Problem 23
Question
In Exercises 23-40, solve the quadratic equation by extracting square roots. List both the exact answer and a decimal answer that has been rounded to two decimal places. $$ x^{2}=16 $$
Step-by-Step Solution
Verified Answer
The solution to the equation \(x^{2} = 16\) is \(x = \pm4\). This means x could either be 4 or -4.
1Step 1: Isolate x
The first step is to isolate x by taking the square root of both sides of the equation. The equation given is \(x^{2}=16\). So, you start by taking the square root of both sides: sqrt(x^2) = sqrt(16)
2Step 2: Simplify
After square roots are taken from both sides of the equation, you get \(x = \pm \sqrt{16}\). This \pm symbol signifies a dual positive or negative value for x.
3Step 3: Exact and decimal solutions
\(\sqrt{16}\) equals 4 as exact answer. And also, as derived in step 3, there's a negative value for x as well which is -4. These are the exact solutions. The task, however, also requires a decimal answer, which in this case don't differ from the exact solutions as both are already rounded to two decimal places.
Key Concepts
Extracting Square RootsExact SolutionsDecimal SolutionsStep-by-Step Solutions
Extracting Square Roots
The method of extracting square roots is a straightforward strategy for solving specific types of quadratic equations. When you encounter an equation in the form \(x^2 = c\), your aim is to solve for \(x\) by taking the square root of both sides.
This process helps in reducing the quadratic equation to a simpler linear equation. The crucial part is to remember that taking the square root introduces both positive and negative roots. For instance, in the equation \(x^2 = 16\), we calculate \(\sqrt{x^2} = \sqrt{16}\).
This process helps in reducing the quadratic equation to a simpler linear equation. The crucial part is to remember that taking the square root introduces both positive and negative roots. For instance, in the equation \(x^2 = 16\), we calculate \(\sqrt{x^2} = \sqrt{16}\).
- The square root of \(x^2\) simplifies to \(x\).
- The square root of 16 results in both +4 and -4.
Exact Solutions
An exact solution provides the most precise and simplified form of the answers to a quadratic equation, without any approximations. In the context of solving \(x^2 = 16\), the exact solutions involve evaluating the square root of 16.
Since the square root of 16 is straightforward, the exact solutions are \(x = 4\) and \(x = -4\).
Since the square root of 16 is straightforward, the exact solutions are \(x = 4\) and \(x = -4\).
- These solutions are exact because they are not approximated or rounded.
- They provide the true roots of the equation as integers.
Decimal Solutions
Decimal solutions are derived by rounding the exact answers to a specified number of decimal places. In some cases, particularly when dealing with non-perfect squares, the exact roots are irrational, and decimals can provide a useful approximation.
Nevertheless, in this specific exercise, both exact solutions \(x = 4\) and \(x = -4\) are already decimals at two places: 4.00 and -4.00 respectively.
Nevertheless, in this specific exercise, both exact solutions \(x = 4\) and \(x = -4\) are already decimals at two places: 4.00 and -4.00 respectively.
- It is the nature of the problem that these values do not change when converted to decimals.
- Recognizing when decimal conversion might affect precision is important.
Step-by-Step Solutions
A step-by-step solution approach helps break down the problem into manageable parts. This methodical way of solving provides clarity and ensures that nothing important is missed.
Let's look at our example:
Let's look at our example:
- **Step 1**: Start with the given quadratic equation \(x^2 = 16\). The first action is isolating x by taking the square root of both sides.
- **Step 2**: Extract the roots: you simplify to \(x = \pm \sqrt{16}\), which further simplifies to \(x = \pm 4\).
- **Step 3**: Address both the exact solutions (\(4\) and \(-4\)) and their decimal equivalents (concluding they are 4.00 and -4.00).
Other exercises in this chapter
Problem 23
Find the real solution(s) of the radical equation. Check your solutions. \(\sqrt{x-10}-4=0\)
View solution Problem 23
Use the Quadratic Formula to solve the quadratic equation. $$ 4 x^{2}+4 x=7 $$
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Your weekly paycheck is \(12 \%\) more than your coworker's. Your two paychecks total \(\$ 848\). Find the amount of each paycheck.
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Solve the equation and check your solution. (Some equations have no solution.) $$ 2(x+5)-7=3(x-2) $$
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