Problem 23
Question
In Exercises \(21-32,\) evaluate each function at the given values of the independent variable and simplify. $$g(x)=x^{2}+2 x+3$$ a. \(g(-1)\) b. \(g(x+5) \quad\) c. \(g(-x)\)
Step-by-Step Solution
Verified Answer
The values are a. \(g(-1)=2\), b. \(g(x+5) = x^{2}+12x+38\), c. \(g(-x) = x^{2}-2x+3\).
1Step 1: Evaluate g(-1)
Substitute \(x = -1\) into the equation \(g(x)=x^{2}+2x+3\). This gives \(g(-1)=(-1)^{2}+2*(-1)+3=1-2+3=2\).
2Step 2: Evaluate g(x+5)
Substitute \(x = x+5\) into the equation \(g(x)=x^{2}+2x+3\). This gives \(g(x+5)=(x+5)^{2}+2*(x+5)+3=(x^{2}+10x+25)+2x+10+3=x^{2}+12x+38\).
3Step 3: Evaluate g(-x)
Substitute \(x = -x\) into the equation \(g(x)=x^{2}+2x+3\). This gives \(g(-x)=(-x)^{2}+2*(-x)+3=x^{2}-2x+3\).
Key Concepts
Independent VariableFunction SimplificationPolynomial Functions
Independent Variable
In mathematics, especially when dealing with functions, an independent variable is the input of the function. For the function described as \( g(x) = x^2 + 2x + 3 \), the independent variable is \(x\). It simply acts as a placeholder or a symbol representing the input value. When evaluating a function at specific points, you substitute these points into the equation wherever the independent variable appears.
- For example, in part (a), substituting \(x = -1\) leads to \(g(-1) = 1 - 2 + 3 = 2\).
- In part (b), substituting \(x = x + 5\) generalizes the input, making the function \(g(x+5) = x^2 + 12x + 38\).
- Similarly, evaluating \(g(-x)\) in part (c) changes the input to its negative counterpart, resulting in \(x^2 - 2x + 3\).
Function Simplification
Simplifying a function involves reducing the expression to its most basic form without changing its value or outcome. The goal is to make the function more manageable and easier to work with while maintaining its integrity.
To simplify correctly, you must follow basic algebraic rules like combining like terms and applying distributive properties. Take, for instance, the simplification of \(g(x+5)\):
- First, expand \((x+5)^2\) which results in \(x^2 + 10x + 25\).
- Next, distribute the input \(2(x + 5)\) to get \(2x + 10\).
- Combine these with the constant \(+3\) to finally yield \(x^2 + 12x + 38\).
By understanding each step and the algebra involved, simplifying functions can become a smoother, more logical process. These fundamentals are often applied when processing more complex mathematical models and systems.
To simplify correctly, you must follow basic algebraic rules like combining like terms and applying distributive properties. Take, for instance, the simplification of \(g(x+5)\):
- First, expand \((x+5)^2\) which results in \(x^2 + 10x + 25\).
- Next, distribute the input \(2(x + 5)\) to get \(2x + 10\).
- Combine these with the constant \(+3\) to finally yield \(x^2 + 12x + 38\).
By understanding each step and the algebra involved, simplifying functions can become a smoother, more logical process. These fundamentals are often applied when processing more complex mathematical models and systems.
Polynomial Functions
Polynomial functions are a cornerstone of algebra, relating to equations that are expressed as a sum of terms including the independent variable raised to various powers. The function \(g(x) = x^2 + 2x + 3\) is a quadratic polynomial, meaning it is a second-degree polynomial function.
- The degree of this polynomial is 2, as indicated by the highest power of \(x\).
- All polynomial functions are continuous and smooth, meaning they have no breaks or sharp corners on their graphs.
- They can be classified by their degree: linear, quadratic, cubic, quartic, and so forth.
Other exercises in this chapter
Problem 23
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Slope \(=-\frac{2}{3},\) passing through \((6,-2)\)
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Find: a. \((f \circ g)(x)\) b. \(\left(g^{\circ} f\right)(x)\) c. \((f \circ g)(2)\) $$f(x)=x^{2}+2, g(x)=x^{2}-2$$
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Find the midpoint of each line segment with the given endpoints. $$ (-3,-4) \text { and }(6,-8) $$
View solution Problem 24
Begin by graphing the absolute value function, \(f(x)=|x| .\) Then use transformations of this graph to graph the given function. $$ g(x)=|x|+3 $$
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