Problem 23
Question
In Exercises \(21-30\), find the exact polar coordinates of the points of intersection of graphs of the polar equations. Remember to check for intersection at the pole (origin). $$ r=1-2 \sin (\theta) \text { and } r=2 $$
Step-by-Step Solution
Verified Answer
The polar coordinates of the intersection points are \((2, \frac{7\pi}{6})\) and \((2, \frac{11\pi}{6})\).
1Step 1: Set the Equations Equal
We begin by setting the two equations equal to solve for \( \theta \). This will help us find the points of intersection. The equations are \( r = 1 - 2\sin(\theta) \) and \( r = 2 \). Setting them equal gives: \[ 1 - 2\sin(\theta) = 2 \]
2Step 2: Solve for \( \sin(\theta) \)
Solve the equation \( 1 - 2\sin(\theta) = 2 \) for \( \sin(\theta) \):\[ 1 - 2\sin(\theta) = 2 \]Subtract 1 from both sides:\[ -2\sin(\theta) = 1 \]Divide both sides by -2:\[ \sin(\theta) = -\frac{1}{2} \]
3Step 3: Find \( \theta \) Values
The values of \( \theta \) where \( \sin(\theta) = -\frac{1}{2} \) are:- \( \theta = \frac{7\pi}{6} \)- \( \theta = \frac{11\pi}{6} \)These values are found using the unit circle.
4Step 4: Check Intersection at the Pole
To check if the graphs intersect at the pole, set \( r = 0 \) and find \( \theta \) for the first equation:\[ 0 = 1 - 2\sin(\theta) \]Solving gives \( \sin(\theta) = \frac{1}{2} \), which has solutions \( \theta = \frac{\pi}{6}, \frac{5\pi}{6} \). However, these do not satisfy \( r = 2 \) in the second equation.
5Step 5: Determine Exact Polar Coordinates
From steps 1 to 4, we determine that the points of intersection occur at \( \theta = \frac{7\pi}{6} \) and \( \theta = \frac{11\pi}{6} \). For both points of intersection, since \( r \) must be 2 in the second equation, the corresponding polar coordinates are:1. \( (2, \frac{7\pi}{6}) \) 2. \( (2, \frac{11\pi}{6}) \)
Key Concepts
Intersection of GraphsPolar EquationsUnit Circle
Intersection of Graphs
When working with polar graphs, the intersection points represent where the two curves meet. To find the intersection points, we set the equations equal to each other. This allows us to find the common values of \(\theta\), as shown in the original exercise.
- Start by equating the two polar equations, such as \(r=1-2 \ \sin(\theta)\) and \(r=2\).
- Solve for \(\theta\) to find where the intersection occurs.
- Check each obtained solution by substituting back to confirm that the intersection indeed exists on both graphs.
Polar Equations
Polar equations represent curves based on distance \(r\) from the origin and angle \(\theta\) relative to the positive x-axis. They offer an alternative method to describe shapes and paths, especially appealing in circular or rotational dynamics.
- In contrast to Cartesian coordinates, polar coordinates detail the point's location through angle and radius.
- Equations like \(r = 1 - 2\sin(\theta)\) represent complex curves, often forming loops or rotational shapes.
- The variable \(r\) in polar equations gives the radius, determining the distance from the center or pole.
Unit Circle
The unit circle is a fundamental concept in trigonometry. It simplifies finding angles and their trigonometric functions, such as sine and cosine, which are crucial for understanding polar coordinates.
- It's a circle with a radius of 1, centered at the origin of a coordinate plane.
- In the unit circle, the angle \(\theta\) is measured counterclockwise from the positive x-axis.
- The coordinates of a point on this circle are \( (\cos(\theta), \sin(\theta))\), which correspond to the x and y projections.
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