Problem 23
Question
\(\int_{i}^{1+i} z e^{z} d z\)
Step-by-Step Solution
Verified Answer
The integral evaluates to \( i e^{1+i} - (i-1) e^i \).
1Step 1: Understanding the Integral
We are given the integral \( \int_{i}^{1+i} z e^{z} dz \). The limits of integration are from \( i \) to \( 1+i \), and it involves the function \( z e^{z} \). We aim to find the value of this definite integral.
2Step 2: Choosing the Integration Technique
The integral has the form \( \int z e^z \, dz \), which suggests using integration by parts. The formula for integration by parts is \( \int u \, dv = uv - \int v \, du \). We will identify parts of the integral as \( u = z \) and \( dv = e^z \, dz \).
3Step 3: Applying Integration by Parts
Using \( u = z \), the derivative is \( du = dz \). For \( dv = e^z \, dz \), the antiderivative is \( v = e^z \). Substituting into the integration by parts formula, \( \int z e^z \, dz = z e^z - \int e^z \, dz \).
4Step 4: Solving the Integral
Now, solve \( \int e^z \, dz = e^z \). Substituting back, we have \( z e^z - e^z + C \) as the indefinite integral. Therefore, \( \int z e^z \, dz = z e^z - e^z + C \).
5Step 5: Evaluating the Definite Integral
Substitute the limits of integration into the expression obtained: \( \left[ z e^z - e^z \right]_{z=i}^{z=1+i} = \left( (1+i)e^{1+i} - e^{1+i} \right) - \left( i e^i - e^i \right) \).
6Step 6: Simplifying the Expression
Calculate each term: \( (1+i)e^{1+i} - e^{1+i} \) simplifies to \( i e^{1+i} \); \( i e^i - e^i \) simplifies to \( (i-1)e^i \). Evaluate: \( i e^{1+i} - (i-1)e^i \).
7Step 7: Using Euler's Formula to Simplify Further
Apply Euler's formula \( e^{z} = e^{x+iy} = e^x (\cos y + i \sin y) \) to express these in a more familiar form for further simplification or evaluation.
8Step 8: Conclusion: Final Evaluation
After simplifying using Euler's formula and substituting back the values, the final value of the integral is calculated. The detailed calculations and simplifications will show \( i e^{1+i} - (i-1) e^i \).
Key Concepts
Integration by PartsEuler's FormulaDefinite IntegralComplex Numbers
Integration by Parts
Integration by parts is a technique commonly used in calculus to integrate the product of two functions. It is particularly useful when one function becomes simpler upon differentiation, and the other is easy to integrate.
This method is derived from the product rule of differentiation. The formula for integration by parts is:
This method is derived from the product rule of differentiation. The formula for integration by parts is:
- \[ \int u \, dv = uv - \int v \, du \]
- \( u \) is the function differentiated (e.g., \( u = z \) in our original exercise)
- \( dv \) is the part integrated (e.g., \( dv = e^z \, dz \) in our case)
Euler's Formula
Euler's formula is a foundational formula in complex analysis that connects complex numbers with trigonometry and exponential functions. It is expressed as:
For example, when integrating functions involving complex numbers, it's often helpful to break down expressions like \( e^{z} \) by writing them in terms of Euler's formula to separate real and imaginary parts. This approach makes the process of integration more straightforward, especially when evaluating definite integrals over complex paths.
- \[ e^{ix} = \cos x + i \sin x \]
For example, when integrating functions involving complex numbers, it's often helpful to break down expressions like \( e^{z} \) by writing them in terms of Euler's formula to separate real and imaginary parts. This approach makes the process of integration more straightforward, especially when evaluating definite integrals over complex paths.
Definite Integral
The concept of a definite integral is central to calculus and analysis. It calculates the accumulation of quantities, represented by the area under the curve of a function between two specified bounds.
In mathematical terms, the definite integral from \( a \) to \( b \) of a function \( f(x) \) is given by:
In the context of complex integration, like our original problem \( \int_{i}^{1+i} z e^{z} dz \), we apply the same principles but along a path in the complex plane. By evaluating the function at the boundaries \( i \) and \( 1+i \), we find the accumulated change between these points. The use of definite integrals is essential for accurate calculations in various areas such as physics, engineering, and probability.
In mathematical terms, the definite integral from \( a \) to \( b \) of a function \( f(x) \) is given by:
- \[ \int_{a}^{b} f(x) \, dx = F(b) - F(a) \]
In the context of complex integration, like our original problem \( \int_{i}^{1+i} z e^{z} dz \), we apply the same principles but along a path in the complex plane. By evaluating the function at the boundaries \( i \) and \( 1+i \), we find the accumulated change between these points. The use of definite integrals is essential for accurate calculations in various areas such as physics, engineering, and probability.
Complex Numbers
Complex numbers extend the concept of one-dimensional numbers to a two-dimensional plane by introducing the imaginary unit \( i \), where \( i^2 = -1 \). A complex number is typically represented as \( z = x + yi \), with \( x \) and \( y \) being real numbers.
These numbers are crucial in many areas of mathematics and engineering because they allow for the evaluation and solution of equations that do not have real solutions.
These numbers are crucial in many areas of mathematics and engineering because they allow for the evaluation and solution of equations that do not have real solutions.
- Each complex number can be depicted as a point or a vector in a plane, known as the complex plane.
- They are used to represent and solve problems with periodic and oscillatory phenomena, such as waves.
Other exercises in this chapter
Problem 23
Evaluate the given integral by any means. \(\oint_{C}\left(\frac{e^{z}}{z+3}-3 \bar{z}\right) d z, C\) is the unit circle \(|z|=1\)
View solution Problem 23
\(\oint_{C} \frac{e^{-2 z}}{z^{4}} d z ; C\) is the circle \(|z-1|=3\)
View solution Problem 23
\(\oint_{C}\left(\frac{e^{z}}{z+3}-3 \bar{z}\right) d z, C\) is the unit circle \(|z|=1\)
View solution Problem 24
Evaluate the given integral by any means. \(\oint_{C}\left(z^{3}+z^{2}+\operatorname{Re}(z)\right) d z, C\) is the triangle with vertices \(z=0, z=1+2 i, z=1\)
View solution