Problem 23
Question
In Problems 23-28, find each of the given projections if \(\mathbf{u}=\mathbf{i}+2 \mathbf{j}, \mathbf{v}=2 \mathbf{i}-\mathbf{j}\), and \(\mathbf{w}=\mathbf{i}+5 \mathbf{j}\). $$ \operatorname{proj}_{\mathbf{v}} \mathbf{u} $$
Step-by-Step Solution
Verified Answer
The projection of \( \mathbf{u} \) onto \( \mathbf{v} \) is the zero vector \( \mathbf{0} \).
1Step 1: Understand the Projection Formula
To find the projection of vector \( \mathbf{u} \) onto vector \( \mathbf{v} \), we use the formula: \[ \operatorname{proj}_{\mathbf{v}} \mathbf{u} = \frac{\mathbf{u} \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}} \mathbf{v} \] where \( \mathbf{u} \cdot \mathbf{v} \) is the dot product of \( \mathbf{u} \) and \( \mathbf{v} \), and \( \mathbf{v} \cdot \mathbf{v} \) is the dot product of \( \mathbf{v} \) with itself.
2Step 2: Calculate the Dot Product \( \mathbf{u} \cdot \mathbf{v} \)
Compute the dot product of \( \mathbf{u} \) and \( \mathbf{v} \): \( \mathbf{u} = \mathbf{i} + 2\mathbf{j} \) and \( \mathbf{v} = 2\mathbf{i} - \mathbf{j} \). The dot product \( \mathbf{u} \cdot \mathbf{v} \) is calculated as: \[ (1)(2) + (2)(-1) = 2 - 2 = 0 \]
3Step 3: Calculate the Dot Product \( \mathbf{v} \cdot \mathbf{v} \)
Compute the dot product of \( \mathbf{v} \) with itself: \( \mathbf{v} = 2\mathbf{i} - \mathbf{j} \). The dot product \( \mathbf{v} \cdot \mathbf{v} \) is given by: \[ (2)(2) + (-1)(-1) = 4 + 1 = 5 \]
4Step 4: Calculate the Projection
Substitute the dot products into the projection formula: \[ \operatorname{proj}_{\mathbf{v}} \mathbf{u} = \frac{0}{5} \mathbf{v} = 0 \cdot \mathbf{v} = \mathbf{0} \] Hence, the projection of \( \mathbf{u} \) onto \( \mathbf{v} \) is the zero vector.
Key Concepts
Dot ProductProjection FormulaVectors in Mathematics
Dot Product
The dot product is a fundamental operation in vector mathematics. It combines pairs of vectors to produce a single scalar quantity. This scalar represents the product of the magnitudes of the two vectors and the cosine of the angle between them. Mathematically, the dot product of two vectors \( \mathbf{a} = a_1 \mathbf{i} + a_2 \mathbf{j} \) and \( \mathbf{b} = b_1 \mathbf{i} + b_2 \mathbf{j} \) is defined as: \[ \mathbf{a} \cdot \mathbf{b} = a_1 b_1 + a_2 b_2 \] In simple terms, each corresponding component of the vectors is multiplied and then summed up:
- \( a_1 \) is multiplied by \( b_1 \)
- \( a_2 \) is multiplied by \( b_2 \)
Projection Formula
The projection formula helps us find the shadow of one vector onto another. It is used to determine the component of one vector in the direction of another. Using the projection formula for vector \( \mathbf{u} \) onto vector \( \mathbf{v} \), we have: \[ \operatorname{proj}_{\mathbf{v}} \mathbf{u} = \frac{\mathbf{u} \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}} \mathbf{v} \] Each term plays a crucial role in calculating the projection:
- \( \mathbf{u} \cdot \mathbf{v} \): Calculates the extent to which \( \mathbf{u} \) is in the direction of \( \mathbf{v} \)
- \( \mathbf{v} \cdot \mathbf{v} \): Scales the denominator to the length of \( \mathbf{v} \)
- \( \mathbf{v} \): Determines the direction
Vectors in Mathematics
Vectors are a fundamental concept in mathematics, especially in geometry and physics. A vector is defined by its magnitude and direction and is often represented with an arrow, where the direction and length visually represent these properties. In common mathematical notation, vectors are expressed as combinations of unit vectors \( \mathbf{i}, \mathbf{j}, \mathbf{k} \): \( \mathbf{v} = v_x \mathbf{i} + v_y \mathbf{j} + v_z \mathbf{k} \). In two dimensions, vectors simplify to linear combinations of \( \mathbf{i} \) and \( \mathbf{j} \) as seen in our example vectors \( \mathbf{u} \) and \( \mathbf{v} \):
- \( \mathbf{u} = \mathbf{i} + 2 \mathbf{j} \)
- \( \mathbf{v} = 2 \mathbf{i} - \mathbf{j} \)
Other exercises in this chapter
Problem 23
Julie, flying in a wind blowing 40 miles per hour due south, discovers that she is heading due east when she points her airplane in the direction \(\mathrm{N} 6
View solution Problem 23
Sketch the curve in the xy-plane. Then, for the given point, find the curvature and the radius of curvature. Finally, \(y=\tan x,(\pi / 4,1)\)
View solution Problem 23
Find the general equation of a central ellipsoid that is symmetric with respect to the following: (a) origin (b) \(x\)-axis (c) \(x y\)-plane
View solution Problem 23
Find the symmetric equations of the tangent line to the curve with equation $$ \mathbf{r}(t)=2 \cos t \mathbf{i}+6 \sin t \mathbf{j}+t \mathbf{k} $$ at \(t=\pi
View solution