roots of complex numbers easily. A complex number in trigonometric form is given by:\[ z = r (\cos \theta + i \sin \theta) \]- **\( r \)** represents the modulus or magnitude of the complex number.- **\( \theta \)** is the argument, which is the angle the complex number makes with the positive real axis in the complex plane.This form is particularly useful because of its connection to trigonometry and geometry. Knowing how to transition between the standard form, \( a + bi \), where \( a \) is the real part and \( b \) is the imaginary part, and the trigonometric form is key to tackling complex number problems efficiently.
Polar Coordinates
The concept of polar coordinates is an extension of the traditional Cartesian coordinate system, adding a new dimension of clarity to how we view complex numbers. Instead of representing a point on the plane with \( (x, y) \), polar coordinates use \( (r, \theta) \):
Using polar coordinates, complex numbers become easier to manipulate geometrically and computationally. Therefore, understanding polar coordinates offers a solid foundation for moving forward with the deeper properties of complex numbers.
- \( r \) is the distance from the origin to the point, equivalent to the modulus of a complex number.
- \( \theta \) is the angle from the positive x-axis to the line connecting the origin to the point, akin to the argument of a complex number.
Using polar coordinates, complex numbers become easier to manipulate geometrically and computationally. Therefore, understanding polar coordinates offers a solid foundation for moving forward with the deeper properties of complex numbers.
Euler's Formula
Euler's formula is a beautiful and elegant bridge between the exponential function and trigonometric functions. It states:\[ e^{i\theta} = \cos \theta + i \sin \theta \]This relation allows us to represent complex numbers in the exponential form \( z = re^{i\theta} \), which is incredibly powerful in calculations.
- It highlights the cyclical nature of the exponential function when dealing with complex exponents.
- It shows why complex numbers on a unit circle can be so easily expressed in this tidy form.
De Moivre's Theorem
De Moivre's Theorem is an excellent tool for finding powers and extracting roots of complex numbers. It can be stated as:\[ (\cos \theta + i \sin \theta)^n = \cos(n\theta) + i \sin(n\theta) \]For a complex number in trigonometric form, this theorem allows easy calculation of powers by just multiplying the argument, \( \theta \), by the power, \( n \).
This greatly simplifies many problems, including those like the original exercise where a complex number is raised to the power of 10. Simply applying De Moivre can lead directly to a solution without lengthy calculations.
This greatly simplifies many problems, including those like the original exercise where a complex number is raised to the power of 10. Simply applying De Moivre can lead directly to a solution without lengthy calculations.
- It's efficient for high powers and can be further extended for fractional powers in roots of complex numbers.
- It simplifies finding new complex numbers derived from a given one.
Other exercises in this chapter
Problem 23
Along the \(y\) -axis,\(\lim _{z \rightarrow 0} \frac{x+i y}{x-i y}=\lim _{y \rightarrow 0} \frac{i y}{-i y}=-1,\) whereas along the \(x\) -axis,\(\lim _{z \rig
View solution Problem 23
$$\ln (-5)=\log _{e} 5+i(\pi+2 n \pi)=1.16094+(\pi+2 n \pi) i$$
View solution Problem 24
Along the line \(x=1\),\(\lim _{z \rightarrow 1} \frac{x+y-1}{z-1}=\lim _{y \rightarrow 0} \frac{y}{i y}=\frac{1}{i}=-i\),whereas along the \(x\) -axis, \(\lim
View solution Problem 24
$$(2 \sqrt{2})^{4}\left[\cos \frac{8 \pi}{3}+i \sin \frac{8 \pi}{3}\right]=-32+32 \sqrt{3} i$$
View solution