Problem 23
Question
In Problems 23-28, find the slope of the line containing the given two points. \((1,1)\) and \((2,2)\)
Step-by-Step Solution
Verified Answer
The slope of the line is 1.
1Step 1: Calculate the Change in Y
To find the slope of the line passing through the points \((1,1)\) and \((2,2)\), start by calculating the difference in the y-values of the two points. This is done by subtracting the y-coordinate of the first point from the y-coordinate of the second point, resulting in the change in y: \( \Delta y = y_2 - y_1 = 2 - 1 = 1 \).
2Step 2: Calculate the Change in X
Next, calculate the difference in the x-values of the two points. Subtract the x-coordinate of the first point from the x-coordinate of the second point to find the change in x: \( \Delta x = x_2 - x_1 = 2 - 1 = 1 \).
3Step 3: Divide the Changes to Find the Slope
The slope of a line is given by the formula \( m = \frac{\Delta y}{\Delta x} \). Substitute the changes you calculated in the previous steps: \( m = \frac{1}{1} = 1 \). This means the slope of the line is 1.
Key Concepts
Change in YChange in XLinear EquationCoordinate Geometry
Change in Y
When you want to find the slope of a line, one critical step is calculating the 'change in y'. This refers to the difference between the y-coordinates of two points on the line. Let's break it down:
1. Identify the y-coordinates of the two given points. In our example, the points are (1, 1) and (2, 2). The y-coordinates are 1 and 2.
2. Subtract the y-coordinate of the first point from the y-coordinate of the second point. This calculation gives you the change in y.
3. Formula: \[ \Delta y = y_2 - y_1 \]
In our case: \( 2 - 1 = 1 \).
By understanding this simple subtraction, you can determine how much the y-values rise or fall as you move from one point to another along the line.
1. Identify the y-coordinates of the two given points. In our example, the points are (1, 1) and (2, 2). The y-coordinates are 1 and 2.
2. Subtract the y-coordinate of the first point from the y-coordinate of the second point. This calculation gives you the change in y.
3. Formula: \[ \Delta y = y_2 - y_1 \]
In our case: \( 2 - 1 = 1 \).
By understanding this simple subtraction, you can determine how much the y-values rise or fall as you move from one point to another along the line.
Change in X
Once you have calculated the 'change in y', the next step is to find the 'change in x'. This is done similarly by calculating the difference in the x-coordinates of the two points.
1. Identify the x-coordinates of the two given points, which in our example are 1 and 2.
2. Subtract the x-coordinate of the first point from the x-coordinate of the second point.
3. Formula:\[\Delta x = x_2 - x_1\]
In our case: \( 2 - 1 = 1 \).
This process tells us how much the x-values move horizontally as we move from one point to another on the line.
1. Identify the x-coordinates of the two given points, which in our example are 1 and 2.
2. Subtract the x-coordinate of the first point from the x-coordinate of the second point.
3. Formula:\[\Delta x = x_2 - x_1\]
In our case: \( 2 - 1 = 1 \).
This process tells us how much the x-values move horizontally as we move from one point to another on the line.
Linear Equation
In coordinate geometry, a 'linear equation' represents a straight line. The slope, a key aspect of this equation, indicates the steepness of the line.
The general form of a linear equation is:\[y = mx + b\]
Here:
The general form of a linear equation is:\[y = mx + b\]
Here:
- \( m \) is the slope, showing how much y changes with a one-unit change in x.
- \( b \) is the y-intercept, where the line crosses the y-axis.
Coordinate Geometry
Coordinate geometry involves studying geometric figures using a coordinate system. It's the bridge connecting algebraic equations and geometric figures. Points are plotted using coordinates in the form \((x, y)\).
Key components include:
Key components include:
- Coordinates: Show exact position on the plane.
- Slope: Measures the angle or steepness of a line.
- Distance: The length between two points.
Other exercises in this chapter
Problem 22
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